Integrand size = 138, antiderivative size = 29 \[ \int \frac {e^4 x+e^{\frac {256-32 x^2+x^4}{e^4}} \left (e^4 (-4+x)-256 x^2+64 x^3+16 x^4-4 x^5\right )+e^4 (4-x) \log (4-x)}{e^{5+\frac {2 \left (256-32 x^2+x^4\right )}{e^4}} (-4+x)+e^{5+\frac {256-32 x^2+x^4}{e^4}} (8-2 x) \log (4-x)+e^5 (-4+x) \log ^2(4-x)} \, dx=\frac {x}{e \left (e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)\right )} \]
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\[ \int \frac {e^4 x+e^{\frac {256-32 x^2+x^4}{e^4}} \left (e^4 (-4+x)-256 x^2+64 x^3+16 x^4-4 x^5\right )+e^4 (4-x) \log (4-x)}{e^{5+\frac {2 \left (256-32 x^2+x^4\right )}{e^4}} (-4+x)+e^{5+\frac {256-32 x^2+x^4}{e^4}} (8-2 x) \log (4-x)+e^5 (-4+x) \log ^2(4-x)} \, dx=\int \frac {e^4 x+e^{\frac {256-32 x^2+x^4}{e^4}} \left (e^4 (-4+x)-256 x^2+64 x^3+16 x^4-4 x^5\right )+e^4 (4-x) \log (4-x)}{e^{5+\frac {2 \left (256-32 x^2+x^4\right )}{e^4}} (-4+x)+e^{5+\frac {256-32 x^2+x^4}{e^4}} (8-2 x) \log (4-x)+e^5 (-4+x) \log ^2(4-x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{-5+\frac {64 x^2}{e^4}} \left (-e^4 x-e^{\frac {256-32 x^2+x^4}{e^4}} \left (e^4 (-4+x)-256 x^2+64 x^3+16 x^4-4 x^5\right )-e^4 (4-x) \log (4-x)\right )}{(4-x) \left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx \\ & = \int \left (\frac {e^{-5+\frac {64 x^2}{e^4}} \left (e^4+64 x^2-4 x^4\right )}{e^{\frac {\left (16+x^2\right )^2}{e^4}}-e^{\frac {64 x^2}{e^4}} \log (4-x)}-\frac {e^{-5+\frac {64 x^2}{e^4}} x \left (-e^4+256 x \log (4-x)-64 x^2 \log (4-x)-16 x^3 \log (4-x)+4 x^4 \log (4-x)\right )}{(-4+x) \left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}\right ) \, dx \\ & = \int \frac {e^{-5+\frac {64 x^2}{e^4}} \left (e^4+64 x^2-4 x^4\right )}{e^{\frac {\left (16+x^2\right )^2}{e^4}}-e^{\frac {64 x^2}{e^4}} \log (4-x)} \, dx-\int \frac {e^{-5+\frac {64 x^2}{e^4}} x \left (-e^4+256 x \log (4-x)-64 x^2 \log (4-x)-16 x^3 \log (4-x)+4 x^4 \log (4-x)\right )}{(-4+x) \left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx \\ & = \int \frac {e^4+64 x^2-4 x^4}{e^5 \left (e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)\right )} \, dx-\int \frac {e^{-5+\frac {64 x^2}{e^4}} x \left (e^4-4 (-4+x)^2 x (4+x) \log (4-x)\right )}{(4-x) \left (e^{\frac {256+x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx \\ & = \frac {\int \frac {e^4+64 x^2-4 x^4}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)} \, dx}{e^5}-\int \left (\frac {e^{-5+\frac {64 x^2}{e^4}} \left (-e^4+256 x \log (4-x)-64 x^2 \log (4-x)-16 x^3 \log (4-x)+4 x^4 \log (4-x)\right )}{\left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}+\frac {4 e^{-5+\frac {64 x^2}{e^4}} \left (-e^4+256 x \log (4-x)-64 x^2 \log (4-x)-16 x^3 \log (4-x)+4 x^4 \log (4-x)\right )}{(-4+x) \left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}\right ) \, dx \\ & = -\left (4 \int \frac {e^{-5+\frac {64 x^2}{e^4}} \left (-e^4+256 x \log (4-x)-64 x^2 \log (4-x)-16 x^3 \log (4-x)+4 x^4 \log (4-x)\right )}{(-4+x) \left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx\right )+\frac {\int \left (\frac {e^4}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)}+\frac {64 x^2}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)}-\frac {4 x^4}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)}\right ) \, dx}{e^5}-\int \frac {e^{-5+\frac {64 x^2}{e^4}} \left (-e^4+256 x \log (4-x)-64 x^2 \log (4-x)-16 x^3 \log (4-x)+4 x^4 \log (4-x)\right )}{\left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx \\ & = -\left (4 \int \frac {e^{-5+\frac {64 x^2}{e^4}} \left (e^4-4 (-4+x)^2 x (4+x) \log (4-x)\right )}{(4-x) \left (e^{\frac {256+x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx\right )-\frac {4 \int \frac {x^4}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)} \, dx}{e^5}+\frac {64 \int \frac {x^2}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)} \, dx}{e^5}+\frac {\int \frac {1}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)} \, dx}{e}-\int \frac {e^{-5+\frac {64 x^2}{e^4}} \left (-e^4+4 (-4+x)^2 x (4+x) \log (4-x)\right )}{\left (e^{\frac {256+x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx \\ & = -\left (4 \int \left (-\frac {e^{-1+\frac {64 x^2}{e^4}}}{(-4+x) \left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}+\frac {256 e^{-5+\frac {64 x^2}{e^4}} x \log (4-x)}{(-4+x) \left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}-\frac {64 e^{-5+\frac {64 x^2}{e^4}} x^2 \log (4-x)}{(-4+x) \left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}-\frac {16 e^{-5+\frac {64 x^2}{e^4}} x^3 \log (4-x)}{(-4+x) \left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}+\frac {4 e^{-5+\frac {64 x^2}{e^4}} x^4 \log (4-x)}{(-4+x) \left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}\right ) \, dx\right )-\frac {4 \int \frac {x^4}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)} \, dx}{e^5}+\frac {64 \int \frac {x^2}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)} \, dx}{e^5}+\frac {\int \frac {1}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)} \, dx}{e}-\int \left (-\frac {e^{-1+\frac {64 x^2}{e^4}}}{\left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}+\frac {256 e^{-5+\frac {64 x^2}{e^4}} x \log (4-x)}{\left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}-\frac {64 e^{-5+\frac {64 x^2}{e^4}} x^2 \log (4-x)}{\left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}-\frac {16 e^{-5+\frac {64 x^2}{e^4}} x^3 \log (4-x)}{\left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}+\frac {4 e^{-5+\frac {64 x^2}{e^4}} x^4 \log (4-x)}{\left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2}\right ) \, dx \\ & = 4 \int \frac {e^{-1+\frac {64 x^2}{e^4}}}{(-4+x) \left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx-4 \int \frac {e^{-5+\frac {64 x^2}{e^4}} x^4 \log (4-x)}{\left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx+16 \int \frac {e^{-5+\frac {64 x^2}{e^4}} x^3 \log (4-x)}{\left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx-16 \int \frac {e^{-5+\frac {64 x^2}{e^4}} x^4 \log (4-x)}{(-4+x) \left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx+64 \int \frac {e^{-5+\frac {64 x^2}{e^4}} x^2 \log (4-x)}{\left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx+64 \int \frac {e^{-5+\frac {64 x^2}{e^4}} x^3 \log (4-x)}{(-4+x) \left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx-256 \int \frac {e^{-5+\frac {64 x^2}{e^4}} x \log (4-x)}{\left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx+256 \int \frac {e^{-5+\frac {64 x^2}{e^4}} x^2 \log (4-x)}{(-4+x) \left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx-1024 \int \frac {e^{-5+\frac {64 x^2}{e^4}} x \log (4-x)}{(-4+x) \left (-e^{\frac {256}{e^4}+\frac {x^4}{e^4}}+e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx-\frac {4 \int \frac {x^4}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)} \, dx}{e^5}+\frac {64 \int \frac {x^2}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)} \, dx}{e^5}+\frac {\int \frac {1}{e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)} \, dx}{e}+\int \frac {e^{-1+\frac {64 x^2}{e^4}}}{\left (e^{\frac {256}{e^4}+\frac {x^4}{e^4}}-e^{\frac {32 x^2}{e^4}} \log (4-x)\right )^2} \, dx \\ & = \text {Too large to display} \\ \end{align*}
Time = 0.25 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00 \[ \int \frac {e^4 x+e^{\frac {256-32 x^2+x^4}{e^4}} \left (e^4 (-4+x)-256 x^2+64 x^3+16 x^4-4 x^5\right )+e^4 (4-x) \log (4-x)}{e^{5+\frac {2 \left (256-32 x^2+x^4\right )}{e^4}} (-4+x)+e^{5+\frac {256-32 x^2+x^4}{e^4}} (8-2 x) \log (4-x)+e^5 (-4+x) \log ^2(4-x)} \, dx=\frac {x}{e \left (e^{\frac {\left (-16+x^2\right )^2}{e^4}}-\log (4-x)\right )} \]
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Time = 1.81 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.03
method | result | size |
risch | \(\frac {{\mathrm e}^{-1} x}{{\mathrm e}^{\left (x -4\right )^{2} \left (4+x \right )^{2} {\mathrm e}^{-4}}-\ln \left (-x +4\right )}\) | \(30\) |
parallelrisch | \(-\frac {x \,{\mathrm e}^{-1}}{\ln \left (-x +4\right )-{\mathrm e}^{\left (x^{4}-32 x^{2}+256\right ) {\mathrm e}^{-4}}}\) | \(35\) |
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Time = 0.25 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.28 \[ \int \frac {e^4 x+e^{\frac {256-32 x^2+x^4}{e^4}} \left (e^4 (-4+x)-256 x^2+64 x^3+16 x^4-4 x^5\right )+e^4 (4-x) \log (4-x)}{e^{5+\frac {2 \left (256-32 x^2+x^4\right )}{e^4}} (-4+x)+e^{5+\frac {256-32 x^2+x^4}{e^4}} (8-2 x) \log (4-x)+e^5 (-4+x) \log ^2(4-x)} \, dx=-\frac {x e^{4}}{e^{5} \log \left (-x + 4\right ) - e^{\left ({\left (x^{4} - 32 \, x^{2} + 5 \, e^{4} + 256\right )} e^{\left (-4\right )}\right )}} \]
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Time = 0.14 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.93 \[ \int \frac {e^4 x+e^{\frac {256-32 x^2+x^4}{e^4}} \left (e^4 (-4+x)-256 x^2+64 x^3+16 x^4-4 x^5\right )+e^4 (4-x) \log (4-x)}{e^{5+\frac {2 \left (256-32 x^2+x^4\right )}{e^4}} (-4+x)+e^{5+\frac {256-32 x^2+x^4}{e^4}} (8-2 x) \log (4-x)+e^5 (-4+x) \log ^2(4-x)} \, dx=\frac {x}{e e^{\frac {x^{4} - 32 x^{2} + 256}{e^{4}}} - e \log {\left (4 - x \right )}} \]
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Time = 0.43 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.59 \[ \int \frac {e^4 x+e^{\frac {256-32 x^2+x^4}{e^4}} \left (e^4 (-4+x)-256 x^2+64 x^3+16 x^4-4 x^5\right )+e^4 (4-x) \log (4-x)}{e^{5+\frac {2 \left (256-32 x^2+x^4\right )}{e^4}} (-4+x)+e^{5+\frac {256-32 x^2+x^4}{e^4}} (8-2 x) \log (4-x)+e^5 (-4+x) \log ^2(4-x)} \, dx=-\frac {x e^{\left (32 \, x^{2} e^{\left (-4\right )}\right )}}{e^{\left (32 \, x^{2} e^{\left (-4\right )} + 1\right )} \log \left (-x + 4\right ) - e^{\left (x^{4} e^{\left (-4\right )} + 256 \, e^{\left (-4\right )} + 1\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 926 vs. \(2 (26) = 52\).
Time = 1.20 (sec) , antiderivative size = 926, normalized size of antiderivative = 31.93 \[ \int \frac {e^4 x+e^{\frac {256-32 x^2+x^4}{e^4}} \left (e^4 (-4+x)-256 x^2+64 x^3+16 x^4-4 x^5\right )+e^4 (4-x) \log (4-x)}{e^{5+\frac {2 \left (256-32 x^2+x^4\right )}{e^4}} (-4+x)+e^{5+\frac {256-32 x^2+x^4}{e^4}} (8-2 x) \log (4-x)+e^5 (-4+x) \log ^2(4-x)} \, dx=\text {Too large to display} \]
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Time = 9.85 (sec) , antiderivative size = 158, normalized size of antiderivative = 5.45 \[ \int \frac {e^4 x+e^{\frac {256-32 x^2+x^4}{e^4}} \left (e^4 (-4+x)-256 x^2+64 x^3+16 x^4-4 x^5\right )+e^4 (4-x) \log (4-x)}{e^{5+\frac {2 \left (256-32 x^2+x^4\right )}{e^4}} (-4+x)+e^{5+\frac {256-32 x^2+x^4}{e^4}} (8-2 x) \log (4-x)+e^5 (-4+x) \log ^2(4-x)} \, dx=\frac {x\,{\mathrm {e}}^{-1}\,{\left (4\,{\mathrm {e}}^4-x\,{\mathrm {e}}^4\right )}^2-{\mathrm {e}}^{-5}\,\ln \left (4-x\right )\,{\left (4\,{\mathrm {e}}^4-x\,{\mathrm {e}}^4\right )}^2\,\left (4\,x^5-16\,x^4-64\,x^3+256\,x^2\right )}{\left (\ln \left (4-x\right )-{\mathrm {e}}^{{\mathrm {e}}^{-4}\,x^4-32\,{\mathrm {e}}^{-4}\,x^2+256\,{\mathrm {e}}^{-4}}\right )\,\left (x-4\right )\,\left (4\,{\mathrm {e}}^8-x\,{\mathrm {e}}^8+512\,x^2\,{\mathrm {e}}^4\,\ln \left (4-x\right )-32\,x^4\,{\mathrm {e}}^4\,\ln \left (4-x\right )+4\,x^5\,{\mathrm {e}}^4\,\ln \left (4-x\right )-1024\,x\,{\mathrm {e}}^4\,\ln \left (4-x\right )\right )} \]
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