Integrand size = 291, antiderivative size = 31 \[ \int \frac {e^x \left (3 x^2-6 x^3+3 x^4+\left (9 x-3 x^2-6 x^3\right ) \log (2)+\left (-12+9 x+3 x^2\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )+\log ^{\frac {x}{3}}\left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \left (-x^5+\left (-5 x^3+2 x^4\right ) \log (2)-x^3 \log ^2(2)+\left (x^4-x^5+\left (3 x^3+2 x^4\right ) \log (2)+\left (-4 x^2-x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{\left (-3 x^4+3 x^5+\left (-9 x^3-6 x^4\right ) \log (2)+\left (12 x^2+3 x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )} \, dx=\frac {e^x}{x}-\log ^{\frac {x}{3}}\left (4+x-\frac {5 x}{x-\log (2)}\right ) \]
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\[ \int \frac {e^x \left (3 x^2-6 x^3+3 x^4+\left (9 x-3 x^2-6 x^3\right ) \log (2)+\left (-12+9 x+3 x^2\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )+\log ^{\frac {x}{3}}\left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \left (-x^5+\left (-5 x^3+2 x^4\right ) \log (2)-x^3 \log ^2(2)+\left (x^4-x^5+\left (3 x^3+2 x^4\right ) \log (2)+\left (-4 x^2-x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{\left (-3 x^4+3 x^5+\left (-9 x^3-6 x^4\right ) \log (2)+\left (12 x^2+3 x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )} \, dx=\int \frac {e^x \left (3 x^2-6 x^3+3 x^4+\left (9 x-3 x^2-6 x^3\right ) \log (2)+\left (-12+9 x+3 x^2\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )+\log ^{\frac {x}{3}}\left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \left (-x^5+\left (-5 x^3+2 x^4\right ) \log (2)-x^3 \log ^2(2)+\left (x^4-x^5+\left (3 x^3+2 x^4\right ) \log (2)+\left (-4 x^2-x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{\left (-3 x^4+3 x^5+\left (-9 x^3-6 x^4\right ) \log (2)+\left (12 x^2+3 x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {e^x (-1+x)}{x^2}+\frac {\log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \left (-x^3+x (-5+2 x) \log (2)-x \log ^2(2)-\left (x^3+x (-3+\log (2)) \log (2)+4 \log ^2(2)-x^2 (1+\log (4))\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{3 \left (x^3-x (3-\log (2)) \log (2)+4 \log ^2(2)-x^2 (1+\log (4))\right )}\right ) \, dx \\ & = \frac {1}{3} \int \frac {\log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \left (-x^3+x (-5+2 x) \log (2)-x \log ^2(2)-\left (x^3+x (-3+\log (2)) \log (2)+4 \log ^2(2)-x^2 (1+\log (4))\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{x^3-x (3-\log (2)) \log (2)+4 \log ^2(2)-x^2 (1+\log (4))} \, dx+\int \frac {e^x (-1+x)}{x^2} \, dx \\ & = \frac {e^x}{x}+\frac {1}{3} \int \left (\frac {x \left (-x^2-\log ^2(2)+x \log (4)-\log (32)\right ) \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )}{x^3-x (3-\log (2)) \log (2)+4 \log ^2(2)-x^2 (1+\log (4))}-\log ^{\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )\right )\right ) \, dx \\ & = \frac {e^x}{x}+\frac {1}{3} \int \frac {x \left (-x^2-\log ^2(2)+x \log (4)-\log (32)\right ) \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )}{x^3-x (3-\log (2)) \log (2)+4 \log ^2(2)-x^2 (1+\log (4))} \, dx-\frac {1}{3} \int \log ^{\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )\right ) \, dx \\ & = \frac {e^x}{x}+\frac {1}{3} \int \left (-\log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )+\frac {\left (-x^2-8 x \log (2)+4 \log ^2(2)\right ) \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )}{x^3-x (3-\log (2)) \log (2)+4 \log ^2(2)-x^2 (1+\log (4))}\right ) \, dx-\frac {1}{3} \int \log ^{\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )\right ) \, dx \\ & = \frac {e^x}{x}-\frac {1}{3} \int \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \, dx+\frac {1}{3} \int \frac {\left (-x^2-8 x \log (2)+4 \log ^2(2)\right ) \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )}{x^3-x (3-\log (2)) \log (2)+4 \log ^2(2)-x^2 (1+\log (4))} \, dx-\frac {1}{3} \int \log ^{\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )\right ) \, dx \\ & = \frac {e^x}{x}-\frac {1}{3} \int \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \, dx+\frac {1}{3} \int \left (\frac {4 \log ^2(2) \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )}{x^3-x (3-\log (2)) \log (2)+4 \log ^2(2)-x^2 (1+\log (4))}+\frac {x^2 \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )}{-x^3+x (3-\log (2)) \log (2)-4 \log ^2(2)+x^2 (1+\log (4))}+\frac {8 x \log (2) \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )}{-x^3+x (3-\log (2)) \log (2)-4 \log ^2(2)+x^2 (1+\log (4))}\right ) \, dx-\frac {1}{3} \int \log ^{\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )\right ) \, dx \\ & = \frac {e^x}{x}-\frac {1}{3} \int \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \, dx+\frac {1}{3} \int \frac {x^2 \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )}{-x^3+x (3-\log (2)) \log (2)-4 \log ^2(2)+x^2 (1+\log (4))} \, dx-\frac {1}{3} \int \log ^{\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )\right ) \, dx+\frac {1}{3} (8 \log (2)) \int \frac {x \log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )}{-x^3+x (3-\log (2)) \log (2)-4 \log ^2(2)+x^2 (1+\log (4))} \, dx+\frac {1}{3} \left (4 \log ^2(2)\right ) \int \frac {\log ^{-1+\frac {x}{3}}\left (\frac {-x^2+x (1+\log (2))+\log (16)}{-x+\log (2)}\right )}{x^3-x (3-\log (2)) \log (2)+4 \log ^2(2)-x^2 (1+\log (4))} \, dx \\ \end{align*}
Timed out. \[ \int \frac {e^x \left (3 x^2-6 x^3+3 x^4+\left (9 x-3 x^2-6 x^3\right ) \log (2)+\left (-12+9 x+3 x^2\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )+\log ^{\frac {x}{3}}\left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \left (-x^5+\left (-5 x^3+2 x^4\right ) \log (2)-x^3 \log ^2(2)+\left (x^4-x^5+\left (3 x^3+2 x^4\right ) \log (2)+\left (-4 x^2-x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{\left (-3 x^4+3 x^5+\left (-9 x^3-6 x^4\right ) \log (2)+\left (12 x^2+3 x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )} \, dx=\text {\$Aborted} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 0.27 (sec) , antiderivative size = 152, normalized size of antiderivative = 4.90
\[\frac {{\mathrm e}^{x}}{x}-{\left (-\ln \left (\ln \left (2\right )-x \right )+\ln \left (\left (4+x \right ) \ln \left (2\right )-x^{2}+x \right )-\frac {i \pi \,\operatorname {csgn}\left (\frac {i \left (\left (4+x \right ) \ln \left (2\right )-x^{2}+x \right )}{\ln \left (2\right )-x}\right ) \left (-\operatorname {csgn}\left (\frac {i \left (\left (4+x \right ) \ln \left (2\right )-x^{2}+x \right )}{\ln \left (2\right )-x}\right )+\operatorname {csgn}\left (\frac {i}{\ln \left (2\right )-x}\right )\right ) \left (-\operatorname {csgn}\left (\frac {i \left (\left (4+x \right ) \ln \left (2\right )-x^{2}+x \right )}{\ln \left (2\right )-x}\right )+\operatorname {csgn}\left (i \left (\left (4+x \right ) \ln \left (2\right )-x^{2}+x \right )\right )\right )}{2}\right )}^{\frac {x}{3}}\]
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Time = 0.26 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.29 \[ \int \frac {e^x \left (3 x^2-6 x^3+3 x^4+\left (9 x-3 x^2-6 x^3\right ) \log (2)+\left (-12+9 x+3 x^2\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )+\log ^{\frac {x}{3}}\left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \left (-x^5+\left (-5 x^3+2 x^4\right ) \log (2)-x^3 \log ^2(2)+\left (x^4-x^5+\left (3 x^3+2 x^4\right ) \log (2)+\left (-4 x^2-x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{\left (-3 x^4+3 x^5+\left (-9 x^3-6 x^4\right ) \log (2)+\left (12 x^2+3 x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )} \, dx=-\frac {x \log \left (\frac {x^{2} - {\left (x + 4\right )} \log \left (2\right ) - x}{x - \log \left (2\right )}\right )^{\frac {1}{3} \, x} - e^{x}}{x} \]
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Timed out. \[ \int \frac {e^x \left (3 x^2-6 x^3+3 x^4+\left (9 x-3 x^2-6 x^3\right ) \log (2)+\left (-12+9 x+3 x^2\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )+\log ^{\frac {x}{3}}\left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \left (-x^5+\left (-5 x^3+2 x^4\right ) \log (2)-x^3 \log ^2(2)+\left (x^4-x^5+\left (3 x^3+2 x^4\right ) \log (2)+\left (-4 x^2-x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{\left (-3 x^4+3 x^5+\left (-9 x^3-6 x^4\right ) \log (2)+\left (12 x^2+3 x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )} \, dx=\text {Timed out} \]
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Time = 0.39 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.35 \[ \int \frac {e^x \left (3 x^2-6 x^3+3 x^4+\left (9 x-3 x^2-6 x^3\right ) \log (2)+\left (-12+9 x+3 x^2\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )+\log ^{\frac {x}{3}}\left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \left (-x^5+\left (-5 x^3+2 x^4\right ) \log (2)-x^3 \log ^2(2)+\left (x^4-x^5+\left (3 x^3+2 x^4\right ) \log (2)+\left (-4 x^2-x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{\left (-3 x^4+3 x^5+\left (-9 x^3-6 x^4\right ) \log (2)+\left (12 x^2+3 x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )} \, dx=-\frac {x {\left (\log \left (x^{2} - x {\left (\log \left (2\right ) + 1\right )} - 4 \, \log \left (2\right )\right ) - \log \left (x - \log \left (2\right )\right )\right )}^{\frac {1}{3} \, x} - e^{x}}{x} \]
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\[ \int \frac {e^x \left (3 x^2-6 x^3+3 x^4+\left (9 x-3 x^2-6 x^3\right ) \log (2)+\left (-12+9 x+3 x^2\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )+\log ^{\frac {x}{3}}\left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \left (-x^5+\left (-5 x^3+2 x^4\right ) \log (2)-x^3 \log ^2(2)+\left (x^4-x^5+\left (3 x^3+2 x^4\right ) \log (2)+\left (-4 x^2-x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{\left (-3 x^4+3 x^5+\left (-9 x^3-6 x^4\right ) \log (2)+\left (12 x^2+3 x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )} \, dx=\int { \frac {3 \, {\left (x^{4} - 2 \, x^{3} + {\left (x^{2} + 3 \, x - 4\right )} \log \left (2\right )^{2} + x^{2} - {\left (2 \, x^{3} + x^{2} - 3 \, x\right )} \log \left (2\right )\right )} e^{x} \log \left (\frac {x^{2} - {\left (x + 4\right )} \log \left (2\right ) - x}{x - \log \left (2\right )}\right ) - {\left (x^{5} + x^{3} \log \left (2\right )^{2} + {\left (x^{5} - x^{4} + {\left (x^{3} + 4 \, x^{2}\right )} \log \left (2\right )^{2} - {\left (2 \, x^{4} + 3 \, x^{3}\right )} \log \left (2\right )\right )} \log \left (\frac {x^{2} - {\left (x + 4\right )} \log \left (2\right ) - x}{x - \log \left (2\right )}\right ) \log \left (\log \left (\frac {x^{2} - {\left (x + 4\right )} \log \left (2\right ) - x}{x - \log \left (2\right )}\right )\right ) - {\left (2 \, x^{4} - 5 \, x^{3}\right )} \log \left (2\right )\right )} \log \left (\frac {x^{2} - {\left (x + 4\right )} \log \left (2\right ) - x}{x - \log \left (2\right )}\right )^{\frac {1}{3} \, x}}{3 \, {\left (x^{5} - x^{4} + {\left (x^{3} + 4 \, x^{2}\right )} \log \left (2\right )^{2} - {\left (2 \, x^{4} + 3 \, x^{3}\right )} \log \left (2\right )\right )} \log \left (\frac {x^{2} - {\left (x + 4\right )} \log \left (2\right ) - x}{x - \log \left (2\right )}\right )} \,d x } \]
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Time = 10.02 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.29 \[ \int \frac {e^x \left (3 x^2-6 x^3+3 x^4+\left (9 x-3 x^2-6 x^3\right ) \log (2)+\left (-12+9 x+3 x^2\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )+\log ^{\frac {x}{3}}\left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \left (-x^5+\left (-5 x^3+2 x^4\right ) \log (2)-x^3 \log ^2(2)+\left (x^4-x^5+\left (3 x^3+2 x^4\right ) \log (2)+\left (-4 x^2-x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right ) \log \left (\log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )\right )\right )}{\left (-3 x^4+3 x^5+\left (-9 x^3-6 x^4\right ) \log (2)+\left (12 x^2+3 x^3\right ) \log ^2(2)\right ) \log \left (\frac {x-x^2+(4+x) \log (2)}{-x+\log (2)}\right )} \, dx=\frac {{\mathrm {e}}^x}{x}-{\mathrm {e}}^{\frac {x\,\ln \left (\ln \left (-\frac {x+4\,\ln \left (2\right )+x\,\ln \left (2\right )-x^2}{x-\ln \left (2\right )}\right )\right )}{3}} \]
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