Integrand size = 56, antiderivative size = 22 \[ \int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{81 (-7+x)} \, dx=\frac {1}{81} e^{-2 x} x \left (x+4 \log ^2(7-x)\right ) \]
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\[ \int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{81 (-7+x)} \, dx=\int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{81 (-7+x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {1}{81} \int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{-7+x} \, dx \\ & = \frac {1}{81} \int \left (-2 e^{-2 x} (-1+x) x+\frac {8 e^{-2 x} x \log (7-x)}{-7+x}-4 e^{-2 x} (-1+2 x) \log ^2(7-x)\right ) \, dx \\ & = -\left (\frac {2}{81} \int e^{-2 x} (-1+x) x \, dx\right )-\frac {4}{81} \int e^{-2 x} (-1+2 x) \log ^2(7-x) \, dx+\frac {8}{81} \int \frac {e^{-2 x} x \log (7-x)}{-7+x} \, dx \\ & = -\frac {4}{81} e^{-2 x} \log (7-x)+\frac {56 \operatorname {ExpIntegralEi}(2 (7-x)) \log (7-x)}{81 e^{14}}-\frac {2}{81} \int \left (-e^{-2 x} x+e^{-2 x} x^2\right ) \, dx-\frac {4}{81} \int \left (13 e^{-2 x} \log ^2(7-x)-2 e^{-2 x} (7-x) \log ^2(7-x)\right ) \, dx-\frac {8}{81} \int \frac {e^{-2 x}-\frac {14 \operatorname {ExpIntegralEi}(14-2 x)}{e^{14}}}{14-2 x} \, dx \\ & = -\frac {4}{81} e^{-2 x} \log (7-x)+\frac {56 \operatorname {ExpIntegralEi}(2 (7-x)) \log (7-x)}{81 e^{14}}+\frac {2}{81} \int e^{-2 x} x \, dx-\frac {2}{81} \int e^{-2 x} x^2 \, dx-\frac {8}{81} \int \left (-\frac {e^{-2 x}}{2 (-7+x)}+\frac {7 \operatorname {ExpIntegralEi}(14-2 x)}{e^{14} (-7+x)}\right ) \, dx+\frac {8}{81} \int e^{-2 x} (7-x) \log ^2(7-x) \, dx-\frac {52}{81} \int e^{-2 x} \log ^2(7-x) \, dx \\ & = -\frac {1}{81} e^{-2 x} x+\frac {1}{81} e^{-2 x} x^2-\frac {4}{81} e^{-2 x} \log (7-x)+\frac {56 \operatorname {ExpIntegralEi}(2 (7-x)) \log (7-x)}{81 e^{14}}+\frac {1}{81} \int e^{-2 x} \, dx-\frac {2}{81} \int e^{-2 x} x \, dx+\frac {4}{81} \int \frac {e^{-2 x}}{-7+x} \, dx+\frac {8}{81} \int e^{-2 x} (7-x) \log ^2(7-x) \, dx-\frac {52}{81} \int e^{-2 x} \log ^2(7-x) \, dx-\frac {56 \int \frac {\operatorname {ExpIntegralEi}(14-2 x)}{-7+x} \, dx}{81 e^{14}} \\ & = -\frac {1}{162} e^{-2 x}+\frac {1}{81} e^{-2 x} x^2+\frac {4 \operatorname {ExpIntegralEi}(2 (7-x))}{81 e^{14}}-\frac {4}{81} e^{-2 x} \log (7-x)+\frac {56 \operatorname {ExpIntegralEi}(2 (7-x)) \log (7-x)}{81 e^{14}}-\frac {1}{81} \int e^{-2 x} \, dx+\frac {8}{81} \int e^{-2 x} (7-x) \log ^2(7-x) \, dx-\frac {52}{81} \int e^{-2 x} \log ^2(7-x) \, dx-\frac {56 \int \frac {\operatorname {ExpIntegralEi}(14-2 x)}{-7+x} \, dx}{81 e^{14}} \\ & = \frac {1}{81} e^{-2 x} x^2+\frac {4 \operatorname {ExpIntegralEi}(2 (7-x))}{81 e^{14}}-\frac {4}{81} e^{-2 x} \log (7-x)+\frac {56 \operatorname {ExpIntegralEi}(2 (7-x)) \log (7-x)}{81 e^{14}}+\frac {8}{81} \int e^{-2 x} (7-x) \log ^2(7-x) \, dx-\frac {52}{81} \int e^{-2 x} \log ^2(7-x) \, dx-\frac {56 \int \frac {\operatorname {ExpIntegralEi}(14-2 x)}{-7+x} \, dx}{81 e^{14}} \\ \end{align*}
\[ \int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{81 (-7+x)} \, dx=\int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{81 (-7+x)} \, dx \]
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Time = 0.06 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.18
method | result | size |
risch | \(\frac {4 x \,{\mathrm e}^{-2 x} \ln \left (-x +7\right )^{2}}{81}+\frac {x^{2} {\mathrm e}^{-2 x}}{81}\) | \(26\) |
parallelrisch | \(-\frac {\left (-56 \ln \left (-x +7\right )^{2} x -14 x^{2}\right ) {\mathrm e}^{-2 x}}{1134}\) | \(29\) |
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Time = 0.24 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.55 \[ \int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{81 (-7+x)} \, dx=4 \, x e^{\left (-2 \, x - 4 \, \log \left (3\right )\right )} \log \left (-x + 7\right )^{2} + x^{2} e^{\left (-2 \, x - 4 \, \log \left (3\right )\right )} \]
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Time = 0.16 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86 \[ \int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{81 (-7+x)} \, dx=\frac {\left (x^{2} + 4 x \log {\left (7 - x \right )}^{2}\right ) e^{- 2 x}}{81} \]
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Time = 0.25 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.14 \[ \int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{81 (-7+x)} \, dx=\frac {4}{81} \, x e^{\left (-2 \, x\right )} \log \left (-x + 7\right )^{2} + \frac {1}{81} \, x^{2} e^{\left (-2 \, x\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 71 vs. \(2 (23) = 46\).
Time = 0.26 (sec) , antiderivative size = 71, normalized size of antiderivative = 3.23 \[ \int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{81 (-7+x)} \, dx=\frac {1}{81} \, {\left (4 \, {\left (x - 7\right )} e^{\left (-2 \, x + 14\right )} \log \left (-x + 7\right )^{2} + {\left (x - 7\right )}^{2} e^{\left (-2 \, x + 14\right )} + 28 \, e^{\left (-2 \, x + 14\right )} \log \left (-x + 7\right )^{2} + 14 \, {\left (x - 7\right )} e^{\left (-2 \, x + 14\right )} + 49 \, e^{\left (-2 \, x + 14\right )}\right )} e^{\left (-14\right )} \]
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Timed out. \[ \int \frac {e^{-2 x} \left (-14 x+16 x^2-2 x^3+8 x \log (7-x)+\left (-28+60 x-8 x^2\right ) \log ^2(7-x)\right )}{81 (-7+x)} \, dx=\int -\frac {{\mathrm {e}}^{-2\,x-4\,\ln \left (3\right )}\,\left (14\,x-8\,x\,\ln \left (7-x\right )+{\ln \left (7-x\right )}^2\,\left (8\,x^2-60\,x+28\right )-16\,x^2+2\,x^3\right )}{x-7} \,d x \]
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