Integrand size = 130, antiderivative size = 29 \[ \int \frac {4-2 x^2-2 e^x x^2+\left (2+e^x x+x^2\right ) \log \left (\frac {8+4 e^x x+4 x^2}{x}\right )+\left (-2-e^x x-x^2+e^{2+x} \left (-2-e^x x-x^2\right )\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )} \, dx=1-e^{2+x}-x+\frac {x}{\log ^2\left (4 \left (e^x+\frac {2}{x}+x\right )\right )} \]
[Out]
\[ \int \frac {4-2 x^2-2 e^x x^2+\left (2+e^x x+x^2\right ) \log \left (\frac {8+4 e^x x+4 x^2}{x}\right )+\left (-2-e^x x-x^2+e^{2+x} \left (-2-e^x x-x^2\right )\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )} \, dx=\int \frac {4-2 x^2-2 e^x x^2+\left (2+e^x x+x^2\right ) \log \left (\frac {8+4 e^x x+4 x^2}{x}\right )+\left (-2-e^x x-x^2+e^{2+x} \left (-2-e^x x-x^2\right )\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )} \, dx \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = \int \frac {4-2 x^2-2 e^x x^2+\left (2+e^x x+x^2\right ) \log \left (\frac {8+4 e^x x+4 x^2}{x}\right )+\left (-2-e^x x-x^2+e^{2+x} \left (-2-e^x x-x^2\right )\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (\frac {4 \left (2+e^x x+x^2\right )}{x}\right )} \, dx \\ & = \int \left (-e^{2+x}+\frac {2 \left (2+2 x-x^2+x^3\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )}+\frac {-2 x+\log \left (4 \left (e^x+\frac {2}{x}+x\right )\right )-\log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )}{\log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )}\right ) \, dx \\ & = 2 \int \frac {2+2 x-x^2+x^3}{\left (2+e^x x+x^2\right ) \log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )} \, dx-\int e^{2+x} \, dx+\int \frac {-2 x+\log \left (4 \left (e^x+\frac {2}{x}+x\right )\right )-\log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )}{\log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )} \, dx \\ & = -e^{2+x}+2 \int \left (\frac {2}{\left (2+e^x x+x^2\right ) \log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )}+\frac {2 x}{\left (2+e^x x+x^2\right ) \log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )}-\frac {x^2}{\left (2+e^x x+x^2\right ) \log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )}+\frac {x^3}{\left (2+e^x x+x^2\right ) \log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )}\right ) \, dx+\int \left (-1-\frac {2 x}{\log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )}+\frac {1}{\log ^2\left (4 \left (e^x+\frac {2}{x}+x\right )\right )}\right ) \, dx \\ & = -e^{2+x}-x-2 \int \frac {x}{\log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )} \, dx-2 \int \frac {x^2}{\left (2+e^x x+x^2\right ) \log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )} \, dx+2 \int \frac {x^3}{\left (2+e^x x+x^2\right ) \log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )} \, dx+4 \int \frac {1}{\left (2+e^x x+x^2\right ) \log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )} \, dx+4 \int \frac {x}{\left (2+e^x x+x^2\right ) \log ^3\left (4 \left (e^x+\frac {2}{x}+x\right )\right )} \, dx+\int \frac {1}{\log ^2\left (4 \left (e^x+\frac {2}{x}+x\right )\right )} \, dx \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.97 \[ \int \frac {4-2 x^2-2 e^x x^2+\left (2+e^x x+x^2\right ) \log \left (\frac {8+4 e^x x+4 x^2}{x}\right )+\left (-2-e^x x-x^2+e^{2+x} \left (-2-e^x x-x^2\right )\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )} \, dx=-e^{2+x}-x+\frac {x}{\log ^2\left (4 \left (e^x+\frac {2}{x}+x\right )\right )} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. \(66\) vs. \(2(29)=58\).
Time = 5.72 (sec) , antiderivative size = 67, normalized size of antiderivative = 2.31
method | result | size |
parallelrisch | \(\frac {-4 \ln \left (\frac {4 \,{\mathrm e}^{x} x +4 x^{2}+8}{x}\right )^{2} x -4 \ln \left (\frac {4 \,{\mathrm e}^{x} x +4 x^{2}+8}{x}\right )^{2} {\mathrm e}^{2+x}+4 x}{4 \ln \left (\frac {4 \,{\mathrm e}^{x} x +4 x^{2}+8}{x}\right )^{2}}\) | \(67\) |
risch | \(-{\mathrm e}^{2+x}-x -\frac {4 x}{{\left (\pi \,\operatorname {csgn}\left (i \left ({\mathrm e}^{x} x +x^{2}+2\right )\right ) {\operatorname {csgn}\left (\frac {i \left ({\mathrm e}^{x} x +x^{2}+2\right )}{x}\right )}^{2}-\pi \,\operatorname {csgn}\left (i \left ({\mathrm e}^{x} x +x^{2}+2\right )\right ) \operatorname {csgn}\left (\frac {i \left ({\mathrm e}^{x} x +x^{2}+2\right )}{x}\right ) \operatorname {csgn}\left (\frac {i}{x}\right )-\pi {\operatorname {csgn}\left (\frac {i \left ({\mathrm e}^{x} x +x^{2}+2\right )}{x}\right )}^{3}+\pi {\operatorname {csgn}\left (\frac {i \left ({\mathrm e}^{x} x +x^{2}+2\right )}{x}\right )}^{2} \operatorname {csgn}\left (\frac {i}{x}\right )-4 i \ln \left (2\right )+2 i \ln \left (x \right )-2 i \ln \left ({\mathrm e}^{x} x +x^{2}+2\right )\right )}^{2}}\) | \(160\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 63 vs. \(2 (29) = 58\).
Time = 0.27 (sec) , antiderivative size = 63, normalized size of antiderivative = 2.17 \[ \int \frac {4-2 x^2-2 e^x x^2+\left (2+e^x x+x^2\right ) \log \left (\frac {8+4 e^x x+4 x^2}{x}\right )+\left (-2-e^x x-x^2+e^{2+x} \left (-2-e^x x-x^2\right )\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )} \, dx=-\frac {{\left (x + e^{\left (x + 2\right )}\right )} \log \left (\frac {4 \, {\left ({\left (x^{2} + 2\right )} e^{2} + x e^{\left (x + 2\right )}\right )} e^{\left (-2\right )}}{x}\right )^{2} - x}{\log \left (\frac {4 \, {\left ({\left (x^{2} + 2\right )} e^{2} + x e^{\left (x + 2\right )}\right )} e^{\left (-2\right )}}{x}\right )^{2}} \]
[In]
[Out]
Time = 0.16 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.93 \[ \int \frac {4-2 x^2-2 e^x x^2+\left (2+e^x x+x^2\right ) \log \left (\frac {8+4 e^x x+4 x^2}{x}\right )+\left (-2-e^x x-x^2+e^{2+x} \left (-2-e^x x-x^2\right )\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )} \, dx=- x + \frac {x}{\log {\left (\frac {4 x^{2} + 4 x e^{x} + 8}{x} \right )}^{2}} - e^{2} e^{x} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 163 vs. \(2 (29) = 58\).
Time = 0.34 (sec) , antiderivative size = 163, normalized size of antiderivative = 5.62 \[ \int \frac {4-2 x^2-2 e^x x^2+\left (2+e^x x+x^2\right ) \log \left (\frac {8+4 e^x x+4 x^2}{x}\right )+\left (-2-e^x x-x^2+e^{2+x} \left (-2-e^x x-x^2\right )\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )} \, dx=-\frac {{\left (x + e^{\left (x + 2\right )}\right )} \log \left (x^{2} + x e^{x} + 2\right )^{2} - 4 \, x \log \left (2\right ) \log \left (x\right ) + x \log \left (x\right )^{2} + {\left (4 \, \log \left (2\right )^{2} - 1\right )} x + {\left (4 \, e^{2} \log \left (2\right )^{2} - 4 \, e^{2} \log \left (2\right ) \log \left (x\right ) + e^{2} \log \left (x\right )^{2}\right )} e^{x} + 2 \, {\left ({\left (2 \, e^{2} \log \left (2\right ) - e^{2} \log \left (x\right )\right )} e^{x} + 2 \, x \log \left (2\right ) - x \log \left (x\right )\right )} \log \left (x^{2} + x e^{x} + 2\right )}{4 \, \log \left (2\right )^{2} + 2 \, {\left (2 \, \log \left (2\right ) - \log \left (x\right )\right )} \log \left (x^{2} + x e^{x} + 2\right ) + \log \left (x^{2} + x e^{x} + 2\right )^{2} - 4 \, \log \left (2\right ) \log \left (x\right ) + \log \left (x\right )^{2}} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 64 vs. \(2 (29) = 58\).
Time = 0.94 (sec) , antiderivative size = 64, normalized size of antiderivative = 2.21 \[ \int \frac {4-2 x^2-2 e^x x^2+\left (2+e^x x+x^2\right ) \log \left (\frac {8+4 e^x x+4 x^2}{x}\right )+\left (-2-e^x x-x^2+e^{2+x} \left (-2-e^x x-x^2\right )\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )} \, dx=-\frac {x \log \left (\frac {4 \, {\left (x^{2} + x e^{x} + 2\right )}}{x}\right )^{2} + e^{\left (x + 2\right )} \log \left (\frac {4 \, {\left (x^{2} + x e^{x} + 2\right )}}{x}\right )^{2} - x}{\log \left (\frac {4 \, {\left (x^{2} + x e^{x} + 2\right )}}{x}\right )^{2}} \]
[In]
[Out]
Time = 10.44 (sec) , antiderivative size = 483, normalized size of antiderivative = 16.66 \[ \int \frac {4-2 x^2-2 e^x x^2+\left (2+e^x x+x^2\right ) \log \left (\frac {8+4 e^x x+4 x^2}{x}\right )+\left (-2-e^x x-x^2+e^{2+x} \left (-2-e^x x-x^2\right )\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )}{\left (2+e^x x+x^2\right ) \log ^3\left (\frac {8+4 e^x x+4 x^2}{x}\right )} \, dx=\frac {\frac {x\,\left (x\,{\mathrm {e}}^x+x^2+2\right )}{2\,\left (x^2\,{\mathrm {e}}^x+x^2-2\right )}+\frac {x\,\ln \left (\frac {4\,x\,{\mathrm {e}}^x+4\,x^2+8}{x}\right )\,\left (x\,{\mathrm {e}}^x+x^2+2\right )\,\left (4\,x^2\,{\mathrm {e}}^x+2\,x^3\,{\mathrm {e}}^x-2\,x^4\,{\mathrm {e}}^x+x^5\,{\mathrm {e}}^x+4\,x\,{\mathrm {e}}^x+8\,x^2-x^4+4\right )}{2\,{\left (x^2\,{\mathrm {e}}^x+x^2-2\right )}^3}}{\ln \left (\frac {4\,x\,{\mathrm {e}}^x+4\,x^2+8}{x}\right )}-{\mathrm {e}}^{x+2}-x+\frac {x-\frac {x\,\ln \left (\frac {4\,x\,{\mathrm {e}}^x+4\,x^2+8}{x}\right )\,\left (x\,{\mathrm {e}}^x+x^2+2\right )}{2\,\left (x^2\,{\mathrm {e}}^x+x^2-2\right )}}{{\ln \left (\frac {4\,x\,{\mathrm {e}}^x+4\,x^2+8}{x}\right )}^2}-\frac {-x^7+2\,x^6-4\,x^4-8\,x^3+16\,x^2+24\,x+16}{2\,\left (x^2\,{\mathrm {e}}^x+x^2-2\right )\,\left (-x^4+2\,x^2+4\,x\right )}-\frac {-x^{12}+4\,x^{11}-5\,x^{10}-4\,x^9-2\,x^8+20\,x^7-28\,x^6+88\,x^4+144\,x^3+64\,x^2}{2\,x^2\,\left (-x^4+2\,x^2+4\,x\right )\,\left (x^4\,{\mathrm {e}}^{2\,x}+{\left (x^2-2\right )}^2+2\,x^2\,{\mathrm {e}}^x\,\left (x^2-2\right )\right )}-\frac {x^{16}-2\,x^{15}+x^{14}-24\,x^{11}+8\,x^{10}+16\,x^9+144\,x^6+192\,x^5+64\,x^4}{2\,x^4\,\left (-x^4+2\,x^2+4\,x\right )\,\left (x^6\,{\mathrm {e}}^{3\,x}+{\left (x^2-2\right )}^3+3\,x^4\,{\mathrm {e}}^{2\,x}\,\left (x^2-2\right )+3\,x^2\,{\mathrm {e}}^x\,{\left (x^2-2\right )}^2\right )} \]
[In]
[Out]