Integrand size = 99, antiderivative size = 29 \[ \int \frac {3840-8960 x+2560 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)+\left (-7680 x+1280 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)\right ) \log (x)+\left (-480+640 x-160 x^2+\left (480 x-160 x^2\right ) \log (x)\right ) \log (\log (3))+(15-5 x) \log ^2(\log (3))}{-768 x+256 x^2} \, dx=5 \log (x) \left (x (x-\log (-3+x))-\left (-1+x+\frac {1}{16} \log (\log (3))\right )^2\right ) \]
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Leaf count is larger than twice the leaf count of optimal. \(110\) vs. \(2(29)=58\).
Time = 0.27 (sec) , antiderivative size = 110, normalized size of antiderivative = 3.79, number of steps used = 18, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.131, Rules used = {1607, 6820, 2436, 2332, 2417, 2458, 45, 2393, 2354, 2438, 2404, 2353, 2352} \[ \int \frac {3840-8960 x+2560 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)+\left (-7680 x+1280 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)\right ) \log (x)+\left (-480+640 x-160 x^2+\left (480 x-160 x^2\right ) \log (x)\right ) \log (\log (3))+(15-5 x) \log ^2(\log (3))}{-768 x+256 x^2} \, dx=-10 x+5 x (\log (x)+1)+\frac {5}{8} x (16-\log (\log (3)))+\frac {5}{8} x (8-\log (\log (3))) \log (x)-\frac {5}{8} x (8-\log (\log (3)))-5 (3-x) \log (x-3)-15 \log (3) \log (x-3)-15 \log (x-3) \log \left (\frac {x}{3}\right )+5 (3-x) \log (x-3) (\log (x)+1)-\frac {5}{256} (16-\log (\log (3)))^2 \log (x) \]
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Rule 45
Rule 1607
Rule 2332
Rule 2352
Rule 2353
Rule 2354
Rule 2393
Rule 2404
Rule 2417
Rule 2436
Rule 2438
Rule 2458
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \int \frac {3840-8960 x+2560 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)+\left (-7680 x+1280 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)\right ) \log (x)+\left (-480+640 x-160 x^2+\left (480 x-160 x^2\right ) \log (x)\right ) \log (\log (3))+(15-5 x) \log ^2(\log (3))}{x (-768+256 x)} \, dx \\ & = \int \left (-5 \log (-3+x) (1+\log (x))-\frac {5 \log (x) (48+x (-8+\log (\log (3)))-3 \log (\log (3)))}{8 (-3+x)}-\frac {5 (-16+\log (\log (3))) (-16+32 x+\log (\log (3)))}{256 x}\right ) \, dx \\ & = -\left (\frac {5}{8} \int \frac {\log (x) (48+x (-8+\log (\log (3)))-3 \log (\log (3)))}{-3+x} \, dx\right )-5 \int \log (-3+x) (1+\log (x)) \, dx+\frac {1}{256} (5 (16-\log (\log (3)))) \int \frac {-16+32 x+\log (\log (3))}{x} \, dx \\ & = 5 x (1+\log (x))+5 (3-x) \log (-3+x) (1+\log (x))-\frac {5}{8} \int \left (\frac {24 \log (x)}{-3+x}+\log (x) (-8+\log (\log (3)))\right ) \, dx+5 \int \left (-1-\frac {(3-x) \log (-3+x)}{x}\right ) \, dx+\frac {1}{256} (5 (16-\log (\log (3)))) \int \left (32+\frac {-16+\log (\log (3))}{x}\right ) \, dx \\ & = -5 x+5 x (1+\log (x))+5 (3-x) \log (-3+x) (1+\log (x))+\frac {5}{8} x (16-\log (\log (3)))-\frac {5}{256} \log (x) (16-\log (\log (3)))^2-5 \int \frac {(3-x) \log (-3+x)}{x} \, dx-15 \int \frac {\log (x)}{-3+x} \, dx+\frac {1}{8} (5 (8-\log (\log (3)))) \int \log (x) \, dx \\ & = -5 x-15 \log (3) \log (-3+x)+5 x (1+\log (x))+5 (3-x) \log (-3+x) (1+\log (x))-\frac {5}{8} x (8-\log (\log (3)))+\frac {5}{8} x \log (x) (8-\log (\log (3)))+\frac {5}{8} x (16-\log (\log (3)))-\frac {5}{256} \log (x) (16-\log (\log (3)))^2+5 \text {Subst}\left (\int \frac {x \log (x)}{3+x} \, dx,x,-3+x\right )-15 \int \frac {\log \left (\frac {x}{3}\right )}{-3+x} \, dx \\ & = -5 x-15 \log (3) \log (-3+x)+5 x (1+\log (x))+5 (3-x) \log (-3+x) (1+\log (x))-\frac {5}{8} x (8-\log (\log (3)))+\frac {5}{8} x \log (x) (8-\log (\log (3)))+\frac {5}{8} x (16-\log (\log (3)))-\frac {5}{256} \log (x) (16-\log (\log (3)))^2+15 \operatorname {PolyLog}\left (2,1-\frac {x}{3}\right )+5 \text {Subst}\left (\int \left (\log (x)-\frac {3 \log (x)}{3+x}\right ) \, dx,x,-3+x\right ) \\ & = -5 x-15 \log (3) \log (-3+x)+5 x (1+\log (x))+5 (3-x) \log (-3+x) (1+\log (x))-\frac {5}{8} x (8-\log (\log (3)))+\frac {5}{8} x \log (x) (8-\log (\log (3)))+\frac {5}{8} x (16-\log (\log (3)))-\frac {5}{256} \log (x) (16-\log (\log (3)))^2+15 \operatorname {PolyLog}\left (2,1-\frac {x}{3}\right )+5 \text {Subst}(\int \log (x) \, dx,x,-3+x)-15 \text {Subst}\left (\int \frac {\log (x)}{3+x} \, dx,x,-3+x\right ) \\ & = -10 x-5 (3-x) \log (-3+x)-15 \log (3) \log (-3+x)-15 \log (-3+x) \log \left (\frac {x}{3}\right )+5 x (1+\log (x))+5 (3-x) \log (-3+x) (1+\log (x))-\frac {5}{8} x (8-\log (\log (3)))+\frac {5}{8} x \log (x) (8-\log (\log (3)))+\frac {5}{8} x (16-\log (\log (3)))-\frac {5}{256} \log (x) (16-\log (\log (3)))^2+15 \operatorname {PolyLog}\left (2,1-\frac {x}{3}\right )+15 \text {Subst}\left (\int \frac {\log \left (1+\frac {x}{3}\right )}{x} \, dx,x,-3+x\right ) \\ & = -10 x-5 (3-x) \log (-3+x)-15 \log (3) \log (-3+x)-15 \log (-3+x) \log \left (\frac {x}{3}\right )+5 x (1+\log (x))+5 (3-x) \log (-3+x) (1+\log (x))-\frac {5}{8} x (8-\log (\log (3)))+\frac {5}{8} x \log (x) (8-\log (\log (3)))+\frac {5}{8} x (16-\log (\log (3)))-\frac {5}{256} \log (x) (16-\log (\log (3)))^2 \\ \end{align*}
Result contains higher order function than in optimal. Order 4 vs. order 3 in optimal.
Time = 0.13 (sec) , antiderivative size = 89, normalized size of antiderivative = 3.07 \[ \int \frac {3840-8960 x+2560 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)+\left (-7680 x+1280 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)\right ) \log (x)+\left (-480+640 x-160 x^2+\left (480 x-160 x^2\right ) \log (x)\right ) \log (\log (3))+(15-5 x) \log ^2(\log (3))}{-768 x+256 x^2} \, dx=-15 \log (3) \log (-3+x)-5 \log (x)+10 x \log (x)+15 \log \left (1-\frac {x}{3}\right ) \log (x)-5 x \log (-3+x) \log (x)+\frac {5}{8} \log (x) \log (\log (3))-\frac {5}{8} x \log (x) \log (\log (3))-\frac {5}{256} \log (x) \log ^2(\log (3))+15 \operatorname {PolyLog}\left (2,1-\frac {x}{3}\right )+15 \operatorname {PolyLog}\left (2,\frac {x}{3}\right ) \]
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Time = 0.82 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.34
method | result | size |
norman | \(\left (-5-\frac {5 \ln \left (\ln \left (3\right )\right )^{2}}{256}+\frac {5 \ln \left (\ln \left (3\right )\right )}{8}\right ) \ln \left (x \right )+\left (10-\frac {5 \ln \left (\ln \left (3\right )\right )}{8}\right ) x \ln \left (x \right )-5 \ln \left (x \right ) \ln \left (-3+x \right ) x\) | \(39\) |
risch | \(-5 \ln \left (x \right ) \ln \left (-3+x \right ) x -\frac {5 \ln \left (x \right ) \ln \left (\ln \left (3\right )\right ) x}{8}+10 x \ln \left (x \right )-\frac {5 \ln \left (\ln \left (3\right )\right )^{2} \ln \left (x \right )}{256}+\frac {5 \ln \left (\ln \left (3\right )\right ) \ln \left (x \right )}{8}-5 \ln \left (x \right )\) | \(44\) |
parallelrisch | \(-5 \ln \left (x \right ) \ln \left (-3+x \right ) x -\frac {5 \ln \left (x \right ) \ln \left (\ln \left (3\right )\right ) x}{8}+10 x \ln \left (x \right )-\frac {5 \ln \left (\ln \left (3\right )\right )^{2} \ln \left (x \right )}{256}+\frac {5 \ln \left (\ln \left (3\right )\right ) \ln \left (x \right )}{8}-5 \ln \left (x \right )\) | \(44\) |
parts | \(-15 \ln \left (-3+x \right )-10 x +\frac {5 \ln \left (\ln \left (3\right )\right ) x}{8}+\frac {5 \left (16-\ln \left (\ln \left (3\right )\right )\right ) \ln \left (x \right ) x}{8}+5 \ln \left (-3+x \right ) x -5 \ln \left (x \right ) \ln \left (-3+x \right ) x -\frac {5 \left (-16+\ln \left (\ln \left (3\right )\right )\right ) \left (32 x +\left (-16+\ln \left (\ln \left (3\right )\right )\right ) \ln \left (x \right )\right )}{256}-5 \left (-3+x \right ) \ln \left (-3+x \right )-15\) | \(74\) |
default | \(-15 \ln \left (-3+x \right )+\frac {5 \ln \left (\ln \left (3\right )\right ) x}{8}+\frac {5 \left (16-\ln \left (\ln \left (3\right )\right )\right ) \ln \left (x \right ) x}{8}+5 \ln \left (-3+x \right ) x -5 \ln \left (x \right ) \ln \left (-3+x \right ) x -\frac {5 \ln \left (\ln \left (3\right )\right )^{2} \ln \left (x \right )}{256}-5 \ln \left (x \right )-\frac {5 \ln \left (\ln \left (3\right )\right ) \left (x -\ln \left (x \right )\right )}{8}-5 \left (-3+x \right ) \ln \left (-3+x \right )-15\) | \(76\) |
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Time = 0.25 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.21 \[ \int \frac {3840-8960 x+2560 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)+\left (-7680 x+1280 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)\right ) \log (x)+\left (-480+640 x-160 x^2+\left (480 x-160 x^2\right ) \log (x)\right ) \log (\log (3))+(15-5 x) \log ^2(\log (3))}{-768 x+256 x^2} \, dx=-\frac {5}{8} \, {\left (x - 1\right )} \log \left (x\right ) \log \left (\log \left (3\right )\right ) - \frac {5}{256} \, \log \left (x\right ) \log \left (\log \left (3\right )\right )^{2} - 5 \, {\left (x \log \left (x - 3\right ) - 2 \, x + 1\right )} \log \left (x\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 97 vs. \(2 (24) = 48\).
Time = 0.97 (sec) , antiderivative size = 97, normalized size of antiderivative = 3.34 \[ \int \frac {3840-8960 x+2560 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)+\left (-7680 x+1280 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)\right ) \log (x)+\left (-480+640 x-160 x^2+\left (480 x-160 x^2\right ) \log (x)\right ) \log (\log (3))+(15-5 x) \log ^2(\log (3))}{-768 x+256 x^2} \, dx=\left (- 5 x \log {\left (x \right )} - \frac {15}{4}\right ) \log {\left (x - 3 \right )} + \left (- \frac {5 x \log {\left (\log {\left (3 \right )} \right )}}{8} + 10 x\right ) \log {\left (x \right )} - \left (- \frac {5 \log {\left (\log {\left (3 \right )} \right )}}{8} + \frac {5 \log {\left (\log {\left (3 \right )} \right )}^{2}}{256} + 5\right ) \log {\left (x \right )} + \frac {15 \log {\left (x + \frac {-6720 - 15 \log {\left (\log {\left (3 \right )} \right )}^{2} + 480 \log {\left (\log {\left (3 \right )} \right )}}{- 160 \log {\left (\log {\left (3 \right )} \right )} + 5 \log {\left (\log {\left (3 \right )} \right )}^{2} + 2240} \right )}}{4} \]
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Leaf count of result is larger than twice the leaf count of optimal. 132 vs. \(2 (26) = 52\).
Time = 0.31 (sec) , antiderivative size = 132, normalized size of antiderivative = 4.55 \[ \int \frac {3840-8960 x+2560 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)+\left (-7680 x+1280 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)\right ) \log (x)+\left (-480+640 x-160 x^2+\left (480 x-160 x^2\right ) \log (x)\right ) \log (\log (3))+(15-5 x) \log ^2(\log (3))}{-768 x+256 x^2} \, dx=-\frac {5}{8} \, x {\left (\log \left (\log \left (3\right )\right ) - 16\right )} \log \left (x\right ) + \frac {5}{256} \, {\left (\log \left (x - 3\right ) - \log \left (x\right )\right )} \log \left (\log \left (3\right )\right )^{2} - \frac {5}{256} \, \log \left (x - 3\right ) \log \left (\log \left (3\right )\right )^{2} + \frac {5}{8} \, x {\left (\log \left (\log \left (3\right )\right ) - 24\right )} - 5 \, {\left (x \log \left (x\right ) - x + 3\right )} \log \left (x - 3\right ) - 5 \, {\left (x + 3 \, \log \left (x - 3\right )\right )} \log \left (x - 3\right ) + 15 \, \log \left (x - 3\right )^{2} - \frac {5}{8} \, {\left (x + 3 \, \log \left (x - 3\right )\right )} \log \left (\log \left (3\right )\right ) - \frac {5}{8} \, {\left (\log \left (x - 3\right ) - \log \left (x\right )\right )} \log \left (\log \left (3\right )\right ) + \frac {5}{2} \, \log \left (x - 3\right ) \log \left (\log \left (3\right )\right ) + 15 \, x + 15 \, \log \left (x - 3\right ) - 5 \, \log \left (x\right ) \]
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Time = 0.27 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.24 \[ \int \frac {3840-8960 x+2560 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)+\left (-7680 x+1280 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)\right ) \log (x)+\left (-480+640 x-160 x^2+\left (480 x-160 x^2\right ) \log (x)\right ) \log (\log (3))+(15-5 x) \log ^2(\log (3))}{-768 x+256 x^2} \, dx=-\frac {5}{8} \, x {\left (\log \left (\log \left (3\right )\right ) - 16\right )} \log \left (x\right ) - 5 \, x \log \left (x - 3\right ) \log \left (x\right ) - \frac {5}{256} \, {\left (\log \left (\log \left (3\right )\right )^{2} - 32 \, \log \left (\log \left (3\right )\right ) + 256\right )} \log \left (x\right ) \]
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Time = 11.14 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.10 \[ \int \frac {3840-8960 x+2560 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)+\left (-7680 x+1280 x^2+\left (3840 x-1280 x^2\right ) \log (-3+x)\right ) \log (x)+\left (-480+640 x-160 x^2+\left (480 x-160 x^2\right ) \log (x)\right ) \log (\log (3))+(15-5 x) \log ^2(\log (3))}{-768 x+256 x^2} \, dx=-\frac {5\,\ln \left (x\right )\,\left (256\,x\,\ln \left (x-3\right )-32\,\ln \left (\ln \left (3\right )\right )-512\,x+{\ln \left (\ln \left (3\right )\right )}^2+32\,x\,\ln \left (\ln \left (3\right )\right )+256\right )}{256} \]
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