Integrand size = 7, antiderivative size = 19 \[ \int \left (-2+e^{16} x\right ) \, dx=1+2 \left (9-x+\frac {e^{16} x^2}{4}\right ) \]
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Time = 0.00 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.74, number of steps used = 1, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \left (-2+e^{16} x\right ) \, dx=\frac {e^{16} x^2}{2}-2 x \]
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Rubi steps \begin{align*} \text {integral}& = -2 x+\frac {e^{16} x^2}{2} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.74 \[ \int \left (-2+e^{16} x\right ) \, dx=-2 x+\frac {e^{16} x^2}{2} \]
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Time = 0.27 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.63
method | result | size |
gosper | \(\frac {x^{2} {\mathrm e}^{16}}{2}-2 x\) | \(12\) |
default | \(\frac {x^{2} {\mathrm e}^{16}}{2}-2 x\) | \(12\) |
norman | \(\frac {x^{2} {\mathrm e}^{16}}{2}-2 x\) | \(12\) |
risch | \(\frac {x^{2} {\mathrm e}^{16}}{2}-2 x\) | \(12\) |
parallelrisch | \(\frac {x^{2} {\mathrm e}^{16}}{2}-2 x\) | \(12\) |
parts | \(\frac {x^{2} {\mathrm e}^{16}}{2}-2 x\) | \(12\) |
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none
Time = 0.23 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.58 \[ \int \left (-2+e^{16} x\right ) \, dx=\frac {1}{2} \, x^{2} e^{16} - 2 \, x \]
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Time = 0.02 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.53 \[ \int \left (-2+e^{16} x\right ) \, dx=\frac {x^{2} e^{16}}{2} - 2 x \]
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none
Time = 0.19 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.58 \[ \int \left (-2+e^{16} x\right ) \, dx=\frac {1}{2} \, x^{2} e^{16} - 2 \, x \]
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none
Time = 0.25 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.58 \[ \int \left (-2+e^{16} x\right ) \, dx=\frac {1}{2} \, x^{2} e^{16} - 2 \, x \]
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Time = 0.03 (sec) , antiderivative size = 9, normalized size of antiderivative = 0.47 \[ \int \left (-2+e^{16} x\right ) \, dx=\frac {x\,\left (x\,{\mathrm {e}}^{16}-4\right )}{2} \]
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