Integrand size = 135, antiderivative size = 31 \[ \int \frac {e^{-\frac {e^5+5 x}{x}} \left (4 e^{5+4 e^{-\frac {e^5+5 x}{x}}}+e^{\frac {e^5+5 x}{x}} \left (2 x^2-2 x^3-6 x^4+4 x^5\right )+e^{2 e^{-\frac {e^5+5 x}{x}}} \left (e^5 \left (4+4 x-4 x^2\right )+e^{\frac {e^5+5 x}{x}} \left (2 x^2-4 x^3\right )\right )\right )}{x^2} \, dx=-2+e^4+\left (1+e^{2 e^{-5-\frac {e^5}{x}}}+x-x^2\right )^2 \]
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Time = 0.60 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.84, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.022, Rules used = {6820, 12, 6818} \[ \int \frac {e^{-\frac {e^5+5 x}{x}} \left (4 e^{5+4 e^{-\frac {e^5+5 x}{x}}}+e^{\frac {e^5+5 x}{x}} \left (2 x^2-2 x^3-6 x^4+4 x^5\right )+e^{2 e^{-\frac {e^5+5 x}{x}}} \left (e^5 \left (4+4 x-4 x^2\right )+e^{\frac {e^5+5 x}{x}} \left (2 x^2-4 x^3\right )\right )\right )}{x^2} \, dx=\left (-x^2+x+e^{2 e^{-\frac {e^5}{x}-5}}+1\right )^2 \]
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Rule 12
Rule 6818
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \int \frac {2 e^{-\frac {e^5}{x}} \left (1+e^{2 e^{-5-\frac {e^5}{x}}}+x-x^2\right ) \left (2 e^{2 e^{-5-\frac {e^5}{x}}}+e^{\frac {e^5}{x}} \left (x^2-2 x^3\right )\right )}{x^2} \, dx \\ & = 2 \int \frac {e^{-\frac {e^5}{x}} \left (1+e^{2 e^{-5-\frac {e^5}{x}}}+x-x^2\right ) \left (2 e^{2 e^{-5-\frac {e^5}{x}}}+e^{\frac {e^5}{x}} \left (x^2-2 x^3\right )\right )}{x^2} \, dx \\ & = \left (1+e^{2 e^{-5-\frac {e^5}{x}}}+x-x^2\right )^2 \\ \end{align*}
Time = 0.41 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.84 \[ \int \frac {e^{-\frac {e^5+5 x}{x}} \left (4 e^{5+4 e^{-\frac {e^5+5 x}{x}}}+e^{\frac {e^5+5 x}{x}} \left (2 x^2-2 x^3-6 x^4+4 x^5\right )+e^{2 e^{-\frac {e^5+5 x}{x}}} \left (e^5 \left (4+4 x-4 x^2\right )+e^{\frac {e^5+5 x}{x}} \left (2 x^2-4 x^3\right )\right )\right )}{x^2} \, dx=\left (1+e^{2 e^{-5-\frac {e^5}{x}}}+x-x^2\right )^2 \]
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Time = 1.39 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.71
method | result | size |
risch | \(\left (x^{2}-x -1\right )^{2}+{\mathrm e}^{4 \,{\mathrm e}^{-\frac {{\mathrm e}^{5}+5 x}{x}}}+\left (-2 x^{2}+2 x +2\right ) {\mathrm e}^{2 \,{\mathrm e}^{-\frac {{\mathrm e}^{5}+5 x}{x}}}\) | \(53\) |
parallelrisch | \(-\frac {-x^{5}+2 x^{4}+2 \,{\mathrm e}^{2 \,{\mathrm e}^{-\frac {{\mathrm e}^{5}+5 x}{x}}} x^{3}+x^{3}-2 \,{\mathrm e}^{2 \,{\mathrm e}^{-\frac {{\mathrm e}^{5}+5 x}{x}}} x^{2}-x \,{\mathrm e}^{4 \,{\mathrm e}^{-\frac {{\mathrm e}^{5}+5 x}{x}}}-2 x^{2}-2 \,{\mathrm e}^{2 \,{\mathrm e}^{-\frac {{\mathrm e}^{5}+5 x}{x}}} x}{x}\) | \(107\) |
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Time = 0.26 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.84 \[ \int \frac {e^{-\frac {e^5+5 x}{x}} \left (4 e^{5+4 e^{-\frac {e^5+5 x}{x}}}+e^{\frac {e^5+5 x}{x}} \left (2 x^2-2 x^3-6 x^4+4 x^5\right )+e^{2 e^{-\frac {e^5+5 x}{x}}} \left (e^5 \left (4+4 x-4 x^2\right )+e^{\frac {e^5+5 x}{x}} \left (2 x^2-4 x^3\right )\right )\right )}{x^2} \, dx=x^{4} - 2 \, x^{3} - x^{2} - 2 \, {\left (x^{2} - x - 1\right )} e^{\left (2 \, e^{\left (-\frac {5 \, x + e^{5}}{x}\right )}\right )} + 2 \, x + e^{\left (4 \, e^{\left (-\frac {5 \, x + e^{5}}{x}\right )}\right )} \]
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Time = 3.93 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.65 \[ \int \frac {e^{-\frac {e^5+5 x}{x}} \left (4 e^{5+4 e^{-\frac {e^5+5 x}{x}}}+e^{\frac {e^5+5 x}{x}} \left (2 x^2-2 x^3-6 x^4+4 x^5\right )+e^{2 e^{-\frac {e^5+5 x}{x}}} \left (e^5 \left (4+4 x-4 x^2\right )+e^{\frac {e^5+5 x}{x}} \left (2 x^2-4 x^3\right )\right )\right )}{x^2} \, dx=x^{4} - 2 x^{3} - x^{2} + 2 x + \left (- 2 x^{2} + 2 x + 2\right ) e^{2 e^{- \frac {5 x + e^{5}}{x}}} + e^{4 e^{- \frac {5 x + e^{5}}{x}}} \]
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\[ \int \frac {e^{-\frac {e^5+5 x}{x}} \left (4 e^{5+4 e^{-\frac {e^5+5 x}{x}}}+e^{\frac {e^5+5 x}{x}} \left (2 x^2-2 x^3-6 x^4+4 x^5\right )+e^{2 e^{-\frac {e^5+5 x}{x}}} \left (e^5 \left (4+4 x-4 x^2\right )+e^{\frac {e^5+5 x}{x}} \left (2 x^2-4 x^3\right )\right )\right )}{x^2} \, dx=\int { -\frac {2 \, {\left ({\left (2 \, {\left (x^{2} - x - 1\right )} e^{5} + {\left (2 \, x^{3} - x^{2}\right )} e^{\left (\frac {5 \, x + e^{5}}{x}\right )}\right )} e^{\left (2 \, e^{\left (-\frac {5 \, x + e^{5}}{x}\right )}\right )} - {\left (2 \, x^{5} - 3 \, x^{4} - x^{3} + x^{2}\right )} e^{\left (\frac {5 \, x + e^{5}}{x}\right )} - 2 \, e^{\left (4 \, e^{\left (-\frac {5 \, x + e^{5}}{x}\right )} + 5\right )}\right )} e^{\left (-\frac {5 \, x + e^{5}}{x}\right )}}{x^{2}} \,d x } \]
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\[ \int \frac {e^{-\frac {e^5+5 x}{x}} \left (4 e^{5+4 e^{-\frac {e^5+5 x}{x}}}+e^{\frac {e^5+5 x}{x}} \left (2 x^2-2 x^3-6 x^4+4 x^5\right )+e^{2 e^{-\frac {e^5+5 x}{x}}} \left (e^5 \left (4+4 x-4 x^2\right )+e^{\frac {e^5+5 x}{x}} \left (2 x^2-4 x^3\right )\right )\right )}{x^2} \, dx=\int { -\frac {2 \, {\left ({\left (2 \, {\left (x^{2} - x - 1\right )} e^{5} + {\left (2 \, x^{3} - x^{2}\right )} e^{\left (\frac {5 \, x + e^{5}}{x}\right )}\right )} e^{\left (2 \, e^{\left (-\frac {5 \, x + e^{5}}{x}\right )}\right )} - {\left (2 \, x^{5} - 3 \, x^{4} - x^{3} + x^{2}\right )} e^{\left (\frac {5 \, x + e^{5}}{x}\right )} - 2 \, e^{\left (4 \, e^{\left (-\frac {5 \, x + e^{5}}{x}\right )} + 5\right )}\right )} e^{\left (-\frac {5 \, x + e^{5}}{x}\right )}}{x^{2}} \,d x } \]
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Timed out. \[ \int \frac {e^{-\frac {e^5+5 x}{x}} \left (4 e^{5+4 e^{-\frac {e^5+5 x}{x}}}+e^{\frac {e^5+5 x}{x}} \left (2 x^2-2 x^3-6 x^4+4 x^5\right )+e^{2 e^{-\frac {e^5+5 x}{x}}} \left (e^5 \left (4+4 x-4 x^2\right )+e^{\frac {e^5+5 x}{x}} \left (2 x^2-4 x^3\right )\right )\right )}{x^2} \, dx=\int \frac {{\mathrm {e}}^{-\frac {5\,x+{\mathrm {e}}^5}{x}}\,\left ({\mathrm {e}}^{2\,{\mathrm {e}}^{-\frac {5\,x+{\mathrm {e}}^5}{x}}}\,\left ({\mathrm {e}}^5\,\left (-4\,x^2+4\,x+4\right )+{\mathrm {e}}^{\frac {5\,x+{\mathrm {e}}^5}{x}}\,\left (2\,x^2-4\,x^3\right )\right )+4\,{\mathrm {e}}^5\,{\mathrm {e}}^{4\,{\mathrm {e}}^{-\frac {5\,x+{\mathrm {e}}^5}{x}}}+{\mathrm {e}}^{\frac {5\,x+{\mathrm {e}}^5}{x}}\,\left (4\,x^5-6\,x^4-2\,x^3+2\,x^2\right )\right )}{x^2} \,d x \]
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