Integrand size = 49, antiderivative size = 22 \[ \int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{e^{12} \left (-50787 x+81 x^3+324 x^4\right )} \, dx=\frac {\log ^4\left (-\frac {627}{x}+x+4 x^2\right )}{81 e^{12}} \]
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\[ \int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{e^{12} \left (-50787 x+81 x^3+324 x^4\right )} \, dx=\int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{e^{12} \left (-50787 x+81 x^3+324 x^4\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {\int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-50787 x+81 x^3+324 x^4} \, dx}{e^{12}} \\ & = \frac {\int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{x \left (-50787+81 x^2+324 x^3\right )} \, dx}{e^{12}} \\ & = \frac {\int \left (-\frac {4 \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{81 x}+\frac {8 x (1+6 x) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{81 \left (-627+x^2+4 x^3\right )}\right ) \, dx}{e^{12}} \\ & = -\frac {4 \int \frac {\log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{x} \, dx}{81 e^{12}}+\frac {8 \int \frac {x (1+6 x) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{81 e^{12}} \\ & = -\frac {4 \log (x) \log ^3\left (-\frac {627-x^2-4 x^3}{x}\right )}{81 e^{12}}+\frac {8 \int \left (\frac {x \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3}+\frac {6 x^2 \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3}\right ) \, dx}{81 e^{12}}+\frac {4 \int \frac {x \left (\frac {2 x+12 x^2}{x}-\frac {-627+x^2+4 x^3}{x^2}\right ) \log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{27 e^{12}} \\ & = -\frac {4 \log (x) \log ^3\left (-\frac {627-x^2-4 x^3}{x}\right )}{81 e^{12}}+\frac {8 \int \frac {x \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{81 e^{12}}+\frac {4 \int \frac {\left (-627-x^2-8 x^3\right ) \log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{x \left (627-x^2-4 x^3\right )} \, dx}{27 e^{12}}+\frac {16 \int \frac {x^2 \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{27 e^{12}} \\ & = -\frac {4 \log (x) \log ^3\left (-\frac {627-x^2-4 x^3}{x}\right )}{81 e^{12}}+\frac {8 \int \frac {x \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{81 e^{12}}+\frac {4 \int \left (-\frac {\log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{x}+\frac {2 (-1-6 x) x \log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{627-x^2-4 x^3}\right ) \, dx}{27 e^{12}}+\frac {16 \int \frac {x^2 \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{27 e^{12}} \\ & = -\frac {4 \log (x) \log ^3\left (-\frac {627-x^2-4 x^3}{x}\right )}{81 e^{12}}+\frac {8 \int \frac {x \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{81 e^{12}}-\frac {4 \int \frac {\log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{x} \, dx}{27 e^{12}}+\frac {8 \int \frac {(-1-6 x) x \log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{627-x^2-4 x^3} \, dx}{27 e^{12}}+\frac {16 \int \frac {x^2 \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{27 e^{12}} \\ & = -\frac {4 \log (x) \log ^3\left (-\frac {627-x^2-4 x^3}{x}\right )}{81 e^{12}}+\frac {8 \int \frac {x \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{81 e^{12}}-\frac {4 \int \frac {\log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{x} \, dx}{27 e^{12}}+\frac {8 \int \left (\frac {x \log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3}+\frac {6 x^2 \log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3}\right ) \, dx}{27 e^{12}}+\frac {16 \int \frac {x^2 \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{27 e^{12}} \\ & = -\frac {4 \log (x) \log ^3\left (-\frac {627-x^2-4 x^3}{x}\right )}{81 e^{12}}+\frac {8 \int \frac {x \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{81 e^{12}}-\frac {4 \int \frac {\log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{x} \, dx}{27 e^{12}}+\frac {8 \int \frac {x \log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{27 e^{12}}+\frac {16 \int \frac {x^2 \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{27 e^{12}}+\frac {16 \int \frac {x^2 \log (x) \log ^2\left (\frac {-627+x^2+4 x^3}{x}\right )}{-627+x^2+4 x^3} \, dx}{9 e^{12}} \\ \end{align*}
Time = 0.16 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00 \[ \int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{e^{12} \left (-50787 x+81 x^3+324 x^4\right )} \, dx=\frac {\log ^4\left (-\frac {627}{x}+x+4 x^2\right )}{81 e^{12}} \]
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Time = 0.68 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00
method | result | size |
risch | \(\frac {{\mathrm e}^{-12} \ln \left (\frac {4 x^{3}+x^{2}-627}{x}\right )^{4}}{81}\) | \(22\) |
default | \(\frac {{\mathrm e}^{-12} \ln \left (\frac {4 x^{3}+x^{2}-627}{x}\right )^{4}}{81}\) | \(24\) |
norman | \(\frac {{\mathrm e}^{-12} \ln \left (\frac {4 x^{3}+x^{2}-627}{x}\right )^{4}}{81}\) | \(24\) |
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Time = 0.26 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.95 \[ \int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{e^{12} \left (-50787 x+81 x^3+324 x^4\right )} \, dx=\frac {1}{81} \, e^{\left (-12\right )} \log \left (\frac {4 \, x^{3} + x^{2} - 627}{x}\right )^{4} \]
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Time = 0.09 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86 \[ \int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{e^{12} \left (-50787 x+81 x^3+324 x^4\right )} \, dx=\frac {\log {\left (\frac {4 x^{3} + x^{2} - 627}{x} \right )}^{4}}{81 e^{12}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 236 vs. \(2 (19) = 38\).
Time = 0.22 (sec) , antiderivative size = 236, normalized size of antiderivative = 10.73 \[ \int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{e^{12} \left (-50787 x+81 x^3+324 x^4\right )} \, dx=\frac {4}{81} \, {\left (\log \left (4 \, x^{3} + x^{2} - 627\right ) - \log \left (x\right )\right )} e^{\left (-12\right )} \log \left (\frac {4 \, x^{3} + x^{2} - 627}{x}\right )^{3} - \frac {1}{81} \, {\left (\log \left (4 \, x^{3} + x^{2} - 627\right )^{4} - 4 \, \log \left (4 \, x^{3} + x^{2} - 627\right )^{3} \log \left (x\right ) + 6 \, \log \left (4 \, x^{3} + x^{2} - 627\right )^{2} \log \left (x\right )^{2} - 4 \, \log \left (4 \, x^{3} + x^{2} - 627\right ) \log \left (x\right )^{3} + \log \left (x\right )^{4} + 6 \, {\left (\log \left (4 \, x^{3} + x^{2} - 627\right )^{2} - 2 \, \log \left (4 \, x^{3} + x^{2} - 627\right ) \log \left (x\right ) + \log \left (x\right )^{2}\right )} \log \left (\frac {4 \, x^{3} + x^{2} - 627}{x}\right )^{2} - 4 \, {\left (\log \left (4 \, x^{3} + x^{2} - 627\right )^{3} - 3 \, \log \left (4 \, x^{3} + x^{2} - 627\right )^{2} \log \left (x\right ) + 3 \, \log \left (4 \, x^{3} + x^{2} - 627\right ) \log \left (x\right )^{2} - \log \left (x\right )^{3}\right )} \log \left (\frac {4 \, x^{3} + x^{2} - 627}{x}\right )\right )} e^{\left (-12\right )} \]
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\[ \int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{e^{12} \left (-50787 x+81 x^3+324 x^4\right )} \, dx=\int { \frac {4 \, {\left (8 \, x^{3} + x^{2} + 627\right )} e^{\left (-12\right )} \log \left (\frac {4 \, x^{3} + x^{2} - 627}{x}\right )^{3}}{81 \, {\left (4 \, x^{4} + x^{3} - 627 \, x\right )}} \,d x } \]
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Time = 8.69 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.95 \[ \int \frac {\left (2508+4 x^2+32 x^3\right ) \log ^3\left (\frac {-627+x^2+4 x^3}{x}\right )}{e^{12} \left (-50787 x+81 x^3+324 x^4\right )} \, dx=\frac {{\ln \left (\frac {4\,x^3+x^2-627}{x}\right )}^4\,{\mathrm {e}}^{-12}}{81} \]
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