Integrand size = 94, antiderivative size = 25 \[ \int \frac {10602576-29160 x-2916 x^2+23328 \log (\log (12))+2916 \log ^2(\log (12))}{1-1454 x+528531 x^2-1454 x^3+x^4+\left (-4+2904 x+2904 x^2-4 x^3\right ) \log (\log (12))+\left (6-1446 x+6 x^2\right ) \log ^2(\log (12))+(-4-4 x) \log ^3(\log (12))+\log ^4(\log (12))} \, dx=\frac {4 (5+x)}{-x+\frac {1}{729} (1+x-\log (\log (12)))^2} \]
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Time = 0.12 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.36, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.043, Rules used = {1694, 12, 1828, 8} \[ \int \frac {10602576-29160 x-2916 x^2+23328 \log (\log (12))+2916 \log ^2(\log (12))}{1-1454 x+528531 x^2-1454 x^3+x^4+\left (-4+2904 x+2904 x^2-4 x^3\right ) \log (\log (12))+\left (6-1446 x+6 x^2\right ) \log ^2(\log (12))+(-4-4 x) \log ^3(\log (12))+\log ^4(\log (12))} \, dx=\frac {11664 (x+5)}{4 \left (x+\frac {1}{4} (-1454-4 \log (\log (12)))\right )^2-729 (725+4 \log (\log (12)))} \]
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Rule 8
Rule 12
Rule 1694
Rule 1828
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {11664 \left (-4 x^2-4 x (737+2 \log (\log (12)))-729 (725+4 \log (\log (12)))\right )}{\left (4 x^2-729 (725+4 \log (\log (12)))\right )^2} \, dx,x,x+\frac {1}{4} (-1454-4 \log (\log (12)))\right ) \\ & = 11664 \text {Subst}\left (\int \frac {-4 x^2-4 x (737+2 \log (\log (12)))-729 (725+4 \log (\log (12)))}{\left (4 x^2-729 (725+4 \log (\log (12)))\right )^2} \, dx,x,x+\frac {1}{4} (-1454-4 \log (\log (12)))\right ) \\ & = \frac {11664 (5+x)}{(-727+2 x-2 \log (\log (12)))^2-729 (725+4 \log (\log (12)))}+\frac {8 \text {Subst}\left (\int 0 \, dx,x,x+\frac {1}{4} (-1454-4 \log (\log (12)))\right )}{725+4 \log (\log (12))} \\ & = \frac {11664 (5+x)}{(-727+2 x-2 \log (\log (12)))^2-729 (725+4 \log (\log (12)))} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {10602576-29160 x-2916 x^2+23328 \log (\log (12))+2916 \log ^2(\log (12))}{1-1454 x+528531 x^2-1454 x^3+x^4+\left (-4+2904 x+2904 x^2-4 x^3\right ) \log (\log (12))+\left (6-1446 x+6 x^2\right ) \log ^2(\log (12))+(-4-4 x) \log ^3(\log (12))+\log ^4(\log (12))} \, dx=\frac {2916 (5+x)}{x^2+(-1+\log (\log (12)))^2-x (727+2 \log (\log (12)))} \]
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Time = 0.09 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.28
method | result | size |
gosper | \(\frac {2916 x +14580}{\ln \left (\ln \left (12\right )\right )^{2}-2 x \ln \left (\ln \left (12\right )\right )+x^{2}-2 \ln \left (\ln \left (12\right )\right )-727 x +1}\) | \(32\) |
default | \(\frac {2916 x +14580}{\ln \left (\ln \left (12\right )\right )^{2}-2 x \ln \left (\ln \left (12\right )\right )+x^{2}-2 \ln \left (\ln \left (12\right )\right )-727 x +1}\) | \(32\) |
norman | \(\frac {2916 x +14580}{\ln \left (\ln \left (12\right )\right )^{2}-2 x \ln \left (\ln \left (12\right )\right )+x^{2}-2 \ln \left (\ln \left (12\right )\right )-727 x +1}\) | \(33\) |
parallelrisch | \(\frac {2916 x +14580}{\ln \left (\ln \left (12\right )\right )^{2}-2 x \ln \left (\ln \left (12\right )\right )+x^{2}-2 \ln \left (\ln \left (12\right )\right )-727 x +1}\) | \(33\) |
risch | \(\frac {2916 x +14580}{\ln \left (\ln \left (3\right )+2 \ln \left (2\right )\right )^{2}-2 x \ln \left (\ln \left (3\right )+2 \ln \left (2\right )\right )+x^{2}-2 \ln \left (\ln \left (3\right )+2 \ln \left (2\right )\right )-727 x +1}\) | \(48\) |
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Time = 0.24 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {10602576-29160 x-2916 x^2+23328 \log (\log (12))+2916 \log ^2(\log (12))}{1-1454 x+528531 x^2-1454 x^3+x^4+\left (-4+2904 x+2904 x^2-4 x^3\right ) \log (\log (12))+\left (6-1446 x+6 x^2\right ) \log ^2(\log (12))+(-4-4 x) \log ^3(\log (12))+\log ^4(\log (12))} \, dx=\frac {2916 \, {\left (x + 5\right )}}{x^{2} - 2 \, {\left (x + 1\right )} \log \left (\log \left (12\right )\right ) + \log \left (\log \left (12\right )\right )^{2} - 727 \, x + 1} \]
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Time = 0.41 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.48 \[ \int \frac {10602576-29160 x-2916 x^2+23328 \log (\log (12))+2916 \log ^2(\log (12))}{1-1454 x+528531 x^2-1454 x^3+x^4+\left (-4+2904 x+2904 x^2-4 x^3\right ) \log (\log (12))+\left (6-1446 x+6 x^2\right ) \log ^2(\log (12))+(-4-4 x) \log ^3(\log (12))+\log ^4(\log (12))} \, dx=- \frac {- 2916 x - 14580}{x^{2} + x \left (-727 - 2 \log {\left (\log {\left (12 \right )} \right )}\right ) - 2 \log {\left (\log {\left (12 \right )} \right )} + \log {\left (\log {\left (12 \right )} \right )}^{2} + 1} \]
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Time = 0.20 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.28 \[ \int \frac {10602576-29160 x-2916 x^2+23328 \log (\log (12))+2916 \log ^2(\log (12))}{1-1454 x+528531 x^2-1454 x^3+x^4+\left (-4+2904 x+2904 x^2-4 x^3\right ) \log (\log (12))+\left (6-1446 x+6 x^2\right ) \log ^2(\log (12))+(-4-4 x) \log ^3(\log (12))+\log ^4(\log (12))} \, dx=\frac {2916 \, {\left (x + 5\right )}}{x^{2} - x {\left (2 \, \log \left (\log \left (12\right )\right ) + 727\right )} + \log \left (\log \left (12\right )\right )^{2} - 2 \, \log \left (\log \left (12\right )\right ) + 1} \]
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Time = 0.25 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.24 \[ \int \frac {10602576-29160 x-2916 x^2+23328 \log (\log (12))+2916 \log ^2(\log (12))}{1-1454 x+528531 x^2-1454 x^3+x^4+\left (-4+2904 x+2904 x^2-4 x^3\right ) \log (\log (12))+\left (6-1446 x+6 x^2\right ) \log ^2(\log (12))+(-4-4 x) \log ^3(\log (12))+\log ^4(\log (12))} \, dx=\frac {2916 \, {\left (x + 5\right )}}{x^{2} - 2 \, x \log \left (\log \left (12\right )\right ) + \log \left (\log \left (12\right )\right )^{2} - 727 \, x - 2 \, \log \left (\log \left (12\right )\right ) + 1} \]
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Time = 0.21 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.32 \[ \int \frac {10602576-29160 x-2916 x^2+23328 \log (\log (12))+2916 \log ^2(\log (12))}{1-1454 x+528531 x^2-1454 x^3+x^4+\left (-4+2904 x+2904 x^2-4 x^3\right ) \log (\log (12))+\left (6-1446 x+6 x^2\right ) \log ^2(\log (12))+(-4-4 x) \log ^3(\log (12))+\log ^4(\log (12))} \, dx=\frac {2916\,x+14580}{x^2+\left (-2\,\ln \left (\ln \left (12\right )\right )-727\right )\,x-2\,\ln \left (\ln \left (12\right )\right )+{\ln \left (\ln \left (12\right )\right )}^2+1} \]
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