Integrand size = 112, antiderivative size = 28 \[ \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{18 x^2-48 x^3+32 x^4} \, dx=e^{-3 e^{\left .-\frac {3}{2}\right /x}+x}-\frac {10 x^2}{-\frac {3}{4}+x} \]
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\[ \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{18 x^2-48 x^3+32 x^4} \, dx=\int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{18 x^2-48 x^3+32 x^4} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{x^2 \left (18-48 x+32 x^2\right )} \, dx \\ & = \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{2 x^2 (-3+4 x)^2} \, dx \\ & = \frac {1}{2} \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{x^2 (-3+4 x)^2} \, dx \\ & = \frac {1}{2} \int \left (2 e^{-3 e^{\left .-\frac {3}{2}\right /x}+x}-\frac {9 e^{-3 e^{\left .-\frac {3}{2}\right /x}-\frac {3}{2 x}+x}}{x^2}+\frac {160 (3-2 x) x}{(3-4 x)^2}\right ) \, dx \\ & = -\left (\frac {9}{2} \int \frac {e^{-3 e^{\left .-\frac {3}{2}\right /x}-\frac {3}{2 x}+x}}{x^2} \, dx\right )+80 \int \frac {(3-2 x) x}{(3-4 x)^2} \, dx+\int e^{-3 e^{\left .-\frac {3}{2}\right /x}+x} \, dx \\ & = \frac {40 x^2}{3-4 x}-\frac {9}{2} \int \frac {e^{-3 e^{\left .-\frac {3}{2}\right /x}-\frac {3}{2 x}+x}}{x^2} \, dx+\int e^{-3 e^{\left .-\frac {3}{2}\right /x}+x} \, dx \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.07 \[ \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{18 x^2-48 x^3+32 x^4} \, dx=e^{-3 e^{\left .-\frac {3}{2}\right /x}+x}-10 x-\frac {45}{2 (-3+4 x)} \]
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Time = 0.31 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.07
method | result | size |
risch | \(-10 x -\frac {45}{8 \left (x -\frac {3}{4}\right )}+{\mathrm e}^{\left (x \,{\mathrm e}^{\frac {3}{2 x}}-3\right ) {\mathrm e}^{-\frac {3}{2 x}}}\) | \(30\) |
parts | \({\mathrm e}^{\left (x \,{\mathrm e}^{\frac {3}{2 x}}-3\right ) {\mathrm e}^{-\frac {3}{2 x}}}-10 x -\frac {45}{2 \left (-3+4 x \right )}\) | \(34\) |
parallelrisch | \(\frac {-2880 x^{3}+288 \,{\mathrm e}^{\left (x \,{\mathrm e}^{\frac {3}{2 x}}-3\right ) {\mathrm e}^{-\frac {3}{2 x}}} x^{2}-216 \,{\mathrm e}^{\left (x \,{\mathrm e}^{\frac {3}{2 x}}-3\right ) {\mathrm e}^{-\frac {3}{2 x}}} x}{72 x \left (-3+4 x \right )}\) | \(67\) |
norman | \(\frac {\left (-40 \,{\mathrm e}^{\frac {3}{2 x}} x^{3}+4 x^{2} {\mathrm e}^{\left (x \,{\mathrm e}^{\frac {3}{2 x}}-3\right ) {\mathrm e}^{-\frac {3}{2 x}}} {\mathrm e}^{\frac {3}{2 x}}-3 \,{\mathrm e}^{\frac {3}{2 x}} {\mathrm e}^{\left (x \,{\mathrm e}^{\frac {3}{2 x}}-3\right ) {\mathrm e}^{-\frac {3}{2 x}}} x \right ) {\mathrm e}^{-\frac {3}{2 x}}}{x \left (-3+4 x \right )}\) | \(92\) |
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Time = 0.25 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.57 \[ \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{18 x^2-48 x^3+32 x^4} \, dx=-\frac {80 \, x^{2} - 2 \, {\left (4 \, x - 3\right )} e^{\left ({\left (x e^{\left (\frac {3}{2 \, x}\right )} - 3\right )} e^{\left (-\frac {3}{2 \, x}\right )}\right )} - 60 \, x + 45}{2 \, {\left (4 \, x - 3\right )}} \]
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Time = 0.19 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.96 \[ \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{18 x^2-48 x^3+32 x^4} \, dx=- 10 x + e^{\left (x e^{\frac {3}{2 x}} - 3\right ) e^{- \frac {3}{2 x}}} - \frac {45}{8 x - 6} \]
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\[ \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{18 x^2-48 x^3+32 x^4} \, dx=\int { -\frac {{\left ({\left (144 \, x^{2} - 2 \, {\left (16 \, x^{4} - 24 \, x^{3} + 9 \, x^{2}\right )} e^{\left (\frac {3}{2 \, x}\right )} - 216 \, x + 81\right )} e^{\left ({\left (x e^{\left (\frac {3}{2 \, x}\right )} - 3\right )} e^{\left (-\frac {3}{2 \, x}\right )}\right )} + 160 \, {\left (2 \, x^{4} - 3 \, x^{3}\right )} e^{\left (\frac {3}{2 \, x}\right )}\right )} e^{\left (-\frac {3}{2 \, x}\right )}}{2 \, {\left (16 \, x^{4} - 24 \, x^{3} + 9 \, x^{2}\right )}} \,d x } \]
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\[ \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{18 x^2-48 x^3+32 x^4} \, dx=\int { -\frac {{\left ({\left (144 \, x^{2} - 2 \, {\left (16 \, x^{4} - 24 \, x^{3} + 9 \, x^{2}\right )} e^{\left (\frac {3}{2 \, x}\right )} - 216 \, x + 81\right )} e^{\left ({\left (x e^{\left (\frac {3}{2 \, x}\right )} - 3\right )} e^{\left (-\frac {3}{2 \, x}\right )}\right )} + 160 \, {\left (2 \, x^{4} - 3 \, x^{3}\right )} e^{\left (\frac {3}{2 \, x}\right )}\right )} e^{\left (-\frac {3}{2 \, x}\right )}}{2 \, {\left (16 \, x^{4} - 24 \, x^{3} + 9 \, x^{2}\right )}} \,d x } \]
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Time = 9.99 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.89 \[ \int \frac {e^{\left .-\frac {3}{2}\right /x} \left (e^{\left .\frac {3}{2}\right /x} \left (480 x^3-320 x^4\right )+e^{e^{\left .-\frac {3}{2}\right /x} \left (-3+e^{\left .\frac {3}{2}\right /x} x\right )} \left (-81+216 x-144 x^2+e^{\left .\frac {3}{2}\right /x} \left (18 x^2-48 x^3+32 x^4\right )\right )\right )}{18 x^2-48 x^3+32 x^4} \, dx={\mathrm {e}}^{-\frac {3}{{\left ({\mathrm {e}}^{1/x}\right )}^{3/2}}}\,{\mathrm {e}}^x-\frac {45}{8\,\left (x-\frac {3}{4}\right )}-10\,x \]
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