Integrand size = 75, antiderivative size = 27 \[ \int \frac {-60-30 x+\left (-30+15 x+6 x^2-3 x^3\right ) \log \left (\frac {20-4 x^2}{x^2}\right )}{\left (-160-240 x-88 x^2+28 x^3+24 x^4+4 x^5\right ) \log ^2\left (\frac {20-4 x^2}{x^2}\right )} \, dx=\frac {3 x}{4 (2+x)^2 \log \left (\frac {4 \left (\frac {5}{x}-x\right )}{x}\right )} \]
[Out]
\[ \int \frac {-60-30 x+\left (-30+15 x+6 x^2-3 x^3\right ) \log \left (\frac {20-4 x^2}{x^2}\right )}{\left (-160-240 x-88 x^2+28 x^3+24 x^4+4 x^5\right ) \log ^2\left (\frac {20-4 x^2}{x^2}\right )} \, dx=\int \frac {-60-30 x+\left (-30+15 x+6 x^2-3 x^3\right ) \log \left (\frac {20-4 x^2}{x^2}\right )}{\left (-160-240 x-88 x^2+28 x^3+24 x^4+4 x^5\right ) \log ^2\left (\frac {20-4 x^2}{x^2}\right )} \, dx \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = \int \frac {3 \left (10 (2+x)+\left (10-5 x-2 x^2+x^3\right ) \log \left (-4+\frac {20}{x^2}\right )\right )}{4 (2+x)^3 \left (5-x^2\right ) \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx \\ & = \frac {3}{4} \int \frac {10 (2+x)+\left (10-5 x-2 x^2+x^3\right ) \log \left (-4+\frac {20}{x^2}\right )}{(2+x)^3 \left (5-x^2\right ) \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx \\ & = \frac {3}{4} \int \left (-\frac {10}{(2+x)^2 \left (-5+x^2\right ) \log ^2\left (-4+\frac {20}{x^2}\right )}+\frac {2-x}{(2+x)^3 \log \left (-4+\frac {20}{x^2}\right )}\right ) \, dx \\ & = \frac {3}{4} \int \frac {2-x}{(2+x)^3 \log \left (-4+\frac {20}{x^2}\right )} \, dx-\frac {15}{2} \int \frac {1}{(2+x)^2 \left (-5+x^2\right ) \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx \\ & = \frac {3}{4} \int \left (\frac {4}{(2+x)^3 \log \left (-4+\frac {20}{x^2}\right )}-\frac {1}{(2+x)^2 \log \left (-4+\frac {20}{x^2}\right )}\right ) \, dx-\frac {15}{2} \int \left (-\frac {1}{(2+x)^2 \log ^2\left (-4+\frac {20}{x^2}\right )}+\frac {4}{(2+x) \log ^2\left (-4+\frac {20}{x^2}\right )}+\frac {9-4 x}{\left (-5+x^2\right ) \log ^2\left (-4+\frac {20}{x^2}\right )}\right ) \, dx \\ & = -\left (\frac {3}{4} \int \frac {1}{(2+x)^2 \log \left (-4+\frac {20}{x^2}\right )} \, dx\right )+3 \int \frac {1}{(2+x)^3 \log \left (-4+\frac {20}{x^2}\right )} \, dx+\frac {15}{2} \int \frac {1}{(2+x)^2 \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx-\frac {15}{2} \int \frac {9-4 x}{\left (-5+x^2\right ) \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx-30 \int \frac {1}{(2+x) \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx \\ & = -\left (\frac {3}{4} \int \frac {1}{(2+x)^2 \log \left (-4+\frac {20}{x^2}\right )} \, dx\right )+3 \int \frac {1}{(2+x)^3 \log \left (-4+\frac {20}{x^2}\right )} \, dx-\frac {15}{2} \int \left (\frac {9}{\left (-5+x^2\right ) \log ^2\left (-4+\frac {20}{x^2}\right )}-\frac {4 x}{\left (-5+x^2\right ) \log ^2\left (-4+\frac {20}{x^2}\right )}\right ) \, dx+\frac {15}{2} \int \frac {1}{(2+x)^2 \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx-30 \int \frac {1}{(2+x) \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx \\ & = -\left (\frac {3}{4} \int \frac {1}{(2+x)^2 \log \left (-4+\frac {20}{x^2}\right )} \, dx\right )+3 \int \frac {1}{(2+x)^3 \log \left (-4+\frac {20}{x^2}\right )} \, dx+\frac {15}{2} \int \frac {1}{(2+x)^2 \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx-30 \int \frac {1}{(2+x) \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx+30 \int \frac {x}{\left (-5+x^2\right ) \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx-\frac {135}{2} \int \frac {1}{\left (-5+x^2\right ) \log ^2\left (-4+\frac {20}{x^2}\right )} \, dx \\ \end{align*}
Time = 0.22 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.74 \[ \int \frac {-60-30 x+\left (-30+15 x+6 x^2-3 x^3\right ) \log \left (\frac {20-4 x^2}{x^2}\right )}{\left (-160-240 x-88 x^2+28 x^3+24 x^4+4 x^5\right ) \log ^2\left (\frac {20-4 x^2}{x^2}\right )} \, dx=\frac {3 x}{4 (2+x)^2 \log \left (-4+\frac {20}{x^2}\right )} \]
[In]
[Out]
Time = 6.73 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.85
method | result | size |
norman | \(\frac {3 x}{4 \left (2+x \right )^{2} \ln \left (\frac {-4 x^{2}+20}{x^{2}}\right )}\) | \(23\) |
parallelrisch | \(\frac {3 x}{4 \left (x^{2}+4 x +4\right ) \ln \left (-\frac {4 \left (x^{2}-5\right )}{x^{2}}\right )}\) | \(27\) |
risch | \(\frac {3 x}{4 \left (x^{2}+4 x +4\right ) \ln \left (\frac {-4 x^{2}+20}{x^{2}}\right )}\) | \(28\) |
[In]
[Out]
none
Time = 0.23 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.96 \[ \int \frac {-60-30 x+\left (-30+15 x+6 x^2-3 x^3\right ) \log \left (\frac {20-4 x^2}{x^2}\right )}{\left (-160-240 x-88 x^2+28 x^3+24 x^4+4 x^5\right ) \log ^2\left (\frac {20-4 x^2}{x^2}\right )} \, dx=\frac {3 \, x}{4 \, {\left (x^{2} + 4 \, x + 4\right )} \log \left (-\frac {4 \, {\left (x^{2} - 5\right )}}{x^{2}}\right )} \]
[In]
[Out]
Time = 0.08 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.89 \[ \int \frac {-60-30 x+\left (-30+15 x+6 x^2-3 x^3\right ) \log \left (\frac {20-4 x^2}{x^2}\right )}{\left (-160-240 x-88 x^2+28 x^3+24 x^4+4 x^5\right ) \log ^2\left (\frac {20-4 x^2}{x^2}\right )} \, dx=\frac {3 x}{\left (4 x^{2} + 16 x + 16\right ) \log {\left (\frac {20 - 4 x^{2}}{x^{2}} \right )}} \]
[In]
[Out]
Result contains complex when optimal does not.
Time = 0.32 (sec) , antiderivative size = 63, normalized size of antiderivative = 2.33 \[ \int \frac {-60-30 x+\left (-30+15 x+6 x^2-3 x^3\right ) \log \left (\frac {20-4 x^2}{x^2}\right )}{\left (-160-240 x-88 x^2+28 x^3+24 x^4+4 x^5\right ) \log ^2\left (\frac {20-4 x^2}{x^2}\right )} \, dx=\frac {3 \, x}{4 \, {\left (4 i \, \pi + {\left (i \, \pi + 2 \, \log \left (2\right )\right )} x^{2} - 4 \, {\left (-i \, \pi - 2 \, \log \left (2\right )\right )} x + {\left (x^{2} + 4 \, x + 4\right )} \log \left (x^{2} - 5\right ) - 2 \, {\left (x^{2} + 4 \, x + 4\right )} \log \left (x\right ) + 8 \, \log \left (2\right )\right )}} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 48 vs. \(2 (23) = 46\).
Time = 0.27 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.78 \[ \int \frac {-60-30 x+\left (-30+15 x+6 x^2-3 x^3\right ) \log \left (\frac {20-4 x^2}{x^2}\right )}{\left (-160-240 x-88 x^2+28 x^3+24 x^4+4 x^5\right ) \log ^2\left (\frac {20-4 x^2}{x^2}\right )} \, dx=\frac {3 \, x}{4 \, {\left (x^{2} \log \left (-\frac {4 \, {\left (x^{2} - 5\right )}}{x^{2}}\right ) + 4 \, x \log \left (-\frac {4 \, {\left (x^{2} - 5\right )}}{x^{2}}\right ) + 4 \, \log \left (-\frac {4 \, {\left (x^{2} - 5\right )}}{x^{2}}\right )\right )}} \]
[In]
[Out]
Time = 8.75 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.81 \[ \int \frac {-60-30 x+\left (-30+15 x+6 x^2-3 x^3\right ) \log \left (\frac {20-4 x^2}{x^2}\right )}{\left (-160-240 x-88 x^2+28 x^3+24 x^4+4 x^5\right ) \log ^2\left (\frac {20-4 x^2}{x^2}\right )} \, dx=\frac {3\,x}{4\,\ln \left (-\frac {4\,x^2-20}{x^2}\right )\,{\left (x+2\right )}^2}-\frac {12}{5\,{\left (x+2\right )}^2}-\frac {3\,x^2}{5\,{\left (x+2\right )}^2}-\frac {12\,x}{5\,{\left (x+2\right )}^2} \]
[In]
[Out]