Integrand size = 107, antiderivative size = 24 \[ \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x+2 x^4+x^7} \, dx=e^{e^{2-x+2 \left (1-\frac {5}{x+x^4}\right )} x} \]
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\[ \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x+2 x^4+x^7} \, dx=\int \frac {\exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right ) \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x+2 x^4+x^7} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right ) \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x \left (1+2 x^3+x^6\right )} \, dx \\ & = \int \frac {\exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right ) \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x \left (1+x^3\right )^2} \, dx \\ & = \int \left (\exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right )+\frac {10 \exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right )}{x}-\exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right ) x+\frac {10 \exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right )}{3 (1+x)^2}-\frac {10 \exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right )}{3 (1+x)}+\frac {10 \exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right ) x}{\left (1-x+x^2\right )^2}-\frac {20 \exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right ) x}{3 \left (1-x+x^2\right )}\right ) \, dx \\ & = \frac {10}{3} \int \frac {\exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right )}{(1+x)^2} \, dx-\frac {10}{3} \int \frac {\exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right )}{1+x} \, dx-\frac {20}{3} \int \frac {\exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right ) x}{1-x+x^2} \, dx+10 \int \frac {\exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right )}{x} \, dx+10 \int \frac {\exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right ) x}{\left (1-x+x^2\right )^2} \, dx+\int \exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right ) \, dx-\int \exp \left (e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}\right ) x \, dx \\ & = \frac {10}{3} \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{(1+x)^2} \, dx-\frac {10}{3} \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{1+x} \, dx-\frac {20}{3} \int \left (\frac {\left (1-\frac {i}{\sqrt {3}}\right ) e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{-1-i \sqrt {3}+2 x}+\frac {\left (1+\frac {i}{\sqrt {3}}\right ) e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{-1+i \sqrt {3}+2 x}\right ) \, dx+10 \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{x} \, dx+10 \int \left (-\frac {2 \left (1+i \sqrt {3}\right ) e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{3 \left (1+i \sqrt {3}-2 x\right )^2}+\frac {2 i e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{3 \sqrt {3} \left (1+i \sqrt {3}-2 x\right )}-\frac {2 \left (1-i \sqrt {3}\right ) e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{3 \left (-1+i \sqrt {3}+2 x\right )^2}+\frac {2 i e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{3 \sqrt {3} \left (-1+i \sqrt {3}+2 x\right )}\right ) \, dx+\int e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} \, dx-\int e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x \, dx \\ & = \frac {10}{3} \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{(1+x)^2} \, dx-\frac {10}{3} \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{1+x} \, dx+10 \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{x} \, dx+\frac {(20 i) \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{1+i \sqrt {3}-2 x} \, dx}{3 \sqrt {3}}+\frac {(20 i) \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{-1+i \sqrt {3}+2 x} \, dx}{3 \sqrt {3}}-\frac {1}{3} \left (20 \left (1-i \sqrt {3}\right )\right ) \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{\left (-1+i \sqrt {3}+2 x\right )^2} \, dx-\frac {1}{9} \left (20 \left (3-i \sqrt {3}\right )\right ) \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{-1-i \sqrt {3}+2 x} \, dx-\frac {1}{3} \left (20 \left (1+i \sqrt {3}\right )\right ) \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{\left (1+i \sqrt {3}-2 x\right )^2} \, dx-\frac {1}{9} \left (20 \left (3+i \sqrt {3}\right )\right ) \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}}}{-1+i \sqrt {3}+2 x} \, dx+\int e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} \, dx-\int e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x \, dx \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.17 \[ \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x+2 x^4+x^7} \, dx=e^{e^{4-\frac {10}{x}-x+\frac {10 x^2}{1+x^3}} x} \]
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Time = 22.77 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.38
method | result | size |
parallelrisch | \({\mathrm e}^{x \,{\mathrm e}^{-\frac {x^{5}-4 x^{4}+x^{2}-4 x +10}{x \left (x^{3}+1\right )}}}\) | \(33\) |
risch | \({\mathrm e}^{x \,{\mathrm e}^{-\frac {x^{5}-4 x^{4}+x^{2}-4 x +10}{x \left (1+x \right ) \left (x^{2}-x +1\right )}}}\) | \(41\) |
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Leaf count of result is larger than twice the leaf count of optimal. 86 vs. \(2 (18) = 36\).
Time = 0.26 (sec) , antiderivative size = 86, normalized size of antiderivative = 3.58 \[ \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x+2 x^4+x^7} \, dx=e^{\left (-\frac {x^{5} - 4 \, x^{4} + x^{2} - {\left (x^{5} + x^{2}\right )} e^{\left (-\frac {x^{5} - 4 \, x^{4} + x^{2} - 4 \, x + 10}{x^{4} + x}\right )} - 4 \, x + 10}{x^{4} + x} + \frac {x^{5} - 4 \, x^{4} + x^{2} - 4 \, x + 10}{x^{4} + x}\right )} \]
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Time = 0.39 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x+2 x^4+x^7} \, dx=e^{x e^{\frac {- x^{5} + 4 x^{4} - x^{2} + 4 x - 10}{x^{4} + x}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 46 vs. \(2 (18) = 36\).
Time = 0.93 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.92 \[ \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x+2 x^4+x^7} \, dx=e^{\left (x e^{\left (-x + \frac {20 \, x}{3 \, {\left (x^{2} - x + 1\right )}} - \frac {10}{3 \, {\left (x^{2} - x + 1\right )}} + \frac {10}{3 \, {\left (x + 1\right )}} - \frac {10}{x} + 4\right )}\right )} \]
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\[ \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x+2 x^4+x^7} \, dx=\int { -\frac {{\left (x^{8} - x^{7} + 2 \, x^{5} - 2 \, x^{4} - 40 \, x^{3} + x^{2} - x - 10\right )} e^{\left (x e^{\left (-\frac {x^{5} - 4 \, x^{4} + x^{2} - 4 \, x + 10}{x^{4} + x}\right )} - \frac {x^{5} - 4 \, x^{4} + x^{2} - 4 \, x + 10}{x^{4} + x}\right )}}{x^{7} + 2 \, x^{4} + x} \,d x } \]
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Time = 9.35 (sec) , antiderivative size = 60, normalized size of antiderivative = 2.50 \[ \int \frac {e^{e^{\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} x+\frac {-10+4 x-x^2+4 x^4-x^5}{x+x^4}} \left (10+x-x^2+40 x^3+2 x^4-2 x^5+x^7-x^8\right )}{x+2 x^4+x^7} \, dx={\mathrm {e}}^{x\,{\mathrm {e}}^{-\frac {x^4}{x^3+1}}\,{\mathrm {e}}^{\frac {4\,x^3}{x^3+1}}\,{\mathrm {e}}^{\frac {4}{x^3+1}}\,{\mathrm {e}}^{-\frac {x}{x^3+1}}\,{\mathrm {e}}^{-\frac {10}{x^4+x}}} \]
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