Integrand size = 49, antiderivative size = 14 \[ \int \frac {-12-4 \log (x)+(3+\log (x))^x (-4+(-12-4 \log (x)) \log (3+\log (x)))}{3+3 x+(1+x) \log (x)+(3+\log (x))^{1+x}} \, dx=\log \left (\frac {16}{\left (1+x+(3+\log (x))^x\right )^4}\right ) \]
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\[ \int \frac {-12-4 \log (x)+(3+\log (x))^x (-4+(-12-4 \log (x)) \log (3+\log (x)))}{3+3 x+(1+x) \log (x)+(3+\log (x))^{1+x}} \, dx=\int \frac {-12-4 \log (x)+(3+\log (x))^x (-4+(-12-4 \log (x)) \log (3+\log (x)))}{3+3 x+(1+x) \log (x)+(3+\log (x))^{1+x}} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {-12-4 \log (x)+(3+\log (x))^x (-4+(-12-4 \log (x)) \log (3+\log (x)))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx \\ & = \int \left (-\frac {4 (1+3 \log (3+\log (x))+\log (x) \log (3+\log (x)))}{3+\log (x)}+\frac {4 (-2+x-\log (x)+3 \log (3+\log (x))+3 x \log (3+\log (x))+\log (x) \log (3+\log (x))+x \log (x) \log (3+\log (x)))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )}\right ) \, dx \\ & = -\left (4 \int \frac {1+3 \log (3+\log (x))+\log (x) \log (3+\log (x))}{3+\log (x)} \, dx\right )+4 \int \frac {-2+x-\log (x)+3 \log (3+\log (x))+3 x \log (3+\log (x))+\log (x) \log (3+\log (x))+x \log (x) \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx \\ & = -\left (4 \int \left (\frac {1}{3+\log (x)}+\log (3+\log (x))\right ) \, dx\right )+4 \int \frac {-2+x+3 (1+x) \log (3+\log (x))+\log (x) (-1+(1+x) \log (3+\log (x)))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx \\ & = -\left (4 \int \frac {1}{3+\log (x)} \, dx\right )-4 \int \log (3+\log (x)) \, dx+4 \int \left (-\frac {2}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )}+\frac {x}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )}-\frac {\log (x)}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )}+\frac {3 \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )}+\frac {3 x \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )}+\frac {\log (x) \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )}+\frac {x \log (x) \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )}\right ) \, dx \\ & = 4 \int \frac {x}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx-4 \int \frac {\log (x)}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx-4 \int \log (3+\log (x)) \, dx+4 \int \frac {\log (x) \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx+4 \int \frac {x \log (x) \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx-4 \text {Subst}\left (\int \frac {e^x}{3+x} \, dx,x,\log (x)\right )-8 \int \frac {1}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx+12 \int \frac {\log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx+12 \int \frac {x \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx \\ & = -\frac {4 \text {Ei}(3+\log (x))}{e^3}+4 \int \frac {x}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx-4 \int \frac {\log (x)}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx-4 \int \log (3+\log (x)) \, dx+4 \int \frac {\log (x) \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx+4 \int \frac {x \log (x) \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx-8 \int \frac {1}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx+12 \int \frac {\log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx+12 \int \frac {x \log (3+\log (x))}{(3+\log (x)) \left (1+x+(3+\log (x))^x\right )} \, dx \\ \end{align*}
Time = 0.25 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.86 \[ \int \frac {-12-4 \log (x)+(3+\log (x))^x (-4+(-12-4 \log (x)) \log (3+\log (x)))}{3+3 x+(1+x) \log (x)+(3+\log (x))^{1+x}} \, dx=-4 \log \left (1+x+(3+\log (x))^x\right ) \]
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Time = 1.04 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.93
method | result | size |
risch | \(-4 \ln \left (\left (3+\ln \left (x \right )\right )^{x}+x +1\right )\) | \(13\) |
parallelrisch | \(-4 \ln \left (x +{\mathrm e}^{x \ln \left (3+\ln \left (x \right )\right )}+1\right )\) | \(15\) |
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Time = 0.25 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.86 \[ \int \frac {-12-4 \log (x)+(3+\log (x))^x (-4+(-12-4 \log (x)) \log (3+\log (x)))}{3+3 x+(1+x) \log (x)+(3+\log (x))^{1+x}} \, dx=-4 \, \log \left (x + {\left (\log \left (x\right ) + 3\right )}^{x} + 1\right ) \]
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Time = 0.25 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.21 \[ \int \frac {-12-4 \log (x)+(3+\log (x))^x (-4+(-12-4 \log (x)) \log (3+\log (x)))}{3+3 x+(1+x) \log (x)+(3+\log (x))^{1+x}} \, dx=- 4 \log {\left (x + e^{x \log {\left (\log {\left (x \right )} + 3 \right )}} + 1 \right )} \]
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Time = 0.21 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.86 \[ \int \frac {-12-4 \log (x)+(3+\log (x))^x (-4+(-12-4 \log (x)) \log (3+\log (x)))}{3+3 x+(1+x) \log (x)+(3+\log (x))^{1+x}} \, dx=-4 \, \log \left (x + {\left (\log \left (x\right ) + 3\right )}^{x} + 1\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 67 vs. \(2 (14) = 28\).
Time = 0.90 (sec) , antiderivative size = 67, normalized size of antiderivative = 4.79 \[ \int \frac {-12-4 \log (x)+(3+\log (x))^x (-4+(-12-4 \log (x)) \log (3+\log (x)))}{3+3 x+(1+x) \log (x)+(3+\log (x))^{1+x}} \, dx=-\frac {4 \, x e^{3} \log \left (x\right ) \log \left (\log \left (x\right ) + 3\right )}{e^{3} \log \left (x\right ) + 3 \, e^{3}} + 4 \, x \log \left (\log \left (x\right ) + 3\right ) - \frac {12 \, x e^{3} \log \left (\log \left (x\right ) + 3\right )}{e^{3} \log \left (x\right ) + 3 \, e^{3}} - 4 \, \log \left (x + {\left (\log \left (x\right ) + 3\right )}^{x} + 1\right ) \]
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Time = 9.59 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.86 \[ \int \frac {-12-4 \log (x)+(3+\log (x))^x (-4+(-12-4 \log (x)) \log (3+\log (x)))}{3+3 x+(1+x) \log (x)+(3+\log (x))^{1+x}} \, dx=-4\,\ln \left (x+{\left (\ln \left (x\right )+3\right )}^x+1\right ) \]
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