Integrand size = 227, antiderivative size = 25 \[ \int \frac {\left (960-960 x+300 x^2-30 x^3+e^x \left (-960+960 x-300 x^2+30 x^3\right )\right ) \log (-2+x)+\left (120-60 x+e^x (-120+60 x)\right ) \log ^2(-2+x)+\left (-480 x+240 x^2-30 x^3+e^x \left (480 x-240 x^2+30 x^3\right )+\left (480 x-360 x^2+60 x^3+e^x \left (-1440 x+1320 x^2-360 x^3+30 x^4\right )\right ) \log (-2+x)+e^x \left (-120 x+60 x^2\right ) \log ^2(-2+x)\right ) \log (x)}{-512 x+768 x^2-448 x^3+128 x^4-18 x^5+x^6+\left (-128 x+128 x^2-40 x^3+4 x^4\right ) \log (-2+x)+\left (-8 x+4 x^2\right ) \log ^2(-2+x)} \, dx=\frac {30 \left (-1+e^x\right ) \log (x)}{2+\frac {(-4+x)^2}{\log (-2+x)}} \]
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\[ \int \frac {\left (960-960 x+300 x^2-30 x^3+e^x \left (-960+960 x-300 x^2+30 x^3\right )\right ) \log (-2+x)+\left (120-60 x+e^x (-120+60 x)\right ) \log ^2(-2+x)+\left (-480 x+240 x^2-30 x^3+e^x \left (480 x-240 x^2+30 x^3\right )+\left (480 x-360 x^2+60 x^3+e^x \left (-1440 x+1320 x^2-360 x^3+30 x^4\right )\right ) \log (-2+x)+e^x \left (-120 x+60 x^2\right ) \log ^2(-2+x)\right ) \log (x)}{-512 x+768 x^2-448 x^3+128 x^4-18 x^5+x^6+\left (-128 x+128 x^2-40 x^3+4 x^4\right ) \log (-2+x)+\left (-8 x+4 x^2\right ) \log ^2(-2+x)} \, dx=\int \frac {\left (960-960 x+300 x^2-30 x^3+e^x \left (-960+960 x-300 x^2+30 x^3\right )\right ) \log (-2+x)+\left (120-60 x+e^x (-120+60 x)\right ) \log ^2(-2+x)+\left (-480 x+240 x^2-30 x^3+e^x \left (480 x-240 x^2+30 x^3\right )+\left (480 x-360 x^2+60 x^3+e^x \left (-1440 x+1320 x^2-360 x^3+30 x^4\right )\right ) \log (-2+x)+e^x \left (-120 x+60 x^2\right ) \log ^2(-2+x)\right ) \log (x)}{-512 x+768 x^2-448 x^3+128 x^4-18 x^5+x^6+\left (-128 x+128 x^2-40 x^3+4 x^4\right ) \log (-2+x)+\left (-8 x+4 x^2\right ) \log ^2(-2+x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {30 \left (-\left (\left (-1+e^x\right ) (-4+x)^2 x \log (x)\right )-2 (-2+x) \log ^2(-2+x) \left (-1+e^x+e^x x \log (x)\right )-\left (8-6 x+x^2\right ) \log (-2+x) \left (\left (-1+e^x\right ) (-4+x)+\left (2+e^x (-6+x)\right ) x \log (x)\right )\right )}{(2-x) x \left ((-4+x)^2+2 \log (-2+x)\right )^2} \, dx \\ & = 30 \int \frac {-\left (\left (-1+e^x\right ) (-4+x)^2 x \log (x)\right )-2 (-2+x) \log ^2(-2+x) \left (-1+e^x+e^x x \log (x)\right )-\left (8-6 x+x^2\right ) \log (-2+x) \left (\left (-1+e^x\right ) (-4+x)+\left (2+e^x (-6+x)\right ) x \log (x)\right )}{(2-x) x \left ((-4+x)^2+2 \log (-2+x)\right )^2} \, dx \\ & = 30 \int \left (-\frac {(-4+x) \log (-2+x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {4 (-4+x) \log (-2+x)}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {2 \log ^2(-2+x)}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {(-4+x)^2 \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {2 (-4+x) \log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {e^x \left (-32 \log (-2+x)+32 x \log (-2+x)-10 x^2 \log (-2+x)+x^3 \log (-2+x)-4 \log ^2(-2+x)+2 x \log ^2(-2+x)+16 x \log (x)-8 x^2 \log (x)+x^3 \log (x)-48 x \log (-2+x) \log (x)+44 x^2 \log (-2+x) \log (x)-12 x^3 \log (-2+x) \log (x)+x^4 \log (-2+x) \log (x)-4 x \log ^2(-2+x) \log (x)+2 x^2 \log ^2(-2+x) \log (x)\right )}{(-2+x) x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}\right ) \, dx \\ & = -\left (30 \int \frac {(-4+x) \log (-2+x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx\right )-30 \int \frac {(-4+x)^2 \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+30 \int \frac {e^x \left (-32 \log (-2+x)+32 x \log (-2+x)-10 x^2 \log (-2+x)+x^3 \log (-2+x)-4 \log ^2(-2+x)+2 x \log ^2(-2+x)+16 x \log (x)-8 x^2 \log (x)+x^3 \log (x)-48 x \log (-2+x) \log (x)+44 x^2 \log (-2+x) \log (x)-12 x^3 \log (-2+x) \log (x)+x^4 \log (-2+x) \log (x)-4 x \log ^2(-2+x) \log (x)+2 x^2 \log ^2(-2+x) \log (x)\right )}{(-2+x) x \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-60 \int \frac {\log ^2(-2+x)}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+60 \int \frac {(-4+x) \log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+120 \int \frac {(-4+x) \log (-2+x)}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx \\ & = -\left (30 \int \left (-\frac {(-4+x)^3}{2 \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {-4+x}{2 \left (16-8 x+x^2+2 \log (-2+x)\right )}\right ) \, dx\right )-30 \int \left (-\frac {6 \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {4 \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {x \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}\right ) \, dx+30 \int \frac {e^x \left (-(-4+x)^2 x \log (x)-2 (-2+x) \log ^2(-2+x) (1+x \log (x))-\left (8-6 x+x^2\right ) \log (-2+x) (-4+x+(-6+x) x \log (x))\right )}{(2-x) x \left ((-4+x)^2+2 \log (-2+x)\right )^2} \, dx-60 \int \left (\frac {1}{4 x}+\frac {(-4+x)^4}{4 x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {(-4+x)^2}{2 x \left (16-8 x+x^2+2 \log (-2+x)\right )}\right ) \, dx+60 \int \left (-\frac {4 \log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {x \log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}\right ) \, dx+120 \int \left (-\frac {(-4+x)^3}{2 x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {-4+x}{2 x \left (16-8 x+x^2+2 \log (-2+x)\right )}\right ) \, dx \\ & = -15 \log (x)+15 \int \frac {(-4+x)^3}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-15 \int \frac {(-4+x)^4}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-15 \int \frac {-4+x}{16-8 x+x^2+2 \log (-2+x)} \, dx+30 \int \frac {(-4+x)^2}{x \left (16-8 x+x^2+2 \log (-2+x)\right )} \, dx-30 \int \frac {x \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+30 \int \left (\frac {e^x (-4+x) \log (-2+x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {4 e^x (-4+x) \log (-2+x)}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {2 e^x \log ^2(-2+x)}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {e^x \left (16-8 x+x^2-48 \log (-2+x)+44 x \log (-2+x)-12 x^2 \log (-2+x)+x^3 \log (-2+x)-4 \log ^2(-2+x)+2 x \log ^2(-2+x)\right ) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}\right ) \, dx-60 \int \frac {(-4+x)^3}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+60 \int \frac {-4+x}{x \left (16-8 x+x^2+2 \log (-2+x)\right )} \, dx+60 \int \frac {x \log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-120 \int \frac {\log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+180 \int \frac {\log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-240 \int \frac {\log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx \\ & = -15 \log (x)-15 \int \left (-\frac {256}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {256}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {96 x}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {16 x^2}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {x^3}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}\right ) \, dx+15 \int \left (-\frac {64}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {48 x}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {12 x^2}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {x^3}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}\right ) \, dx-15 \int \left (-\frac {4}{16-8 x+x^2+2 \log (-2+x)}+\frac {x}{16-8 x+x^2+2 \log (-2+x)}\right ) \, dx+30 \int \frac {e^x (-4+x) \log (-2+x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+30 \int \left (-\frac {8}{16-8 x+x^2+2 \log (-2+x)}+\frac {16}{x \left (16-8 x+x^2+2 \log (-2+x)\right )}+\frac {x}{16-8 x+x^2+2 \log (-2+x)}\right ) \, dx-30 \int \frac {x \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+30 \int \frac {e^x \left (16-8 x+x^2-48 \log (-2+x)+44 x \log (-2+x)-12 x^2 \log (-2+x)+x^3 \log (-2+x)-4 \log ^2(-2+x)+2 x \log ^2(-2+x)\right ) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+60 \int \frac {e^x \log ^2(-2+x)}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-60 \int \left (\frac {48}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {64}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {12 x}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {x^2}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2}\right ) \, dx+60 \int \left (\frac {1}{16-8 x+x^2+2 \log (-2+x)}-\frac {4}{x \left (16-8 x+x^2+2 \log (-2+x)\right )}\right ) \, dx+60 \int \frac {x \log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-120 \int \frac {e^x (-4+x) \log (-2+x)}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-120 \int \frac {\log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+180 \int \frac {\log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-240 \int \frac {\log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx \\ & = -15 \log (x)-15 \int \frac {x}{16-8 x+x^2+2 \log (-2+x)} \, dx+30 \int \frac {x}{16-8 x+x^2+2 \log (-2+x)} \, dx+30 \int \left (-\frac {e^x (-4+x)^3}{2 \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {e^x (-4+x)}{2 \left (16-8 x+x^2+2 \log (-2+x)\right )}\right ) \, dx-30 \int \frac {x \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+30 \int \left (\frac {16 e^x \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {8 e^x x \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {e^x x^2 \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {48 e^x \log (-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {44 e^x x \log (-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {12 e^x x^2 \log (-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {e^x x^3 \log (-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {4 e^x \log ^2(-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {2 e^x x \log ^2(-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2}\right ) \, dx-60 \int \frac {x^2}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+2 \left (60 \int \frac {1}{16-8 x+x^2+2 \log (-2+x)} \, dx\right )+60 \int \left (\frac {e^x}{4 x}+\frac {e^x (-4+x)^4}{4 x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}-\frac {e^x (-4+x)^2}{2 x \left (16-8 x+x^2+2 \log (-2+x)\right )}\right ) \, dx+60 \int \frac {x \log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-120 \int \left (-\frac {e^x (-4+x)^3}{2 x \left (16-8 x+x^2+2 \log (-2+x)\right )^2}+\frac {e^x (-4+x)}{2 x \left (16-8 x+x^2+2 \log (-2+x)\right )}\right ) \, dx-120 \int \frac {\log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-180 \int \frac {x^2}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+180 \int \frac {\log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+240 \int \frac {x^2}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-240 \int \frac {1}{16-8 x+x^2+2 \log (-2+x)} \, dx-240 \int \frac {1}{x \left (16-8 x+x^2+2 \log (-2+x)\right )} \, dx-240 \int \frac {\log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+480 \int \frac {1}{x \left (16-8 x+x^2+2 \log (-2+x)\right )} \, dx+2 \left (720 \int \frac {x}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx\right )-960 \int \frac {1}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-1440 \int \frac {x}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-2880 \int \frac {1}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+3840 \int \frac {1}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx \\ & = -15 \log (x)+15 \int \frac {e^x}{x} \, dx-15 \int \frac {e^x (-4+x)^3}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+15 \int \frac {e^x (-4+x)^4}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+15 \int \frac {e^x (-4+x)}{16-8 x+x^2+2 \log (-2+x)} \, dx-15 \int \frac {x}{16-8 x+x^2+2 \log (-2+x)} \, dx-30 \int \frac {e^x (-4+x)^2}{x \left (16-8 x+x^2+2 \log (-2+x)\right )} \, dx+30 \int \frac {x}{16-8 x+x^2+2 \log (-2+x)} \, dx-30 \int \frac {x \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+30 \int \frac {e^x x^2 \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+30 \int \frac {e^x x^3 \log (-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+60 \int \frac {e^x (-4+x)^3}{x \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-60 \int \frac {x^2}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+2 \left (60 \int \frac {1}{16-8 x+x^2+2 \log (-2+x)} \, dx\right )-60 \int \frac {e^x (-4+x)}{x \left (16-8 x+x^2+2 \log (-2+x)\right )} \, dx+60 \int \frac {x \log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+60 \int \frac {e^x x \log ^2(-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-120 \int \frac {\log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-120 \int \frac {e^x \log ^2(-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-180 \int \frac {x^2}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+180 \int \frac {\log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+240 \int \frac {x^2}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-240 \int \frac {1}{16-8 x+x^2+2 \log (-2+x)} \, dx-240 \int \frac {1}{x \left (16-8 x+x^2+2 \log (-2+x)\right )} \, dx-240 \int \frac {e^x x \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-240 \int \frac {\log (-2+x) \log (x)}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-360 \int \frac {e^x x^2 \log (-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+480 \int \frac {1}{x \left (16-8 x+x^2+2 \log (-2+x)\right )} \, dx+480 \int \frac {e^x \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+2 \left (720 \int \frac {x}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx\right )-960 \int \frac {1}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+1320 \int \frac {e^x x \log (-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-1440 \int \frac {x}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-1440 \int \frac {e^x \log (-2+x) \log (x)}{(-2+x) \left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx-2880 \int \frac {1}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx+3840 \int \frac {1}{\left (16-8 x+x^2+2 \log (-2+x)\right )^2} \, dx \\ & = \text {Too large to display} \\ \end{align*}
Time = 0.16 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.08 \[ \int \frac {\left (960-960 x+300 x^2-30 x^3+e^x \left (-960+960 x-300 x^2+30 x^3\right )\right ) \log (-2+x)+\left (120-60 x+e^x (-120+60 x)\right ) \log ^2(-2+x)+\left (-480 x+240 x^2-30 x^3+e^x \left (480 x-240 x^2+30 x^3\right )+\left (480 x-360 x^2+60 x^3+e^x \left (-1440 x+1320 x^2-360 x^3+30 x^4\right )\right ) \log (-2+x)+e^x \left (-120 x+60 x^2\right ) \log ^2(-2+x)\right ) \log (x)}{-512 x+768 x^2-448 x^3+128 x^4-18 x^5+x^6+\left (-128 x+128 x^2-40 x^3+4 x^4\right ) \log (-2+x)+\left (-8 x+4 x^2\right ) \log ^2(-2+x)} \, dx=\frac {30 \left (-1+e^x\right ) \log (-2+x) \log (x)}{(-4+x)^2+2 \log (-2+x)} \]
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Time = 23.53 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.52
method | result | size |
parallelrisch | \(\frac {240 \ln \left (-2+x \right ) \ln \left (x \right ) {\mathrm e}^{x}-240 \ln \left (x \right ) \ln \left (-2+x \right )}{8 x^{2}+16 \ln \left (-2+x \right )-64 x +128}\) | \(38\) |
risch | \(15 \,{\mathrm e}^{x} \ln \left (x \right )-15 \ln \left (x \right )-\frac {15 \left ({\mathrm e}^{x} x^{2}-x^{2}-8 \,{\mathrm e}^{x} x +8 x +16 \,{\mathrm e}^{x}-16\right ) \ln \left (x \right )}{x^{2}+2 \ln \left (-2+x \right )-8 x +16}\) | \(57\) |
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Time = 0.27 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.12 \[ \int \frac {\left (960-960 x+300 x^2-30 x^3+e^x \left (-960+960 x-300 x^2+30 x^3\right )\right ) \log (-2+x)+\left (120-60 x+e^x (-120+60 x)\right ) \log ^2(-2+x)+\left (-480 x+240 x^2-30 x^3+e^x \left (480 x-240 x^2+30 x^3\right )+\left (480 x-360 x^2+60 x^3+e^x \left (-1440 x+1320 x^2-360 x^3+30 x^4\right )\right ) \log (-2+x)+e^x \left (-120 x+60 x^2\right ) \log ^2(-2+x)\right ) \log (x)}{-512 x+768 x^2-448 x^3+128 x^4-18 x^5+x^6+\left (-128 x+128 x^2-40 x^3+4 x^4\right ) \log (-2+x)+\left (-8 x+4 x^2\right ) \log ^2(-2+x)} \, dx=\frac {30 \, {\left (e^{x} - 1\right )} \log \left (x - 2\right ) \log \left (x\right )}{x^{2} - 8 \, x + 2 \, \log \left (x - 2\right ) + 16} \]
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Leaf count of result is larger than twice the leaf count of optimal. 68 vs. \(2 (20) = 40\).
Time = 0.28 (sec) , antiderivative size = 68, normalized size of antiderivative = 2.72 \[ \int \frac {\left (960-960 x+300 x^2-30 x^3+e^x \left (-960+960 x-300 x^2+30 x^3\right )\right ) \log (-2+x)+\left (120-60 x+e^x (-120+60 x)\right ) \log ^2(-2+x)+\left (-480 x+240 x^2-30 x^3+e^x \left (480 x-240 x^2+30 x^3\right )+\left (480 x-360 x^2+60 x^3+e^x \left (-1440 x+1320 x^2-360 x^3+30 x^4\right )\right ) \log (-2+x)+e^x \left (-120 x+60 x^2\right ) \log ^2(-2+x)\right ) \log (x)}{-512 x+768 x^2-448 x^3+128 x^4-18 x^5+x^6+\left (-128 x+128 x^2-40 x^3+4 x^4\right ) \log (-2+x)+\left (-8 x+4 x^2\right ) \log ^2(-2+x)} \, dx=\frac {15 x^{2} \log {\left (x \right )} - 120 x \log {\left (x \right )} + 240 \log {\left (x \right )}}{x^{2} - 8 x + 2 \log {\left (x - 2 \right )} + 16} - 15 \log {\left (x \right )} + \frac {30 e^{x} \log {\left (x \right )} \log {\left (x - 2 \right )}}{x^{2} - 8 x + 2 \log {\left (x - 2 \right )} + 16} \]
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Time = 0.25 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.80 \[ \int \frac {\left (960-960 x+300 x^2-30 x^3+e^x \left (-960+960 x-300 x^2+30 x^3\right )\right ) \log (-2+x)+\left (120-60 x+e^x (-120+60 x)\right ) \log ^2(-2+x)+\left (-480 x+240 x^2-30 x^3+e^x \left (480 x-240 x^2+30 x^3\right )+\left (480 x-360 x^2+60 x^3+e^x \left (-1440 x+1320 x^2-360 x^3+30 x^4\right )\right ) \log (-2+x)+e^x \left (-120 x+60 x^2\right ) \log ^2(-2+x)\right ) \log (x)}{-512 x+768 x^2-448 x^3+128 x^4-18 x^5+x^6+\left (-128 x+128 x^2-40 x^3+4 x^4\right ) \log (-2+x)+\left (-8 x+4 x^2\right ) \log ^2(-2+x)} \, dx=\frac {15 \, {\left (2 \, e^{x} \log \left (x - 2\right ) \log \left (x\right ) + {\left (x^{2} - 8 \, x + 16\right )} \log \left (x\right )\right )}}{x^{2} - 8 \, x + 2 \, \log \left (x - 2\right ) + 16} - 15 \, \log \left (x\right ) \]
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Time = 0.31 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.44 \[ \int \frac {\left (960-960 x+300 x^2-30 x^3+e^x \left (-960+960 x-300 x^2+30 x^3\right )\right ) \log (-2+x)+\left (120-60 x+e^x (-120+60 x)\right ) \log ^2(-2+x)+\left (-480 x+240 x^2-30 x^3+e^x \left (480 x-240 x^2+30 x^3\right )+\left (480 x-360 x^2+60 x^3+e^x \left (-1440 x+1320 x^2-360 x^3+30 x^4\right )\right ) \log (-2+x)+e^x \left (-120 x+60 x^2\right ) \log ^2(-2+x)\right ) \log (x)}{-512 x+768 x^2-448 x^3+128 x^4-18 x^5+x^6+\left (-128 x+128 x^2-40 x^3+4 x^4\right ) \log (-2+x)+\left (-8 x+4 x^2\right ) \log ^2(-2+x)} \, dx=\frac {30 \, {\left (e^{x} \log \left (x - 2\right ) \log \left (x\right ) - \log \left (x - 2\right ) \log \left (x\right )\right )}}{x^{2} - 8 \, x + 2 \, \log \left (x - 2\right ) + 16} \]
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Timed out. \[ \int \frac {\left (960-960 x+300 x^2-30 x^3+e^x \left (-960+960 x-300 x^2+30 x^3\right )\right ) \log (-2+x)+\left (120-60 x+e^x (-120+60 x)\right ) \log ^2(-2+x)+\left (-480 x+240 x^2-30 x^3+e^x \left (480 x-240 x^2+30 x^3\right )+\left (480 x-360 x^2+60 x^3+e^x \left (-1440 x+1320 x^2-360 x^3+30 x^4\right )\right ) \log (-2+x)+e^x \left (-120 x+60 x^2\right ) \log ^2(-2+x)\right ) \log (x)}{-512 x+768 x^2-448 x^3+128 x^4-18 x^5+x^6+\left (-128 x+128 x^2-40 x^3+4 x^4\right ) \log (-2+x)+\left (-8 x+4 x^2\right ) \log ^2(-2+x)} \, dx=\int -\frac {\ln \left (x-2\right )\,\left (300\,x^2-960\,x-30\,x^3+{\mathrm {e}}^x\,\left (30\,x^3-300\,x^2+960\,x-960\right )+960\right )-\ln \left (x\right )\,\left (480\,x-\ln \left (x-2\right )\,\left (480\,x-{\mathrm {e}}^x\,\left (-30\,x^4+360\,x^3-1320\,x^2+1440\,x\right )-360\,x^2+60\,x^3\right )-240\,x^2+30\,x^3-{\mathrm {e}}^x\,\left (30\,x^3-240\,x^2+480\,x\right )+{\ln \left (x-2\right )}^2\,{\mathrm {e}}^x\,\left (120\,x-60\,x^2\right )\right )+{\ln \left (x-2\right )}^2\,\left ({\mathrm {e}}^x\,\left (60\,x-120\right )-60\,x+120\right )}{512\,x+{\ln \left (x-2\right )}^2\,\left (8\,x-4\,x^2\right )+\ln \left (x-2\right )\,\left (-4\,x^4+40\,x^3-128\,x^2+128\,x\right )-768\,x^2+448\,x^3-128\,x^4+18\,x^5-x^6} \,d x \]
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