\(\int -\frac {19 e^{16}}{25} \, dx\) [2540]

Optimal result

Integrand size = 7, antiderivative size = 13 \[ \int -\frac {19 e^{16}}{25} \, dx=-\frac {19}{25} \left (-7+e^{16} (1+x)\right ) \]

[Out]

-19/25*exp(16)*(1+x)+133/25

Rubi [A] (verified)

Time = 0.00 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.62, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {8} \[ \int -\frac {19 e^{16}}{25} \, dx=-\frac {19 e^{16} x}{25} \]

[In]

Int[(-19*E^16)/25,x]

[Out]

(-19*E^16*x)/25

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rubi steps \begin{align*} \text {integral}& = -\frac {19 e^{16} x}{25} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.00 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.62 \[ \int -\frac {19 e^{16}}{25} \, dx=-\frac {19 e^{16} x}{25} \]

[In]

Integrate[(-19*E^16)/25,x]

[Out]

(-19*E^16*x)/25

Maple [A] (verified)

Time = 0.03 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.46

method	result	size
default	\(-\frac {19 x \,{\mathrm e}^{16}}{25}\)	\(6\)
norman	\(-\frac {19 x \,{\mathrm e}^{16}}{25}\)	\(6\)
risch	\(-\frac {19 x \,{\mathrm e}^{16}}{25}\)	\(6\)
parallelrisch	\(-\frac {19 x \,{\mathrm e}^{16}}{25}\)	\(6\)

[In]

int(-19/25*exp(16),x,method=_RETURNVERBOSE)

[Out]

-19/25*x*exp(16)

Fricas [A] (verification not implemented)

none

Time = 0.23 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.38 \[ \int -\frac {19 e^{16}}{25} \, dx=-\frac {19}{25} \, x e^{16} \]

[In]

integrate(-19/25*exp(16),x, algorithm="fricas")

[Out]

-19/25*x*e^16

Sympy [A] (verification not implemented)

Time = 0.02 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.62 \[ \int -\frac {19 e^{16}}{25} \, dx=- \frac {19 x e^{16}}{25} \]

[In]

integrate(-19/25*exp(16),x)

[Out]

-19*x*exp(16)/25

Maxima [A] (verification not implemented)

none

Time = 0.19 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.38 \[ \int -\frac {19 e^{16}}{25} \, dx=-\frac {19}{25} \, x e^{16} \]

[In]

integrate(-19/25*exp(16),x, algorithm="maxima")

[Out]

-19/25*x*e^16

Giac [A] (verification not implemented)

none

Time = 0.25 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.38 \[ \int -\frac {19 e^{16}}{25} \, dx=-\frac {19}{25} \, x e^{16} \]

[In]

integrate(-19/25*exp(16),x, algorithm="giac")

[Out]

-19/25*x*e^16

Mupad [B] (verification not implemented)

Time = 0.00 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.38 \[ \int -\frac {19 e^{16}}{25} \, dx=-\frac {19\,x\,{\mathrm {e}}^{16}}{25} \]

[In]

int(-(19*exp(16))/25,x)

[Out]

-(19*x*exp(16))/25