Integrand size = 60, antiderivative size = 17 \[ \int \frac {-x+(10+x) \log (10+x)+\left (20 x+2 x^2+100 x^4+10 x^5+80 x^7+8 x^8\right ) \log ^2(10+x)}{(10+x) \log ^2(10+x)} \, dx=1+\left (x+x^4\right )^2+\frac {x}{\log (10+x)} \]
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Time = 0.12 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.76, number of steps used = 13, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {6820, 14, 2458, 2395, 2334, 2335, 2339, 30, 2436} \[ \int \frac {-x+(10+x) \log (10+x)+\left (20 x+2 x^2+100 x^4+10 x^5+80 x^7+8 x^8\right ) \log ^2(10+x)}{(10+x) \log ^2(10+x)} \, dx=x^8+2 x^5+x^2+\frac {x+10}{\log (x+10)}-\frac {10}{\log (x+10)} \]
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Rule 14
Rule 30
Rule 2334
Rule 2335
Rule 2339
Rule 2395
Rule 2436
Rule 2458
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \int \left (2 x \left (1+5 x^3+4 x^6\right )-\frac {x}{(10+x) \log ^2(10+x)}+\frac {1}{\log (10+x)}\right ) \, dx \\ & = 2 \int x \left (1+5 x^3+4 x^6\right ) \, dx-\int \frac {x}{(10+x) \log ^2(10+x)} \, dx+\int \frac {1}{\log (10+x)} \, dx \\ & = 2 \int \left (x+5 x^4+4 x^7\right ) \, dx-\text {Subst}\left (\int \frac {-10+x}{x \log ^2(x)} \, dx,x,10+x\right )+\text {Subst}\left (\int \frac {1}{\log (x)} \, dx,x,10+x\right ) \\ & = x^2+2 x^5+x^8+\operatorname {LogIntegral}(10+x)-\text {Subst}\left (\int \left (\frac {1}{\log ^2(x)}-\frac {10}{x \log ^2(x)}\right ) \, dx,x,10+x\right ) \\ & = x^2+2 x^5+x^8+\operatorname {LogIntegral}(10+x)+10 \text {Subst}\left (\int \frac {1}{x \log ^2(x)} \, dx,x,10+x\right )-\text {Subst}\left (\int \frac {1}{\log ^2(x)} \, dx,x,10+x\right ) \\ & = x^2+2 x^5+x^8+\frac {10+x}{\log (10+x)}+\operatorname {LogIntegral}(10+x)+10 \text {Subst}\left (\int \frac {1}{x^2} \, dx,x,\log (10+x)\right )-\text {Subst}\left (\int \frac {1}{\log (x)} \, dx,x,10+x\right ) \\ & = x^2+2 x^5+x^8-\frac {10}{\log (10+x)}+\frac {10+x}{\log (10+x)} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.18 \[ \int \frac {-x+(10+x) \log (10+x)+\left (20 x+2 x^2+100 x^4+10 x^5+80 x^7+8 x^8\right ) \log ^2(10+x)}{(10+x) \log ^2(10+x)} \, dx=x^2+2 x^5+x^8+\frac {x}{\log (10+x)} \]
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Time = 0.28 (sec) , antiderivative size = 21, normalized size of antiderivative = 1.24
method | result | size |
risch | \(x^{8}+2 x^{5}+x^{2}+\frac {x}{\ln \left (x +10\right )}\) | \(21\) |
parts | \(x^{8}+2 x^{5}+x^{2}+\frac {x +10}{\ln \left (x +10\right )}-\frac {10}{\ln \left (x +10\right )}\) | \(31\) |
parallelrisch | \(-\frac {-20 \ln \left (x +10\right ) x^{8}-40 x^{5} \ln \left (x +10\right )-20 \ln \left (x +10\right ) x^{2}-20 x}{20 \ln \left (x +10\right )}\) | \(40\) |
derivativedivides | \(\left (x +10\right )^{8}-80 \left (x +10\right )^{7}+2800 \left (x +10\right )^{6}-55998 \left (x +10\right )^{5}+699900 \left (x +10\right )^{4}-5598000 \left (x +10\right )^{3}+27980001 \left (x +10\right )^{2}-79900020 x -799000200+\frac {x +10}{\ln \left (x +10\right )}-\frac {10}{\ln \left (x +10\right )}\) | \(71\) |
default | \(\left (x +10\right )^{8}-80 \left (x +10\right )^{7}+2800 \left (x +10\right )^{6}-55998 \left (x +10\right )^{5}+699900 \left (x +10\right )^{4}-5598000 \left (x +10\right )^{3}+27980001 \left (x +10\right )^{2}-79900020 x -799000200+\frac {x +10}{\ln \left (x +10\right )}-\frac {10}{\ln \left (x +10\right )}\) | \(71\) |
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Time = 0.25 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.53 \[ \int \frac {-x+(10+x) \log (10+x)+\left (20 x+2 x^2+100 x^4+10 x^5+80 x^7+8 x^8\right ) \log ^2(10+x)}{(10+x) \log ^2(10+x)} \, dx=\frac {{\left (x^{8} + 2 \, x^{5} + x^{2}\right )} \log \left (x + 10\right ) + x}{\log \left (x + 10\right )} \]
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Time = 0.06 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00 \[ \int \frac {-x+(10+x) \log (10+x)+\left (20 x+2 x^2+100 x^4+10 x^5+80 x^7+8 x^8\right ) \log ^2(10+x)}{(10+x) \log ^2(10+x)} \, dx=x^{8} + 2 x^{5} + x^{2} + \frac {x}{\log {\left (x + 10 \right )}} \]
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Time = 0.23 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.53 \[ \int \frac {-x+(10+x) \log (10+x)+\left (20 x+2 x^2+100 x^4+10 x^5+80 x^7+8 x^8\right ) \log ^2(10+x)}{(10+x) \log ^2(10+x)} \, dx=\frac {{\left (x^{8} + 2 \, x^{5} + x^{2}\right )} \log \left (x + 10\right ) + x}{\log \left (x + 10\right )} \]
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Time = 0.27 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.18 \[ \int \frac {-x+(10+x) \log (10+x)+\left (20 x+2 x^2+100 x^4+10 x^5+80 x^7+8 x^8\right ) \log ^2(10+x)}{(10+x) \log ^2(10+x)} \, dx=x^{8} + 2 \, x^{5} + x^{2} + \frac {x}{\log \left (x + 10\right )} \]
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Time = 9.08 (sec) , antiderivative size = 20, normalized size of antiderivative = 1.18 \[ \int \frac {-x+(10+x) \log (10+x)+\left (20 x+2 x^2+100 x^4+10 x^5+80 x^7+8 x^8\right ) \log ^2(10+x)}{(10+x) \log ^2(10+x)} \, dx=\frac {x}{\ln \left (x+10\right )}+x^2+2\,x^5+x^8 \]
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