Integrand size = 59, antiderivative size = 23 \[ \int \frac {12 x+16 x^2+e^x \left (-2 x^2+2 x^3\right )}{9+48 x+64 x^2+e^{2 x} x^2+e^x \left (-6 x-16 x^2\right )} \, dx=\frac {2 x^2}{x+\left (7-e^x+\frac {3}{x}\right ) x} \]
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\[ \int \frac {12 x+16 x^2+e^x \left (-2 x^2+2 x^3\right )}{9+48 x+64 x^2+e^{2 x} x^2+e^x \left (-6 x-16 x^2\right )} \, dx=\int \frac {12 x+16 x^2+e^x \left (-2 x^2+2 x^3\right )}{9+48 x+64 x^2+e^{2 x} x^2+e^x \left (-6 x-16 x^2\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {2 x \left (6-\left (-8+e^x\right ) x+e^x x^2\right )}{\left (3-\left (-8+e^x\right ) x\right )^2} \, dx \\ & = 2 \int \frac {x \left (6-\left (-8+e^x\right ) x+e^x x^2\right )}{\left (3-\left (-8+e^x\right ) x\right )^2} \, dx \\ & = 2 \int \left (\frac {(-1+x) x}{-3-8 x+e^x x}+\frac {x \left (3+3 x+8 x^2\right )}{\left (-3-8 x+e^x x\right )^2}\right ) \, dx \\ & = 2 \int \frac {(-1+x) x}{-3-8 x+e^x x} \, dx+2 \int \frac {x \left (3+3 x+8 x^2\right )}{\left (-3-8 x+e^x x\right )^2} \, dx \\ & = 2 \int \left (\frac {3 x}{\left (-3-8 x+e^x x\right )^2}+\frac {3 x^2}{\left (-3-8 x+e^x x\right )^2}+\frac {8 x^3}{\left (-3-8 x+e^x x\right )^2}\right ) \, dx+2 \int \left (-\frac {x}{-3-8 x+e^x x}+\frac {x^2}{-3-8 x+e^x x}\right ) \, dx \\ & = -\left (2 \int \frac {x}{-3-8 x+e^x x} \, dx\right )+2 \int \frac {x^2}{-3-8 x+e^x x} \, dx+6 \int \frac {x}{\left (-3-8 x+e^x x\right )^2} \, dx+6 \int \frac {x^2}{\left (-3-8 x+e^x x\right )^2} \, dx+16 \int \frac {x^3}{\left (-3-8 x+e^x x\right )^2} \, dx \\ \end{align*}
Time = 1.05 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.74 \[ \int \frac {12 x+16 x^2+e^x \left (-2 x^2+2 x^3\right )}{9+48 x+64 x^2+e^{2 x} x^2+e^x \left (-6 x-16 x^2\right )} \, dx=-\frac {2 x^2}{-3-8 x+e^x x} \]
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Time = 0.04 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.74
method | result | size |
norman | \(-\frac {2 x^{2}}{{\mathrm e}^{x} x -8 x -3}\) | \(17\) |
risch | \(-\frac {2 x^{2}}{{\mathrm e}^{x} x -8 x -3}\) | \(17\) |
parallelrisch | \(-\frac {2 x^{2}}{{\mathrm e}^{x} x -8 x -3}\) | \(17\) |
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Time = 0.25 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.70 \[ \int \frac {12 x+16 x^2+e^x \left (-2 x^2+2 x^3\right )}{9+48 x+64 x^2+e^{2 x} x^2+e^x \left (-6 x-16 x^2\right )} \, dx=-\frac {2 \, x^{2}}{x e^{x} - 8 \, x - 3} \]
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Time = 0.09 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.65 \[ \int \frac {12 x+16 x^2+e^x \left (-2 x^2+2 x^3\right )}{9+48 x+64 x^2+e^{2 x} x^2+e^x \left (-6 x-16 x^2\right )} \, dx=- \frac {2 x^{2}}{x e^{x} - 8 x - 3} \]
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Time = 0.24 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.70 \[ \int \frac {12 x+16 x^2+e^x \left (-2 x^2+2 x^3\right )}{9+48 x+64 x^2+e^{2 x} x^2+e^x \left (-6 x-16 x^2\right )} \, dx=-\frac {2 \, x^{2}}{x e^{x} - 8 \, x - 3} \]
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Time = 0.25 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.70 \[ \int \frac {12 x+16 x^2+e^x \left (-2 x^2+2 x^3\right )}{9+48 x+64 x^2+e^{2 x} x^2+e^x \left (-6 x-16 x^2\right )} \, dx=-\frac {2 \, x^{2}}{x e^{x} - 8 \, x - 3} \]
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Time = 9.16 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.74 \[ \int \frac {12 x+16 x^2+e^x \left (-2 x^2+2 x^3\right )}{9+48 x+64 x^2+e^{2 x} x^2+e^x \left (-6 x-16 x^2\right )} \, dx=\frac {2\,x^2}{8\,x-x\,{\mathrm {e}}^x+3} \]
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