Integrand size = 16, antiderivative size = 28 \[ \int \frac {1}{4} \left (45-86 x+6 x^2\right ) \log (3) \, dx=\left (x+(1-x) \left (x+\frac {1}{4} x (1+3 (12-x)+x)\right )\right ) \log (3) \]
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Time = 0.00 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {12} \[ \int \frac {1}{4} \left (45-86 x+6 x^2\right ) \log (3) \, dx=\frac {1}{2} x^3 \log (3)-\frac {43}{4} x^2 \log (3)+\frac {45}{4} x \log (3) \]
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Rule 12
Rubi steps \begin{align*} \text {integral}& = \frac {1}{4} \log (3) \int \left (45-86 x+6 x^2\right ) \, dx \\ & = \frac {45}{4} x \log (3)-\frac {43}{4} x^2 \log (3)+\frac {1}{2} x^3 \log (3) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.71 \[ \int \frac {1}{4} \left (45-86 x+6 x^2\right ) \log (3) \, dx=\frac {1}{4} \left (45 x-43 x^2+2 x^3\right ) \log (3) \]
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Time = 0.04 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.57
method | result | size |
gosper | \(\frac {x \left (2 x^{2}-43 x +45\right ) \ln \left (3\right )}{4}\) | \(16\) |
default | \(\frac {\left (2 x^{3}-43 x^{2}+45 x \right ) \ln \left (3\right )}{4}\) | \(19\) |
parallelrisch | \(\frac {\left (2 x^{3}-43 x^{2}+45 x \right ) \ln \left (3\right )}{4}\) | \(19\) |
norman | \(\frac {45 x \ln \left (3\right )}{4}-\frac {43 x^{2} \ln \left (3\right )}{4}+\frac {x^{3} \ln \left (3\right )}{2}\) | \(21\) |
risch | \(\frac {45 x \ln \left (3\right )}{4}-\frac {43 x^{2} \ln \left (3\right )}{4}+\frac {x^{3} \ln \left (3\right )}{2}\) | \(21\) |
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none
Time = 0.23 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.64 \[ \int \frac {1}{4} \left (45-86 x+6 x^2\right ) \log (3) \, dx=\frac {1}{4} \, {\left (2 \, x^{3} - 43 \, x^{2} + 45 \, x\right )} \log \left (3\right ) \]
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Time = 0.02 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93 \[ \int \frac {1}{4} \left (45-86 x+6 x^2\right ) \log (3) \, dx=\frac {x^{3} \log {\left (3 \right )}}{2} - \frac {43 x^{2} \log {\left (3 \right )}}{4} + \frac {45 x \log {\left (3 \right )}}{4} \]
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none
Time = 0.19 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.64 \[ \int \frac {1}{4} \left (45-86 x+6 x^2\right ) \log (3) \, dx=\frac {1}{4} \, {\left (2 \, x^{3} - 43 \, x^{2} + 45 \, x\right )} \log \left (3\right ) \]
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Time = 0.25 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.64 \[ \int \frac {1}{4} \left (45-86 x+6 x^2\right ) \log (3) \, dx=\frac {1}{4} \, {\left (2 \, x^{3} - 43 \, x^{2} + 45 \, x\right )} \log \left (3\right ) \]
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Time = 0.04 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.54 \[ \int \frac {1}{4} \left (45-86 x+6 x^2\right ) \log (3) \, dx=\frac {x\,\ln \left (3\right )\,\left (2\,x^2-43\,x+45\right )}{4} \]
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