Integrand size = 38, antiderivative size = 20 \[ \int \frac {-1-x-x^2+\left (-1-2 x-3 x^2\right ) \log (x)}{\left (x+x^2+x^3\right ) \log (x)} \, dx=4+\log \left (\frac {4}{x \left (1+x+x^2\right ) \log (x)}\right ) \]
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Time = 0.17 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.95, number of steps used = 8, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {1608, 6860, 1642, 642, 2339, 29} \[ \int \frac {-1-x-x^2+\left (-1-2 x-3 x^2\right ) \log (x)}{\left (x+x^2+x^3\right ) \log (x)} \, dx=-\log \left (x^2+x+1\right )-\log (x)-\log (\log (x)) \]
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Rule 29
Rule 642
Rule 1608
Rule 1642
Rule 2339
Rule 6860
Rubi steps \begin{align*} \text {integral}& = \int \frac {-1-x-x^2+\left (-1-2 x-3 x^2\right ) \log (x)}{x \left (1+x+x^2\right ) \log (x)} \, dx \\ & = \int \left (\frac {-1-2 x-3 x^2}{x \left (1+x+x^2\right )}-\frac {1}{x \log (x)}\right ) \, dx \\ & = \int \frac {-1-2 x-3 x^2}{x \left (1+x+x^2\right )} \, dx-\int \frac {1}{x \log (x)} \, dx \\ & = \int \left (-\frac {1}{x}+\frac {-1-2 x}{1+x+x^2}\right ) \, dx-\text {Subst}\left (\int \frac {1}{x} \, dx,x,\log (x)\right ) \\ & = -\log (x)-\log (\log (x))+\int \frac {-1-2 x}{1+x+x^2} \, dx \\ & = -\log (x)-\log \left (1+x+x^2\right )-\log (\log (x)) \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.95 \[ \int \frac {-1-x-x^2+\left (-1-2 x-3 x^2\right ) \log (x)}{\left (x+x^2+x^3\right ) \log (x)} \, dx=-\log (x)-\log \left (1+x+x^2\right )-\log (\log (x)) \]
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Time = 0.08 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.90
method | result | size |
default | \(-\ln \left (\ln \left (x \right )\right )-\ln \left (x \left (x^{2}+x +1\right )\right )\) | \(18\) |
risch | \(-\ln \left (x^{3}+x^{2}+x \right )-\ln \left (\ln \left (x \right )\right )\) | \(18\) |
parts | \(-\ln \left (\ln \left (x \right )\right )-\ln \left (x \left (x^{2}+x +1\right )\right )\) | \(18\) |
norman | \(-\ln \left (x \right )-\ln \left (\ln \left (x \right )\right )-\ln \left (x^{2}+x +1\right )\) | \(20\) |
parallelrisch | \(-\ln \left (x \right )-\ln \left (\ln \left (x \right )\right )-\ln \left (x^{2}+x +1\right )\) | \(20\) |
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Time = 0.25 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.85 \[ \int \frac {-1-x-x^2+\left (-1-2 x-3 x^2\right ) \log (x)}{\left (x+x^2+x^3\right ) \log (x)} \, dx=-\log \left (x^{3} + x^{2} + x\right ) - \log \left (\log \left (x\right )\right ) \]
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Time = 0.07 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.75 \[ \int \frac {-1-x-x^2+\left (-1-2 x-3 x^2\right ) \log (x)}{\left (x+x^2+x^3\right ) \log (x)} \, dx=- \log {\left (x^{3} + x^{2} + x \right )} - \log {\left (\log {\left (x \right )} \right )} \]
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Time = 0.23 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.95 \[ \int \frac {-1-x-x^2+\left (-1-2 x-3 x^2\right ) \log (x)}{\left (x+x^2+x^3\right ) \log (x)} \, dx=-\log \left (x^{2} + x + 1\right ) - \log \left (x\right ) - \log \left (\log \left (x\right )\right ) \]
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Time = 0.26 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.95 \[ \int \frac {-1-x-x^2+\left (-1-2 x-3 x^2\right ) \log (x)}{\left (x+x^2+x^3\right ) \log (x)} \, dx=-\log \left (x^{2} + x + 1\right ) - \log \left (x\right ) - \log \left (\log \left (x\right )\right ) \]
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Time = 10.07 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.85 \[ \int \frac {-1-x-x^2+\left (-1-2 x-3 x^2\right ) \log (x)}{\left (x+x^2+x^3\right ) \log (x)} \, dx=-\ln \left (\ln \left (x\right )\,\left (x^2+x+1\right )\right )-\ln \left (x\right ) \]
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