Integrand size = 69, antiderivative size = 29 \[ \int \frac {9-6 e+e^2+(12 x-4 e x) \log (x)+(-12 x+4 e x) \log ^2(x)+\left (8 x-16 x^2\right ) \log ^3(x)-32 x \log ^3(x) \log ^2(\log (4))}{8 x \log ^3(x)} \, dx=x-\left (x+\frac {3-e}{4 \log (x)}\right )^2-4 x \log ^2(\log (4)) \]
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Time = 0.12 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.66, number of steps used = 8, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {12, 6820, 2339, 30, 2334, 2335} \[ \int \frac {9-6 e+e^2+(12 x-4 e x) \log (x)+(-12 x+4 e x) \log ^2(x)+\left (8 x-16 x^2\right ) \log ^3(x)-32 x \log ^3(x) \log ^2(\log (4))}{8 x \log ^3(x)} \, dx=-\frac {1}{4} \left (-2 x+1-4 \log ^2(\log (4))\right )^2-\frac {(3-e)^2}{16 \log ^2(x)}-\frac {(3-e) x}{2 \log (x)} \]
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Rule 12
Rule 30
Rule 2334
Rule 2335
Rule 2339
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \frac {1}{8} \int \frac {9-6 e+e^2+(12 x-4 e x) \log (x)+(-12 x+4 e x) \log ^2(x)+\left (8 x-16 x^2\right ) \log ^3(x)-32 x \log ^3(x) \log ^2(\log (4))}{x \log ^3(x)} \, dx \\ & = \frac {1}{8} \int \left (\frac {(-3+e)^2}{x \log ^3(x)}-\frac {4 (-3+e)}{\log ^2(x)}+\frac {4 (-3+e)}{\log (x)}-8 \left (-1+2 x+4 \log ^2(\log (4))\right )\right ) \, dx \\ & = -\frac {1}{4} \left (1-2 x-4 \log ^2(\log (4))\right )^2+\frac {1}{2} (3-e) \int \frac {1}{\log ^2(x)} \, dx+\frac {1}{8} (3-e)^2 \int \frac {1}{x \log ^3(x)} \, dx+\frac {1}{2} (-3+e) \int \frac {1}{\log (x)} \, dx \\ & = -\frac {(3-e) x}{2 \log (x)}-\frac {1}{4} \left (1-2 x-4 \log ^2(\log (4))\right )^2-\frac {1}{2} (3-e) \text {li}(x)+\frac {1}{2} (3-e) \int \frac {1}{\log (x)} \, dx+\frac {1}{8} (3-e)^2 \text {Subst}\left (\int \frac {1}{x^3} \, dx,x,\log (x)\right ) \\ & = -\frac {(3-e)^2}{16 \log ^2(x)}-\frac {(3-e) x}{2 \log (x)}-\frac {1}{4} \left (1-2 x-4 \log ^2(\log (4))\right )^2 \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(62\) vs. \(2(29)=58\).
Time = 0.08 (sec) , antiderivative size = 62, normalized size of antiderivative = 2.14 \[ \int \frac {9-6 e+e^2+(12 x-4 e x) \log (x)+(-12 x+4 e x) \log ^2(x)+\left (8 x-16 x^2\right ) \log ^3(x)-32 x \log ^3(x) \log ^2(\log (4))}{8 x \log ^3(x)} \, dx=x-x^2-\frac {9}{16 \log ^2(x)}+\frac {3 e}{8 \log ^2(x)}-\frac {e^2}{16 \log ^2(x)}-\frac {3 x}{2 \log (x)}+\frac {e x}{2 \log (x)}-4 x \log ^2(\log (4)) \]
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Time = 0.70 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.97
method | result | size |
risch | \(-4 x \ln \left (2\right )^{2}-8 \ln \left (2\right ) \ln \left (\ln \left (2\right )\right ) x -4 x \ln \left (\ln \left (2\right )\right )^{2}-x^{2}+x -\frac {-8 x \,{\mathrm e} \ln \left (x \right )+{\mathrm e}^{2}+24 x \ln \left (x \right )-6 \,{\mathrm e}+9}{16 \ln \left (x \right )^{2}}\) | \(57\) |
parallelrisch | \(-\frac {16 \ln \left (4 \ln \left (2\right )^{2}\right )^{2} x \ln \left (x \right )^{2}+16 x^{2} \ln \left (x \right )^{2}-8 x \,{\mathrm e} \ln \left (x \right )-16 x \ln \left (x \right )^{2}+9+{\mathrm e}^{2}+24 x \ln \left (x \right )-6 \,{\mathrm e}}{16 \ln \left (x \right )^{2}}\) | \(61\) |
norman | \(\frac {\left (\frac {{\mathrm e}}{2}-\frac {3}{2}\right ) x \ln \left (x \right )+\left (-4 \ln \left (2\right )^{2}-8 \ln \left (2\right ) \ln \left (\ln \left (2\right )\right )-4 \ln \left (\ln \left (2\right )\right )^{2}+1\right ) x \ln \left (x \right )^{2}-x^{2} \ln \left (x \right )^{2}-\frac {9}{16}-\frac {{\mathrm e}^{2}}{16}+\frac {3 \,{\mathrm e}}{8}}{\ln \left (x \right )^{2}}\) | \(65\) |
parts | \(x +\left (-\frac {{\mathrm e}}{2}+\frac {3}{2}\right ) \left (-\frac {x}{\ln \left (x \right )}-\operatorname {Ei}_{1}\left (-\ln \left (x \right )\right )\right )-\left (\frac {{\mathrm e}}{2}-\frac {3}{2}\right ) \operatorname {Ei}_{1}\left (-\ln \left (x \right )\right )-x^{2}-\ln \left (4 \ln \left (2\right )^{2}\right )^{2} x -\frac {\frac {{\mathrm e}^{2}}{8}-\frac {3 \,{\mathrm e}}{4}+\frac {9}{8}}{2 \ln \left (x \right )^{2}}\) | \(75\) |
default | \(-4 x \ln \left (2\right )^{2}-8 \ln \left (2\right ) \ln \left (\ln \left (2\right )\right ) x -4 x \ln \left (\ln \left (2\right )\right )^{2}-x^{2}+x -\frac {{\mathrm e} \,\operatorname {Ei}_{1}\left (-\ln \left (x \right )\right )}{2}-\frac {{\mathrm e} \left (-\frac {x}{\ln \left (x \right )}-\operatorname {Ei}_{1}\left (-\ln \left (x \right )\right )\right )}{2}-\frac {3 x}{2 \ln \left (x \right )}-\frac {{\mathrm e}^{2}}{16 \ln \left (x \right )^{2}}+\frac {3 \,{\mathrm e}}{8 \ln \left (x \right )^{2}}-\frac {9}{16 \ln \left (x \right )^{2}}\) | \(92\) |
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Time = 0.25 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.90 \[ \int \frac {9-6 e+e^2+(12 x-4 e x) \log (x)+(-12 x+4 e x) \log ^2(x)+\left (8 x-16 x^2\right ) \log ^3(x)-32 x \log ^3(x) \log ^2(\log (4))}{8 x \log ^3(x)} \, dx=-\frac {16 \, x \log \left (4 \, \log \left (2\right )^{2}\right )^{2} \log \left (x\right )^{2} + 16 \, {\left (x^{2} - x\right )} \log \left (x\right )^{2} - 8 \, {\left (x e - 3 \, x\right )} \log \left (x\right ) + e^{2} - 6 \, e + 9}{16 \, \log \left (x\right )^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 61 vs. \(2 (27) = 54\).
Time = 0.07 (sec) , antiderivative size = 61, normalized size of antiderivative = 2.10 \[ \int \frac {9-6 e+e^2+(12 x-4 e x) \log (x)+(-12 x+4 e x) \log ^2(x)+\left (8 x-16 x^2\right ) \log ^3(x)-32 x \log ^3(x) \log ^2(\log (4))}{8 x \log ^3(x)} \, dx=- x^{2} + x \left (- 4 \log {\left (2 \right )}^{2} - 4 \log {\left (\log {\left (2 \right )} \right )}^{2} + 1 - 8 \log {\left (2 \right )} \log {\left (\log {\left (2 \right )} \right )}\right ) + \frac {\left (- 24 x + 8 e x\right ) \log {\left (x \right )} - 9 - e^{2} + 6 e}{16 \log {\left (x \right )}^{2}} \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 0.24 (sec) , antiderivative size = 71, normalized size of antiderivative = 2.45 \[ \int \frac {9-6 e+e^2+(12 x-4 e x) \log (x)+(-12 x+4 e x) \log ^2(x)+\left (8 x-16 x^2\right ) \log ^3(x)-32 x \log ^3(x) \log ^2(\log (4))}{8 x \log ^3(x)} \, dx=-x \log \left (4 \, \log \left (2\right )^{2}\right )^{2} - x^{2} + \frac {1}{2} \, {\rm Ei}\left (\log \left (x\right )\right ) e - \frac {1}{2} \, e \Gamma \left (-1, -\log \left (x\right )\right ) + x - \frac {e^{2}}{16 \, \log \left (x\right )^{2}} + \frac {3 \, e}{8 \, \log \left (x\right )^{2}} - \frac {9}{16 \, \log \left (x\right )^{2}} - \frac {3}{2} \, {\rm Ei}\left (\log \left (x\right )\right ) + \frac {3}{2} \, \Gamma \left (-1, -\log \left (x\right )\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 77 vs. \(2 (32) = 64\).
Time = 0.27 (sec) , antiderivative size = 77, normalized size of antiderivative = 2.66 \[ \int \frac {9-6 e+e^2+(12 x-4 e x) \log (x)+(-12 x+4 e x) \log ^2(x)+\left (8 x-16 x^2\right ) \log ^3(x)-32 x \log ^3(x) \log ^2(\log (4))}{8 x \log ^3(x)} \, dx=-\frac {64 \, x \log \left (2\right )^{2} \log \left (x\right )^{2} + 128 \, x \log \left (2\right ) \log \left (x\right )^{2} \log \left (\log \left (2\right )\right ) + 64 \, x \log \left (x\right )^{2} \log \left (\log \left (2\right )\right )^{2} + 16 \, x^{2} \log \left (x\right )^{2} - 8 \, x e \log \left (x\right ) - 16 \, x \log \left (x\right )^{2} + 24 \, x \log \left (x\right ) + e^{2} - 6 \, e + 9}{16 \, \log \left (x\right )^{2}} \]
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Time = 8.89 (sec) , antiderivative size = 62, normalized size of antiderivative = 2.14 \[ \int \frac {9-6 e+e^2+(12 x-4 e x) \log (x)+(-12 x+4 e x) \log ^2(x)+\left (8 x-16 x^2\right ) \log ^3(x)-32 x \log ^3(x) \log ^2(\log (4))}{8 x \log ^3(x)} \, dx=-\frac {x^4+\frac {x^3\,\left (8\,{\ln \left (4\,{\ln \left (2\right )}^2\right )}^2-8\right )}{8}}{x^2}-\frac {\frac {x^2\,{\left (\mathrm {e}-3\right )}^2}{16}-\frac {x^3\,\ln \left (x\right )\,\left (4\,\mathrm {e}-12\right )}{8}}{x^2\,{\ln \left (x\right )}^2} \]
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