Integrand size = 38, antiderivative size = 25 \[ \int \frac {e^{\frac {1}{2} (-6-x)} (-2-x)}{e^{\frac {1}{2} (-6-x)} x-x^2} \, dx=\log \left (\frac {9 \left (-e^{\frac {1}{2} (-6+x)-x}+x\right )^2}{x^2}\right ) \]
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\[ \int \frac {e^{\frac {1}{2} (-6-x)} (-2-x)}{e^{\frac {1}{2} (-6-x)} x-x^2} \, dx=\int \frac {e^{\frac {1}{2} (-6-x)} (-2-x)}{e^{\frac {1}{2} (-6-x)} x-x^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {-2-x}{x \left (1-e^{3+\frac {x}{2}} x\right )} \, dx \\ & = \int \left (\frac {1}{-1+e^{3+\frac {x}{2}} x}+\frac {2}{x \left (-1+e^{3+\frac {x}{2}} x\right )}\right ) \, dx \\ & = 2 \int \frac {1}{x \left (-1+e^{3+\frac {x}{2}} x\right )} \, dx+\int \frac {1}{-1+e^{3+\frac {x}{2}} x} \, dx \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.68 \[ \int \frac {e^{\frac {1}{2} (-6-x)} (-2-x)}{e^{\frac {1}{2} (-6-x)} x-x^2} \, dx=4 \text {arctanh}\left (1-2 e^{3+\frac {x}{2}} x\right ) \]
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Time = 1.70 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.76
method | result | size |
norman | \(-2 \ln \left (x \right )+2 \ln \left (x -{\mathrm e}^{-\frac {x}{2}-3}\right )\) | \(19\) |
parallelrisch | \(-2 \ln \left (x \right )+2 \ln \left (x -{\mathrm e}^{-\frac {x}{2}-3}\right )\) | \(19\) |
risch | \(-2 \ln \left (x \right )+6+2 \ln \left ({\mathrm e}^{-\frac {x}{2}-3}-x \right )\) | \(20\) |
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Time = 0.28 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.72 \[ \int \frac {e^{\frac {1}{2} (-6-x)} (-2-x)}{e^{\frac {1}{2} (-6-x)} x-x^2} \, dx=-2 \, \log \left (x\right ) + 2 \, \log \left (-x + e^{\left (-\frac {1}{2} \, x - 3\right )}\right ) \]
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Time = 0.07 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.68 \[ \int \frac {e^{\frac {1}{2} (-6-x)} (-2-x)}{e^{\frac {1}{2} (-6-x)} x-x^2} \, dx=- 2 \log {\left (x \right )} + 2 \log {\left (- x + e^{- \frac {x}{2} - 3} \right )} \]
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Time = 0.22 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.92 \[ \int \frac {e^{\frac {1}{2} (-6-x)} (-2-x)}{e^{\frac {1}{2} (-6-x)} x-x^2} \, dx=-x + 2 \, \log \left (\frac {{\left (x e^{\left (\frac {1}{2} \, x + 3\right )} - 1\right )} e^{\left (-3\right )}}{x}\right ) \]
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Time = 0.25 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.80 \[ \int \frac {e^{\frac {1}{2} (-6-x)} (-2-x)}{e^{\frac {1}{2} (-6-x)} x-x^2} \, dx=-2 \, \log \left (-\frac {1}{2} \, x\right ) + 2 \, \log \left (x - e^{\left (-\frac {1}{2} \, x - 3\right )}\right ) \]
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Time = 9.39 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.72 \[ \int \frac {e^{\frac {1}{2} (-6-x)} (-2-x)}{e^{\frac {1}{2} (-6-x)} x-x^2} \, dx=2\,\ln \left (x-\frac {{\mathrm {e}}^{-3}}{\sqrt {{\mathrm {e}}^x}}\right )-2\,\ln \left (x\right ) \]
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