Integrand size = 76, antiderivative size = 29 \[ \int \frac {9-2 x \log (4)+e^x \left (-36+36 x-24 x^2+8 x \log (4)-4 x^2 \log ^2(4)\right )+\left (2 x+e^x \left (-8 x+8 x^2 \log (4)\right )\right ) \log (x)-4 e^x x^2 \log ^2(x)}{4 x^2} \, dx=\frac {\left (\frac {1}{4}-e^x\right ) \left (-9+x+x \left (5+(\log (4)-\log (x))^2\right )\right )}{x} \]
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\[ \int \frac {9-2 x \log (4)+e^x \left (-36+36 x-24 x^2+8 x \log (4)-4 x^2 \log ^2(4)\right )+\left (2 x+e^x \left (-8 x+8 x^2 \log (4)\right )\right ) \log (x)-4 e^x x^2 \log ^2(x)}{4 x^2} \, dx=\int \frac {9-2 x \log (4)+e^x \left (-36+36 x-24 x^2+8 x \log (4)-4 x^2 \log ^2(4)\right )+\left (2 x+e^x \left (-8 x+8 x^2 \log (4)\right )\right ) \log (x)-4 e^x x^2 \log ^2(x)}{4 x^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {1}{4} \int \frac {9-2 x \log (4)+e^x \left (-36+36 x-24 x^2+8 x \log (4)-4 x^2 \log ^2(4)\right )+\left (2 x+e^x \left (-8 x+8 x^2 \log (4)\right )\right ) \log (x)-4 e^x x^2 \log ^2(x)}{x^2} \, dx \\ & = \frac {1}{4} \int \left (\frac {9-2 x \log (4)+2 x \log (x)}{x^2}+\frac {4 e^x \left (-9+9 x \left (1+\frac {4 \log (2)}{9}\right )-6 x^2 \left (1+\frac {\log ^2(4)}{6}\right )-2 x \log (x)+2 x^2 \log (4) \log (x)-x^2 \log ^2(x)\right )}{x^2}\right ) \, dx \\ & = \frac {1}{4} \int \frac {9-2 x \log (4)+2 x \log (x)}{x^2} \, dx+\int \frac {e^x \left (-9+9 x \left (1+\frac {4 \log (2)}{9}\right )-6 x^2 \left (1+\frac {\log ^2(4)}{6}\right )-2 x \log (x)+2 x^2 \log (4) \log (x)-x^2 \log ^2(x)\right )}{x^2} \, dx \\ & = \frac {1}{4} \int \left (\frac {9-2 x \log (4)}{x^2}+\frac {2 \log (x)}{x}\right ) \, dx+\int \left (\frac {e^x \left (-9-x^2 \left (6+\log ^2(4)\right )+x (9+\log (16))\right )}{x^2}+\frac {2 e^x (-1+x \log (4)) \log (x)}{x}-e^x \log ^2(x)\right ) \, dx \\ & = \frac {1}{4} \int \frac {9-2 x \log (4)}{x^2} \, dx+\frac {1}{2} \int \frac {\log (x)}{x} \, dx+2 \int \frac {e^x (-1+x \log (4)) \log (x)}{x} \, dx+\int \frac {e^x \left (-9-x^2 \left (6+\log ^2(4)\right )+x (9+\log (16))\right )}{x^2} \, dx-\int e^x \log ^2(x) \, dx \\ & = -2 \operatorname {ExpIntegralEi}(x) \log (x)+2 e^x \log (4) \log (x)+\frac {\log ^2(x)}{4}+\frac {1}{4} \int \left (\frac {9}{x^2}-\frac {2 \log (4)}{x}\right ) \, dx-2 \int \frac {-\operatorname {ExpIntegralEi}(x)+e^x \log (4)}{x} \, dx+\int \left (-\frac {9 e^x}{x^2}-6 e^x \left (1+\frac {\log ^2(4)}{6}\right )+\frac {e^x (9+\log (16))}{x}\right ) \, dx-\int e^x \log ^2(x) \, dx \\ & = -\frac {9}{4 x}-2 \operatorname {ExpIntegralEi}(x) \log (x)-\frac {1}{2} \log (4) \log (x)+2 e^x \log (4) \log (x)+\frac {\log ^2(x)}{4}-2 \int \left (-\frac {\operatorname {ExpIntegralEi}(x)}{x}+\frac {e^x \log (4)}{x}\right ) \, dx-9 \int \frac {e^x}{x^2} \, dx-\left (6+\log ^2(4)\right ) \int e^x \, dx+(9+\log (16)) \int \frac {e^x}{x} \, dx-\int e^x \log ^2(x) \, dx \\ & = -\frac {9}{4 x}+\frac {9 e^x}{x}-e^x \left (6+\log ^2(4)\right )+\operatorname {ExpIntegralEi}(x) (9+\log (16))-2 \operatorname {ExpIntegralEi}(x) \log (x)-\frac {1}{2} \log (4) \log (x)+2 e^x \log (4) \log (x)+\frac {\log ^2(x)}{4}+2 \int \frac {\operatorname {ExpIntegralEi}(x)}{x} \, dx-9 \int \frac {e^x}{x} \, dx-(2 \log (4)) \int \frac {e^x}{x} \, dx-\int e^x \log ^2(x) \, dx \\ & = -\frac {9}{4 x}+\frac {9 e^x}{x}-9 \operatorname {ExpIntegralEi}(x)-2 \operatorname {ExpIntegralEi}(x) \log (4)-e^x \left (6+\log ^2(4)\right )+\operatorname {ExpIntegralEi}(x) (9+\log (16))-2 \operatorname {ExpIntegralEi}(x) \log (x)+2 (\operatorname {ExpIntegralE}(1,-x)+\operatorname {ExpIntegralEi}(x)) \log (x)-\frac {1}{2} \log (4) \log (x)+2 e^x \log (4) \log (x)+\frac {\log ^2(x)}{4}-2 \int \frac {\operatorname {ExpIntegralE}(1,-x)}{x} \, dx-\int e^x \log ^2(x) \, dx \\ & = -\frac {9}{4 x}+\frac {9 e^x}{x}-9 \operatorname {ExpIntegralEi}(x)+2 x \, _3F_3(1,1,1;2,2,2;x)-2 \operatorname {ExpIntegralEi}(x) \log (4)-e^x \left (6+\log ^2(4)\right )+\operatorname {ExpIntegralEi}(x) (9+\log (16))+\log ^2(-x)+2 \gamma \log (x)-2 \operatorname {ExpIntegralEi}(x) \log (x)+2 (\operatorname {ExpIntegralE}(1,-x)+\operatorname {ExpIntegralEi}(x)) \log (x)-\frac {1}{2} \log (4) \log (x)+2 e^x \log (4) \log (x)+\frac {\log ^2(x)}{4}-\int e^x \log ^2(x) \, dx \\ \end{align*}
Time = 0.62 (sec) , antiderivative size = 58, normalized size of antiderivative = 2.00 \[ \int \frac {9-2 x \log (4)+e^x \left (-36+36 x-24 x^2+8 x \log (4)-4 x^2 \log ^2(4)\right )+\left (2 x+e^x \left (-8 x+8 x^2 \log (4)\right )\right ) \log (x)-4 e^x x^2 \log ^2(x)}{4 x^2} \, dx=\frac {1}{4} \left (-24 e^x-\frac {9}{x}+\frac {36 e^x}{x}-4 e^x \log ^2(4)+\log ^2\left (\frac {x}{4}\right )+4 e^x \log (16) \log (x)-4 e^x \log ^2(x)\right ) \]
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Time = 0.32 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.86
method | result | size |
risch | \(\frac {\left (-4 \,{\mathrm e}^{x}+1\right ) \ln \left (x \right )^{2}}{4}+4 \ln \left (2\right ) \ln \left (x \right ) {\mathrm e}^{x}-\frac {16 x \ln \left (2\right )^{2} {\mathrm e}^{x}+4 x \ln \left (2\right ) \ln \left (x \right )+24 \,{\mathrm e}^{x} x -36 \,{\mathrm e}^{x}+9}{4 x}\) | \(54\) |
norman | \(\frac {-\frac {9}{4}-x \ln \left (2\right ) \ln \left (x \right )+\left (-4 \ln \left (2\right )^{2}-6\right ) x \,{\mathrm e}^{x}+\frac {x \ln \left (x \right )^{2}}{4}-x \,{\mathrm e}^{x} \ln \left (x \right )^{2}+4 x \ln \left (2\right ) {\mathrm e}^{x} \ln \left (x \right )+9 \,{\mathrm e}^{x}}{x}\) | \(55\) |
parallelrisch | \(-\frac {4 x \,{\mathrm e}^{x} \ln \left (x \right )^{2}-16 x \ln \left (2\right ) {\mathrm e}^{x} \ln \left (x \right )+16 x \ln \left (2\right )^{2} {\mathrm e}^{x}-x \ln \left (x \right )^{2}+4 x \ln \left (2\right ) \ln \left (x \right )+24 \,{\mathrm e}^{x} x -36 \,{\mathrm e}^{x}+9}{4 x}\) | \(58\) |
parts | \(\frac {\left (-4 \ln \left (2\right )^{2}-6\right ) x \,{\mathrm e}^{x}-x \,{\mathrm e}^{x} \ln \left (x \right )^{2}+4 x \ln \left (2\right ) {\mathrm e}^{x} \ln \left (x \right )+9 \,{\mathrm e}^{x}}{x}-\ln \left (2\right ) \ln \left (x \right )-\frac {9}{4 x}+\frac {\ln \left (x \right )^{2}}{4}\) | \(58\) |
default | \(\frac {\left (-16 \ln \left (2\right )^{2}-24\right ) x \,{\mathrm e}^{x}-4 x \,{\mathrm e}^{x} \ln \left (x \right )^{2}+16 x \ln \left (2\right ) {\mathrm e}^{x} \ln \left (x \right )+36 \,{\mathrm e}^{x}}{4 x}-\ln \left (2\right ) \ln \left (x \right )-\frac {9}{4 x}+\frac {\ln \left (x \right )^{2}}{4}\) | \(59\) |
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Time = 0.27 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.86 \[ \int \frac {9-2 x \log (4)+e^x \left (-36+36 x-24 x^2+8 x \log (4)-4 x^2 \log ^2(4)\right )+\left (2 x+e^x \left (-8 x+8 x^2 \log (4)\right )\right ) \log (x)-4 e^x x^2 \log ^2(x)}{4 x^2} \, dx=-\frac {{\left (4 \, x e^{x} - x\right )} \log \left (x\right )^{2} + 4 \, {\left (4 \, x \log \left (2\right )^{2} + 6 \, x - 9\right )} e^{x} - 4 \, {\left (4 \, x e^{x} \log \left (2\right ) - x \log \left (2\right )\right )} \log \left (x\right ) + 9}{4 \, x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 53 vs. \(2 (24) = 48\).
Time = 0.16 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.83 \[ \int \frac {9-2 x \log (4)+e^x \left (-36+36 x-24 x^2+8 x \log (4)-4 x^2 \log ^2(4)\right )+\left (2 x+e^x \left (-8 x+8 x^2 \log (4)\right )\right ) \log (x)-4 e^x x^2 \log ^2(x)}{4 x^2} \, dx=\frac {\log {\left (x \right )}^{2}}{4} - \log {\left (2 \right )} \log {\left (x \right )} + \frac {\left (- x \log {\left (x \right )}^{2} + 4 x \log {\left (2 \right )} \log {\left (x \right )} - 6 x - 4 x \log {\left (2 \right )}^{2} + 9\right ) e^{x}}{x} - \frac {9}{4 x} \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 0.24 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.97 \[ \int \frac {9-2 x \log (4)+e^x \left (-36+36 x-24 x^2+8 x \log (4)-4 x^2 \log ^2(4)\right )+\left (2 x+e^x \left (-8 x+8 x^2 \log (4)\right )\right ) \log (x)-4 e^x x^2 \log ^2(x)}{4 x^2} \, dx=-4 \, e^{x} \log \left (2\right )^{2} + 4 \, e^{x} \log \left (2\right ) \log \left (x\right ) - e^{x} \log \left (x\right )^{2} - \log \left (2\right ) \log \left (x\right ) + \frac {1}{4} \, \log \left (x\right )^{2} - \frac {9}{4 \, x} + 9 \, {\rm Ei}\left (x\right ) - 6 \, e^{x} - 9 \, \Gamma \left (-1, -x\right ) \]
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Time = 0.26 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.97 \[ \int \frac {9-2 x \log (4)+e^x \left (-36+36 x-24 x^2+8 x \log (4)-4 x^2 \log ^2(4)\right )+\left (2 x+e^x \left (-8 x+8 x^2 \log (4)\right )\right ) \log (x)-4 e^x x^2 \log ^2(x)}{4 x^2} \, dx=-\frac {16 \, x e^{x} \log \left (2\right )^{2} - 16 \, x e^{x} \log \left (2\right ) \log \left (x\right ) + 4 \, x e^{x} \log \left (x\right )^{2} + 4 \, x \log \left (2\right ) \log \left (x\right ) - x \log \left (x\right )^{2} + 24 \, x e^{x} - 36 \, e^{x} + 9}{4 \, x} \]
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Time = 9.32 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.76 \[ \int \frac {9-2 x \log (4)+e^x \left (-36+36 x-24 x^2+8 x \log (4)-4 x^2 \log ^2(4)\right )+\left (2 x+e^x \left (-8 x+8 x^2 \log (4)\right )\right ) \log (x)-4 e^x x^2 \log ^2(x)}{4 x^2} \, dx=\frac {{\ln \left (x\right )}^2}{4}-4\,{\mathrm {e}}^x\,{\ln \left (2\right )}^2-6\,{\mathrm {e}}^x-{\mathrm {e}}^x\,{\ln \left (x\right )}^2-\ln \left (2\right )\,\ln \left (x\right )+\frac {9\,{\mathrm {e}}^x-\frac {9}{4}}{x}+4\,{\mathrm {e}}^x\,\ln \left (2\right )\,\ln \left (x\right ) \]
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