Integrand size = 65, antiderivative size = 26 \[ \int e^{-9+4 e^{e^{-9-x} x}-x} \left (e^{9+x} \left (4-4 e^x\right )+e^{e^{-9-x} x} \left (16 x-16 x^2+e^x (-16+16 x)\right )\right ) \, dx=1+4 e^{4 e^{e^{-9-x} x}} \left (-e^x+x\right ) \]
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\[ \int e^{-9+4 e^{e^{-9-x} x}-x} \left (e^{9+x} \left (4-4 e^x\right )+e^{e^{-9-x} x} \left (16 x-16 x^2+e^x (-16+16 x)\right )\right ) \, dx=\int e^{-9+4 e^{e^{-9-x} x}-x} \left (e^{9+x} \left (4-4 e^x\right )+e^{e^{-9-x} x} \left (16 x-16 x^2+e^x (-16+16 x)\right )\right ) \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (-4 e^{4 e^{e^{-9-x} x}} \left (-1+e^x\right )+16 e^{-9+4 e^{e^{-9-x} x}-x+e^{-9-x} x} \left (e^x-x\right ) (-1+x)\right ) \, dx \\ & = -\left (4 \int e^{4 e^{e^{-9-x} x}} \left (-1+e^x\right ) \, dx\right )+16 \int e^{-9+4 e^{e^{-9-x} x}-x+e^{-9-x} x} \left (e^x-x\right ) (-1+x) \, dx \\ & = -\left (4 \int \left (-e^{4 e^{e^{-9-x} x}}+e^{4 e^{e^{-9-x} x}+x}\right ) \, dx\right )+16 \int \left (e^{-9+4 e^{e^{-9-x} x}+e^{-9-x} x} (-1+x)-e^{-9+4 e^{e^{-9-x} x}-x+e^{-9-x} x} (-1+x) x\right ) \, dx \\ & = 4 \int e^{4 e^{e^{-9-x} x}} \, dx-4 \int e^{4 e^{e^{-9-x} x}+x} \, dx+16 \int e^{-9+4 e^{e^{-9-x} x}+e^{-9-x} x} (-1+x) \, dx-16 \int e^{-9+4 e^{e^{-9-x} x}-x+e^{-9-x} x} (-1+x) x \, dx \\ & = 4 \int e^{4 e^{e^{-9-x} x}} \, dx-4 \int e^{4 e^{e^{-9-x} x}+x} \, dx+16 \int \left (-e^{-9+4 e^{e^{-9-x} x}+e^{-9-x} x}+e^{-9+4 e^{e^{-9-x} x}+e^{-9-x} x} x\right ) \, dx-16 \int \left (-e^{-9+4 e^{e^{-9-x} x}-x+e^{-9-x} x} x+e^{-9+4 e^{e^{-9-x} x}-x+e^{-9-x} x} x^2\right ) \, dx \\ & = 4 \int e^{4 e^{e^{-9-x} x}} \, dx-4 \int e^{4 e^{e^{-9-x} x}+x} \, dx-16 \int e^{-9+4 e^{e^{-9-x} x}+e^{-9-x} x} \, dx+16 \int e^{-9+4 e^{e^{-9-x} x}+e^{-9-x} x} x \, dx+16 \int e^{-9+4 e^{e^{-9-x} x}-x+e^{-9-x} x} x \, dx-16 \int e^{-9+4 e^{e^{-9-x} x}-x+e^{-9-x} x} x^2 \, dx \\ \end{align*}
Time = 5.07 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.96 \[ \int e^{-9+4 e^{e^{-9-x} x}-x} \left (e^{9+x} \left (4-4 e^x\right )+e^{e^{-9-x} x} \left (16 x-16 x^2+e^x (-16+16 x)\right )\right ) \, dx=e^{4 e^{e^{-9-x} x}} \left (-4 e^x+4 x\right ) \]
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Time = 2.93 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.81
method | result | size |
risch | \(4 \left (x -{\mathrm e}^{x}\right ) {\mathrm e}^{4 \,{\mathrm e}^{x \,{\mathrm e}^{-x -9}}}\) | \(21\) |
parallelrisch | \(\left (4 \,{\mathrm e}^{4 \,{\mathrm e}^{x \,{\mathrm e}^{-x -9}}} x \,{\mathrm e}^{2 x +18}-4 \,{\mathrm e}^{4 \,{\mathrm e}^{x \,{\mathrm e}^{-x -9}}} {\mathrm e}^{x} {\mathrm e}^{2 x +18}\right ) {\mathrm e}^{-2 x -18}\) | \(52\) |
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Time = 0.24 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.31 \[ \int e^{-9+4 e^{e^{-9-x} x}-x} \left (e^{9+x} \left (4-4 e^x\right )+e^{e^{-9-x} x} \left (16 x-16 x^2+e^x (-16+16 x)\right )\right ) \, dx=4 \, {\left (x e^{\left (x + 18\right )} - e^{\left (2 \, x + 18\right )}\right )} e^{\left (-x + 4 \, e^{\left (x e^{\left (-x - 9\right )}\right )} - 18\right )} \]
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Timed out. \[ \int e^{-9+4 e^{e^{-9-x} x}-x} \left (e^{9+x} \left (4-4 e^x\right )+e^{e^{-9-x} x} \left (16 x-16 x^2+e^x (-16+16 x)\right )\right ) \, dx=\text {Timed out} \]
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Time = 0.25 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.77 \[ \int e^{-9+4 e^{e^{-9-x} x}-x} \left (e^{9+x} \left (4-4 e^x\right )+e^{e^{-9-x} x} \left (16 x-16 x^2+e^x (-16+16 x)\right )\right ) \, dx=4 \, {\left (x - e^{x}\right )} e^{\left (4 \, e^{\left (x e^{\left (-x - 9\right )}\right )}\right )} \]
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\[ \int e^{-9+4 e^{e^{-9-x} x}-x} \left (e^{9+x} \left (4-4 e^x\right )+e^{e^{-9-x} x} \left (16 x-16 x^2+e^x (-16+16 x)\right )\right ) \, dx=\int { -4 \, {\left (4 \, {\left (x^{2} - {\left (x - 1\right )} e^{x} - x\right )} e^{\left (x e^{\left (-x - 9\right )}\right )} + {\left (e^{x} - 1\right )} e^{\left (x + 9\right )}\right )} e^{\left (-x + 4 \, e^{\left (x e^{\left (-x - 9\right )}\right )} - 9\right )} \,d x } \]
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Time = 9.00 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.77 \[ \int e^{-9+4 e^{e^{-9-x} x}-x} \left (e^{9+x} \left (4-4 e^x\right )+e^{e^{-9-x} x} \left (16 x-16 x^2+e^x (-16+16 x)\right )\right ) \, dx=4\,{\mathrm {e}}^{4\,{\mathrm {e}}^{x\,{\mathrm {e}}^{-x}\,{\mathrm {e}}^{-9}}}\,\left (x-{\mathrm {e}}^x\right ) \]
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