Integrand size = 68, antiderivative size = 26 \[ \int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{\left (20-20 x+5 x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx=\frac {1}{5} x \left (-5+\frac {2 \left (-2 x+\log \left (\log \left (\log \left (x^2\right )\right )\right )\right )}{2-x}\right ) \]
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\[ \int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{\left (20-20 x+5 x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx=\int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{\left (20-20 x+5 x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{5 (-2+x)^2 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx \\ & = \frac {1}{5} \int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{(-2+x)^2 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx \\ & = \frac {1}{5} \int \left (\frac {8-4 x-20 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 x \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )-x^2 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )}{(-2+x)^2 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )}+\frac {4 \log \left (\log \left (\log \left (x^2\right )\right )\right )}{(-2+x)^2}\right ) \, dx \\ & = \frac {1}{5} \int \frac {8-4 x-20 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 x \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )-x^2 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )}{(-2+x)^2 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx+\frac {4}{5} \int \frac {\log \left (\log \left (\log \left (x^2\right )\right )\right )}{(-2+x)^2} \, dx \\ & = \frac {1}{5} \int \frac {8-4 x-\left (20-4 x+x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )}{(2-x)^2 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx+\frac {4}{5} \int \frac {\log \left (\log \left (\log \left (x^2\right )\right )\right )}{(-2+x)^2} \, dx \\ & = \frac {1}{5} \int \left (\frac {-20+4 x-x^2}{(-2+x)^2}-\frac {4}{(-2+x) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )}\right ) \, dx+\frac {4}{5} \int \frac {\log \left (\log \left (\log \left (x^2\right )\right )\right )}{(-2+x)^2} \, dx \\ & = \frac {1}{5} \int \frac {-20+4 x-x^2}{(-2+x)^2} \, dx-\frac {4}{5} \int \frac {1}{(-2+x) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx+\frac {4}{5} \int \frac {\log \left (\log \left (\log \left (x^2\right )\right )\right )}{(-2+x)^2} \, dx \\ & = \frac {1}{5} \int \left (-1-\frac {16}{(-2+x)^2}\right ) \, dx-\frac {4}{5} \int \frac {1}{(-2+x) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx+\frac {4}{5} \int \frac {\log \left (\log \left (\log \left (x^2\right )\right )\right )}{(-2+x)^2} \, dx \\ & = -\frac {16}{5 (2-x)}-\frac {x}{5}-\frac {4}{5} \int \frac {1}{(-2+x) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx+\frac {4}{5} \int \frac {\log \left (\log \left (\log \left (x^2\right )\right )\right )}{(-2+x)^2} \, dx \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.00 \[ \int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{\left (20-20 x+5 x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx=-\frac {-16-2 x+x^2+2 x \log \left (\log \left (\log \left (x^2\right )\right )\right )}{5 (-2+x)} \]
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Time = 2.23 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.92
method | result | size |
parallelrisch | \(\frac {40-4 \ln \left (\ln \left (\ln \left (x^{2}\right )\right )\right ) x -2 x^{2}}{10 x -20}\) | \(24\) |
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Time = 0.27 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.92 \[ \int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{\left (20-20 x+5 x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx=-\frac {x^{2} + 2 \, x \log \left (\log \left (\log \left (x^{2}\right )\right )\right ) - 2 \, x - 16}{5 \, {\left (x - 2\right )}} \]
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Time = 0.26 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.38 \[ \int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{\left (20-20 x+5 x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx=- \frac {x}{5} - \frac {2 \log {\left (\log {\left (\log {\left (x^{2} \right )} \right )} \right )}}{5} - \frac {4 \log {\left (\log {\left (\log {\left (x^{2} \right )} \right )} \right )}}{5 x - 10} + \frac {16}{5 x - 10} \]
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Time = 0.32 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.96 \[ \int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{\left (20-20 x+5 x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx=-\frac {x^{2} + 2 \, x \log \left (\log \left (2\right ) + \log \left (\log \left (x\right )\right )\right ) - 2 \, x - 16}{5 \, {\left (x - 2\right )}} \]
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Time = 0.36 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.23 \[ \int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{\left (20-20 x+5 x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx=-\frac {1}{5} \, x - \frac {4 \, \log \left (\log \left (\log \left (x^{2}\right )\right )\right )}{5 \, {\left (x - 2\right )}} + \frac {16}{5 \, {\left (x - 2\right )}} - \frac {2}{5} \, \log \left (\log \left (\log \left (x^{2}\right )\right )\right ) \]
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Time = 8.85 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.77 \[ \int \frac {8-4 x+\left (-20+4 x-x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )+4 \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right ) \log \left (\log \left (\log \left (x^2\right )\right )\right )}{\left (20-20 x+5 x^2\right ) \log \left (x^2\right ) \log \left (\log \left (x^2\right )\right )} \, dx=\frac {16}{5\,\left (x-2\right )}-\frac {2\,\ln \left (\ln \left (\ln \left (x^2\right )\right )\right )}{5}-\frac {x}{5}+\frac {\ln \left (\ln \left (\ln \left (x^2\right )\right )\right )\,\left (8\,x-4\,x^2\right )}{5\,x\,{\left (x-2\right )}^2} \]
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