Integrand size = 106, antiderivative size = 22 \[ \int \frac {-2 x^4+2 e^{1+x} x^4+\left (12 x^3-4 e^{1+x} x^3+4 x^4\right ) \log \left (-3+e^{1+x}-x\right )+\left (e^{1+2 x}+e^x (-3-x)\right ) \log ^3\left (-3+e^{1+x}-x\right )}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx=e^x-\frac {x^4}{\log ^2\left (-3+e^{1+x}-x\right )} \]
[Out]
\[ \int \frac {-2 x^4+2 e^{1+x} x^4+\left (12 x^3-4 e^{1+x} x^3+4 x^4\right ) \log \left (-3+e^{1+x}-x\right )+\left (e^{1+2 x}+e^x (-3-x)\right ) \log ^3\left (-3+e^{1+x}-x\right )}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx=\int \frac {-2 x^4+2 e^{1+x} x^4+\left (12 x^3-4 e^{1+x} x^3+4 x^4\right ) \log \left (-3+e^{1+x}-x\right )+\left (e^{1+2 x}+e^x (-3-x)\right ) \log ^3\left (-3+e^{1+x}-x\right )}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = \int \left (e^x+\frac {2 \left (-1+e^{1+x}\right ) x^4}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )}-\frac {4 x^3}{\log ^2\left (-3+e^{1+x}-x\right )}\right ) \, dx \\ & = 2 \int \frac {\left (-1+e^{1+x}\right ) x^4}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx-4 \int \frac {x^3}{\log ^2\left (-3+e^{1+x}-x\right )} \, dx+\int e^x \, dx \\ & = e^x+2 \int \left (\frac {x^4}{\log ^3\left (-3+e^{1+x}-x\right )}+\frac {x^4 (2+x)}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )}\right ) \, dx-4 \int \frac {x^3}{\log ^2\left (-3+e^{1+x}-x\right )} \, dx \\ & = e^x+2 \int \frac {x^4}{\log ^3\left (-3+e^{1+x}-x\right )} \, dx+2 \int \frac {x^4 (2+x)}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx-4 \int \frac {x^3}{\log ^2\left (-3+e^{1+x}-x\right )} \, dx \\ & = e^x+2 \int \left (\frac {2 x^4}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )}+\frac {x^5}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )}\right ) \, dx+2 \int \frac {x^4}{\log ^3\left (-3+e^{1+x}-x\right )} \, dx-4 \int \frac {x^3}{\log ^2\left (-3+e^{1+x}-x\right )} \, dx \\ & = e^x+2 \int \frac {x^4}{\log ^3\left (-3+e^{1+x}-x\right )} \, dx+2 \int \frac {x^5}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx+4 \int \frac {x^4}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx-4 \int \frac {x^3}{\log ^2\left (-3+e^{1+x}-x\right )} \, dx \\ \end{align*}
Time = 0.34 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00 \[ \int \frac {-2 x^4+2 e^{1+x} x^4+\left (12 x^3-4 e^{1+x} x^3+4 x^4\right ) \log \left (-3+e^{1+x}-x\right )+\left (e^{1+2 x}+e^x (-3-x)\right ) \log ^3\left (-3+e^{1+x}-x\right )}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx=e^x-\frac {x^4}{\log ^2\left (-3+e^{1+x}-x\right )} \]
[In]
[Out]
Time = 0.49 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.95
method | result | size |
risch | \({\mathrm e}^{x}-\frac {x^{4}}{\ln \left ({\mathrm e}^{1+x}-3-x \right )^{2}}\) | \(21\) |
parallelrisch | \(\frac {-2 x^{4}+2 \,{\mathrm e}^{x} \ln \left ({\mathrm e}^{1+x}-3-x \right )^{2}}{2 \ln \left ({\mathrm e}^{1+x}-3-x \right )^{2}}\) | \(37\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 41 vs. \(2 (20) = 40\).
Time = 0.26 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.86 \[ \int \frac {-2 x^4+2 e^{1+x} x^4+\left (12 x^3-4 e^{1+x} x^3+4 x^4\right ) \log \left (-3+e^{1+x}-x\right )+\left (e^{1+2 x}+e^x (-3-x)\right ) \log ^3\left (-3+e^{1+x}-x\right )}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx=-\frac {{\left (x^{4} e - e^{\left (x + 1\right )} \log \left (-x + e^{\left (x + 1\right )} - 3\right )^{2}\right )} e^{\left (-1\right )}}{\log \left (-x + e^{\left (x + 1\right )} - 3\right )^{2}} \]
[In]
[Out]
Time = 0.12 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86 \[ \int \frac {-2 x^4+2 e^{1+x} x^4+\left (12 x^3-4 e^{1+x} x^3+4 x^4\right ) \log \left (-3+e^{1+x}-x\right )+\left (e^{1+2 x}+e^x (-3-x)\right ) \log ^3\left (-3+e^{1+x}-x\right )}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx=- \frac {x^{4}}{\log {\left (- x + e e^{x} - 3 \right )}^{2}} + e^{x} \]
[In]
[Out]
none
Time = 0.26 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.55 \[ \int \frac {-2 x^4+2 e^{1+x} x^4+\left (12 x^3-4 e^{1+x} x^3+4 x^4\right ) \log \left (-3+e^{1+x}-x\right )+\left (e^{1+2 x}+e^x (-3-x)\right ) \log ^3\left (-3+e^{1+x}-x\right )}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx=-\frac {x^{4} - e^{x} \log \left (-x + e^{\left (x + 1\right )} - 3\right )^{2}}{\log \left (-x + e^{\left (x + 1\right )} - 3\right )^{2}} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 70 vs. \(2 (20) = 40\).
Time = 0.28 (sec) , antiderivative size = 70, normalized size of antiderivative = 3.18 \[ \int \frac {-2 x^4+2 e^{1+x} x^4+\left (12 x^3-4 e^{1+x} x^3+4 x^4\right ) \log \left (-3+e^{1+x}-x\right )+\left (e^{1+2 x}+e^x (-3-x)\right ) \log ^3\left (-3+e^{1+x}-x\right )}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx=-\frac {{\left ({\left (x + 1\right )}^{4} e - 4 \, {\left (x + 1\right )}^{3} e + 6 \, {\left (x + 1\right )}^{2} e - e^{\left (x + 1\right )} \log \left (-x + e^{\left (x + 1\right )} - 3\right )^{2} - 4 \, {\left (x + 1\right )} e + e\right )} e^{\left (-1\right )}}{\log \left (-x + e^{\left (x + 1\right )} - 3\right )^{2}} \]
[In]
[Out]
Time = 0.68 (sec) , antiderivative size = 274, normalized size of antiderivative = 12.45 \[ \int \frac {-2 x^4+2 e^{1+x} x^4+\left (12 x^3-4 e^{1+x} x^3+4 x^4\right ) \log \left (-3+e^{1+x}-x\right )+\left (e^{1+2 x}+e^x (-3-x)\right ) \log ^3\left (-3+e^{1+x}-x\right )}{\left (-3+e^{1+x}-x\right ) \log ^3\left (-3+e^{1+x}-x\right )} \, dx={\mathrm {e}}^x-\frac {x^4+\frac {2\,x^3\,\ln \left (\mathrm {e}\,{\mathrm {e}}^x-x-3\right )\,\left (x-{\mathrm {e}}^{x+1}+3\right )}{{\mathrm {e}}^{x+1}-1}}{{\ln \left (\mathrm {e}\,{\mathrm {e}}^x-x-3\right )}^2}+\frac {\frac {2\,x^3\,\left (x-{\mathrm {e}}^{x+1}+3\right )}{{\mathrm {e}}^{x+1}-1}-\frac {2\,x^2\,\ln \left (\mathrm {e}\,{\mathrm {e}}^x-x-3\right )\,\left (x-{\mathrm {e}}^{x+1}+3\right )\,\left (4\,x-12\,{\mathrm {e}}^{x+1}+3\,{\mathrm {e}}^{2\,x+2}-2\,x\,{\mathrm {e}}^{x+1}+x^2\,{\mathrm {e}}^{x+1}+9\right )}{{\left ({\mathrm {e}}^{x+1}-1\right )}^3}}{\ln \left (\mathrm {e}\,{\mathrm {e}}^x-x-3\right )}-6\,x^2-\frac {2\,{\mathrm {e}}^{-1}\,\left (-x^4+5\,x^3+12\,x^2\right )}{{\mathrm {e}}^{-1}-{\mathrm {e}}^x}-\frac {2\,{\mathrm {e}}^{-2}\,\left (-x^5+x^4+12\,x^3+12\,x^2\right )}{{\mathrm {e}}^{2\,x}-2\,{\mathrm {e}}^{x-1}+{\mathrm {e}}^{-2}}+\frac {2\,{\mathrm {e}}^{-3}\,\left (x^5+4\,x^4+4\,x^3\right )}{{\mathrm {e}}^{3\,x}+3\,{\mathrm {e}}^{x-2}-{\mathrm {e}}^{-3}-3\,{\mathrm {e}}^{2\,x-1}} \]
[In]
[Out]