Integrand size = 89, antiderivative size = 32 \[ \int \frac {27-18 x-24 x^2+12 x^3+8 x^4-2 x^5-x^6+e^{\frac {4 x+4 x^2}{-3+x+x^2}} \left (12 x^2+24 x^3\right )}{9 x^2-6 x^3-5 x^4+2 x^5+x^6} \, dx=-e^{\frac {4 x}{x-\frac {3}{1+x}}}+\frac {-3+(2-x) x}{x} \]
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\[ \int \frac {27-18 x-24 x^2+12 x^3+8 x^4-2 x^5-x^6+e^{\frac {4 x+4 x^2}{-3+x+x^2}} \left (12 x^2+24 x^3\right )}{9 x^2-6 x^3-5 x^4+2 x^5+x^6} \, dx=\int \frac {27-18 x-24 x^2+12 x^3+8 x^4-2 x^5-x^6+e^{\frac {4 x+4 x^2}{-3+x+x^2}} \left (12 x^2+24 x^3\right )}{9 x^2-6 x^3-5 x^4+2 x^5+x^6} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {27-18 x-24 x^2+12 x^3+8 x^4-2 x^5-x^6+e^{\frac {4 x+4 x^2}{-3+x+x^2}} \left (12 x^2+24 x^3\right )}{x^2 \left (3-x-x^2\right )^2} \, dx \\ & = \int \left (-\frac {24}{\left (-3+x+x^2\right )^2}+\frac {27}{x^2 \left (-3+x+x^2\right )^2}-\frac {18}{x \left (-3+x+x^2\right )^2}+\frac {12 x}{\left (-3+x+x^2\right )^2}+\frac {8 x^2}{\left (-3+x+x^2\right )^2}-\frac {2 x^3}{\left (-3+x+x^2\right )^2}-\frac {x^4}{\left (-3+x+x^2\right )^2}+\frac {12 e^{\frac {4 x (1+x)}{-3+x+x^2}} (1+2 x)}{\left (-3+x+x^2\right )^2}\right ) \, dx \\ & = -\left (2 \int \frac {x^3}{\left (-3+x+x^2\right )^2} \, dx\right )+8 \int \frac {x^2}{\left (-3+x+x^2\right )^2} \, dx+12 \int \frac {x}{\left (-3+x+x^2\right )^2} \, dx+12 \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}} (1+2 x)}{\left (-3+x+x^2\right )^2} \, dx-18 \int \frac {1}{x \left (-3+x+x^2\right )^2} \, dx-24 \int \frac {1}{\left (-3+x+x^2\right )^2} \, dx+27 \int \frac {1}{x^2 \left (-3+x+x^2\right )^2} \, dx-\int \frac {x^4}{\left (-3+x+x^2\right )^2} \, dx \\ & = \frac {12 (6-x)}{13 \left (3-x-x^2\right )}+\frac {8 (6-x) x}{13 \left (3-x-x^2\right )}-\frac {2 (6-x) x^2}{13 \left (3-x-x^2\right )}-\frac {(6-x) x^3}{13 \left (3-x-x^2\right )}-\frac {6 (7+x)}{13 \left (3-x-x^2\right )}+\frac {9 (7+x)}{13 x \left (3-x-x^2\right )}-\frac {24 (1+2 x)}{13 \left (3-x-x^2\right )}+\frac {1}{13} \int \frac {x^2 (-18+2 x)}{-3+x+x^2} \, dx+\frac {2}{13} \int \frac {(-12+x) x}{-3+x+x^2} \, dx-\frac {6}{13} \int \frac {-13-x}{x \left (-3+x+x^2\right )} \, dx+\frac {9}{13} \int \frac {-20-2 x}{x^2 \left (-3+x+x^2\right )} \, dx+\frac {12}{13} \int \frac {1}{-3+x+x^2} \, dx+2 \left (\frac {48}{13} \int \frac {1}{-3+x+x^2} \, dx\right )+12 \int \left (\frac {e^{\frac {4 x (1+x)}{-3+x+x^2}}}{\left (-3+x+x^2\right )^2}+\frac {2 e^{\frac {4 x (1+x)}{-3+x+x^2}} x}{\left (-3+x+x^2\right )^2}\right ) \, dx \\ & = \frac {2 x}{13}+\frac {12 (6-x)}{13 \left (3-x-x^2\right )}+\frac {8 (6-x) x}{13 \left (3-x-x^2\right )}-\frac {2 (6-x) x^2}{13 \left (3-x-x^2\right )}-\frac {(6-x) x^3}{13 \left (3-x-x^2\right )}-\frac {6 (7+x)}{13 \left (3-x-x^2\right )}+\frac {9 (7+x)}{13 x \left (3-x-x^2\right )}-\frac {24 (1+2 x)}{13 \left (3-x-x^2\right )}+\frac {1}{13} \int \left (-20+2 x-\frac {2 (30-13 x)}{-3+x+x^2}\right ) \, dx+\frac {2}{13} \int \frac {3-13 x}{-3+x+x^2} \, dx-\frac {6}{13} \int \left (\frac {13}{3 x}+\frac {-16-13 x}{3 \left (-3+x+x^2\right )}\right ) \, dx+\frac {9}{13} \int \left (\frac {20}{3 x^2}+\frac {26}{9 x}-\frac {2 (43+13 x)}{9 \left (-3+x+x^2\right )}\right ) \, dx-\frac {24}{13} \text {Subst}\left (\int \frac {1}{13-x^2} \, dx,x,1+2 x\right )-2 \left (\frac {96}{13} \text {Subst}\left (\int \frac {1}{13-x^2} \, dx,x,1+2 x\right )\right )+12 \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}}}{\left (-3+x+x^2\right )^2} \, dx+24 \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}} x}{\left (-3+x+x^2\right )^2} \, dx \\ & = -\frac {60}{13 x}-\frac {18 x}{13}+\frac {x^2}{13}+\frac {12 (6-x)}{13 \left (3-x-x^2\right )}+\frac {8 (6-x) x}{13 \left (3-x-x^2\right )}-\frac {2 (6-x) x^2}{13 \left (3-x-x^2\right )}-\frac {(6-x) x^3}{13 \left (3-x-x^2\right )}-\frac {6 (7+x)}{13 \left (3-x-x^2\right )}+\frac {9 (7+x)}{13 x \left (3-x-x^2\right )}-\frac {24 (1+2 x)}{13 \left (3-x-x^2\right )}-\frac {216 \tanh ^{-1}\left (\frac {1+2 x}{\sqrt {13}}\right )}{13 \sqrt {13}}-\frac {2}{13} \int \frac {-16-13 x}{-3+x+x^2} \, dx-\frac {2}{13} \int \frac {30-13 x}{-3+x+x^2} \, dx-\frac {2}{13} \int \frac {43+13 x}{-3+x+x^2} \, dx+12 \int \left (\frac {4 e^{\frac {4 x (1+x)}{-3+x+x^2}}}{13 \left (-1+\sqrt {13}-2 x\right )^2}+\frac {4 e^{\frac {4 x (1+x)}{-3+x+x^2}}}{13 \sqrt {13} \left (-1+\sqrt {13}-2 x\right )}+\frac {4 e^{\frac {4 x (1+x)}{-3+x+x^2}}}{13 \left (1+\sqrt {13}+2 x\right )^2}+\frac {4 e^{\frac {4 x (1+x)}{-3+x+x^2}}}{13 \sqrt {13} \left (1+\sqrt {13}+2 x\right )}\right ) \, dx+24 \int \left (\frac {2 \left (-1+\sqrt {13}\right ) e^{\frac {4 x (1+x)}{-3+x+x^2}}}{13 \left (-1+\sqrt {13}-2 x\right )^2}-\frac {2 e^{\frac {4 x (1+x)}{-3+x+x^2}}}{13 \sqrt {13} \left (-1+\sqrt {13}-2 x\right )}+\frac {2 \left (-1-\sqrt {13}\right ) e^{\frac {4 x (1+x)}{-3+x+x^2}}}{13 \left (1+\sqrt {13}+2 x\right )^2}-\frac {2 e^{\frac {4 x (1+x)}{-3+x+x^2}}}{13 \sqrt {13} \left (1+\sqrt {13}+2 x\right )}\right ) \, dx+\frac {1}{169} \left (-169+19 \sqrt {13}\right ) \int \frac {1}{\frac {1}{2}-\frac {\sqrt {13}}{2}+x} \, dx-\frac {1}{169} \left (169+19 \sqrt {13}\right ) \int \frac {1}{\frac {1}{2}+\frac {\sqrt {13}}{2}+x} \, dx \\ & = -\frac {60}{13 x}-\frac {18 x}{13}+\frac {x^2}{13}+\frac {12 (6-x)}{13 \left (3-x-x^2\right )}+\frac {8 (6-x) x}{13 \left (3-x-x^2\right )}-\frac {2 (6-x) x^2}{13 \left (3-x-x^2\right )}-\frac {(6-x) x^3}{13 \left (3-x-x^2\right )}-\frac {6 (7+x)}{13 \left (3-x-x^2\right )}+\frac {9 (7+x)}{13 x \left (3-x-x^2\right )}-\frac {24 (1+2 x)}{13 \left (3-x-x^2\right )}-\frac {216 \tanh ^{-1}\left (\frac {1+2 x}{\sqrt {13}}\right )}{13 \sqrt {13}}-\frac {1}{169} \left (169-19 \sqrt {13}\right ) \log \left (1-\sqrt {13}+2 x\right )-\frac {1}{169} \left (169+19 \sqrt {13}\right ) \log \left (1+\sqrt {13}+2 x\right )+\frac {48}{13} \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}}}{\left (-1+\sqrt {13}-2 x\right )^2} \, dx+\frac {48}{13} \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}}}{\left (1+\sqrt {13}+2 x\right )^2} \, dx-\frac {1}{169} \left (169-73 \sqrt {13}\right ) \int \frac {1}{\frac {1}{2}+\frac {\sqrt {13}}{2}+x} \, dx-\frac {1}{13} \left (48 \left (1-\sqrt {13}\right )\right ) \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}}}{\left (-1+\sqrt {13}-2 x\right )^2} \, dx-\frac {1}{13} \left (48 \left (1+\sqrt {13}\right )\right ) \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}}}{\left (1+\sqrt {13}+2 x\right )^2} \, dx-\frac {1}{169} \left (-169+19 \sqrt {13}\right ) \int \frac {1}{\frac {1}{2}+\frac {\sqrt {13}}{2}+x} \, dx+\frac {1}{169} \left (169+19 \sqrt {13}\right ) \int \frac {1}{\frac {1}{2}-\frac {\sqrt {13}}{2}+x} \, dx-\frac {1}{169} \left (-169+73 \sqrt {13}\right ) \int \frac {1}{\frac {1}{2}-\frac {\sqrt {13}}{2}+x} \, dx-\frac {1}{169} \left (169+73 \sqrt {13}\right ) \int \frac {1}{\frac {1}{2}-\frac {\sqrt {13}}{2}+x} \, dx+\frac {1}{169} \left (169+73 \sqrt {13}\right ) \int \frac {1}{\frac {1}{2}+\frac {\sqrt {13}}{2}+x} \, dx \\ & = -\frac {60}{13 x}-\frac {18 x}{13}+\frac {x^2}{13}+\frac {12 (6-x)}{13 \left (3-x-x^2\right )}+\frac {8 (6-x) x}{13 \left (3-x-x^2\right )}-\frac {2 (6-x) x^2}{13 \left (3-x-x^2\right )}-\frac {(6-x) x^3}{13 \left (3-x-x^2\right )}-\frac {6 (7+x)}{13 \left (3-x-x^2\right )}+\frac {9 (7+x)}{13 x \left (3-x-x^2\right )}-\frac {24 (1+2 x)}{13 \left (3-x-x^2\right )}-\frac {216 \tanh ^{-1}\left (\frac {1+2 x}{\sqrt {13}}\right )}{13 \sqrt {13}}+\frac {1}{169} \left (169-73 \sqrt {13}\right ) \log \left (1-\sqrt {13}+2 x\right )-\frac {1}{169} \left (169-19 \sqrt {13}\right ) \log \left (1-\sqrt {13}+2 x\right )+\frac {1}{169} \left (169+19 \sqrt {13}\right ) \log \left (1-\sqrt {13}+2 x\right )-\frac {1}{169} \left (169+73 \sqrt {13}\right ) \log \left (1-\sqrt {13}+2 x\right )-\frac {1}{169} \left (169-73 \sqrt {13}\right ) \log \left (1+\sqrt {13}+2 x\right )+\frac {1}{169} \left (169-19 \sqrt {13}\right ) \log \left (1+\sqrt {13}+2 x\right )-\frac {1}{169} \left (169+19 \sqrt {13}\right ) \log \left (1+\sqrt {13}+2 x\right )+\frac {1}{169} \left (169+73 \sqrt {13}\right ) \log \left (1+\sqrt {13}+2 x\right )+\frac {48}{13} \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}}}{\left (-1+\sqrt {13}-2 x\right )^2} \, dx+\frac {48}{13} \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}}}{\left (1+\sqrt {13}+2 x\right )^2} \, dx-\frac {1}{13} \left (48 \left (1-\sqrt {13}\right )\right ) \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}}}{\left (-1+\sqrt {13}-2 x\right )^2} \, dx-\frac {1}{13} \left (48 \left (1+\sqrt {13}\right )\right ) \int \frac {e^{\frac {4 x (1+x)}{-3+x+x^2}}}{\left (1+\sqrt {13}+2 x\right )^2} \, dx \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.78 \[ \int \frac {27-18 x-24 x^2+12 x^3+8 x^4-2 x^5-x^6+e^{\frac {4 x+4 x^2}{-3+x+x^2}} \left (12 x^2+24 x^3\right )}{9 x^2-6 x^3-5 x^4+2 x^5+x^6} \, dx=-e^{4+\frac {12}{-3+x+x^2}}-\frac {3}{x}-x \]
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Time = 0.48 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.84
method | result | size |
risch | \(-x -\frac {3}{x}-{\mathrm e}^{\frac {4 \left (1+x \right ) x}{x^{2}+x -3}}\) | \(27\) |
parts | \(-x -\frac {3}{x}-{\mathrm e}^{\frac {1}{\frac {1}{12} x^{2}+\frac {1}{12} x -\frac {1}{4}}+4}\) | \(27\) |
parallelrisch | \(-\frac {x^{2}+x \,{\mathrm e}^{\frac {4 x^{2}+4 x}{x^{2}+x -3}}+3-4 x}{x}\) | \(35\) |
norman | \(\frac {9-6 x +x^{2}-x^{4}+3 x \,{\mathrm e}^{\frac {4 x^{2}+4 x}{x^{2}+x -3}}-x^{2} {\mathrm e}^{\frac {4 x^{2}+4 x}{x^{2}+x -3}}-x^{3} {\mathrm e}^{\frac {4 x^{2}+4 x}{x^{2}+x -3}}}{x \left (x^{2}+x -3\right )}\) | \(96\) |
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Time = 0.25 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.88 \[ \int \frac {27-18 x-24 x^2+12 x^3+8 x^4-2 x^5-x^6+e^{\frac {4 x+4 x^2}{-3+x+x^2}} \left (12 x^2+24 x^3\right )}{9 x^2-6 x^3-5 x^4+2 x^5+x^6} \, dx=-\frac {x^{2} + x e^{\left (\frac {4 \, {\left (x^{2} + x\right )}}{x^{2} + x - 3}\right )} + 3}{x} \]
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Time = 0.10 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.69 \[ \int \frac {27-18 x-24 x^2+12 x^3+8 x^4-2 x^5-x^6+e^{\frac {4 x+4 x^2}{-3+x+x^2}} \left (12 x^2+24 x^3\right )}{9 x^2-6 x^3-5 x^4+2 x^5+x^6} \, dx=- x - e^{\frac {4 x^{2} + 4 x}{x^{2} + x - 3}} - \frac {3}{x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 129 vs. \(2 (30) = 60\).
Time = 0.36 (sec) , antiderivative size = 129, normalized size of antiderivative = 4.03 \[ \int \frac {27-18 x-24 x^2+12 x^3+8 x^4-2 x^5-x^6+e^{\frac {4 x+4 x^2}{-3+x+x^2}} \left (12 x^2+24 x^3\right )}{9 x^2-6 x^3-5 x^4+2 x^5+x^6} \, dx=-x - \frac {3 \, {\left (20 \, x^{2} + 23 \, x - 39\right )}}{13 \, {\left (x^{3} + x^{2} - 3 \, x\right )}} + \frac {31 \, x - 30}{13 \, {\left (x^{2} + x - 3\right )}} - \frac {2 \, {\left (10 \, x - 21\right )}}{13 \, {\left (x^{2} + x - 3\right )}} - \frac {8 \, {\left (7 \, x - 3\right )}}{13 \, {\left (x^{2} + x - 3\right )}} + \frac {24 \, {\left (2 \, x + 1\right )}}{13 \, {\left (x^{2} + x - 3\right )}} + \frac {6 \, {\left (x + 7\right )}}{13 \, {\left (x^{2} + x - 3\right )}} + \frac {12 \, {\left (x - 6\right )}}{13 \, {\left (x^{2} + x - 3\right )}} - e^{\left (\frac {12}{x^{2} + x - 3} + 4\right )} \]
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Time = 0.28 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.16 \[ \int \frac {27-18 x-24 x^2+12 x^3+8 x^4-2 x^5-x^6+e^{\frac {4 x+4 x^2}{-3+x+x^2}} \left (12 x^2+24 x^3\right )}{9 x^2-6 x^3-5 x^4+2 x^5+x^6} \, dx=-x - \frac {3}{x} - e^{\left (\frac {4 \, x^{2}}{x^{2} + x - 3} + \frac {4 \, x}{x^{2} + x - 3}\right )} \]
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Time = 9.66 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.16 \[ \int \frac {27-18 x-24 x^2+12 x^3+8 x^4-2 x^5-x^6+e^{\frac {4 x+4 x^2}{-3+x+x^2}} \left (12 x^2+24 x^3\right )}{9 x^2-6 x^3-5 x^4+2 x^5+x^6} \, dx=-x-{\mathrm {e}}^{\frac {4\,x}{x^2+x-3}}\,{\mathrm {e}}^{\frac {4\,x^2}{x^2+x-3}}-\frac {3}{x} \]
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