Integrand size = 107, antiderivative size = 29 \[ \int \frac {e^3 \left (-100 x^3+24 x^4\right )-2 e^3 x^4 \log (4)+2 e^3 x^4 \log (4) \log (x)}{-15625+22500 x-10800 x^2+1728 x^3+\left (1875 x-1800 x^2+432 x^3\right ) \log (4) \log (x)+\left (-75 x^2+36 x^3\right ) \log ^2(4) \log ^2(x)+x^3 \log ^3(4) \log ^3(x)} \, dx=\frac {e^3 x^2}{\left (-2+\frac {(-5+x)^2}{x}-x-\log (4) \log (x)\right )^2} \]
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\[ \int \frac {e^3 \left (-100 x^3+24 x^4\right )-2 e^3 x^4 \log (4)+2 e^3 x^4 \log (4) \log (x)}{-15625+22500 x-10800 x^2+1728 x^3+\left (1875 x-1800 x^2+432 x^3\right ) \log (4) \log (x)+\left (-75 x^2+36 x^3\right ) \log ^2(4) \log ^2(x)+x^3 \log ^3(4) \log ^3(x)} \, dx=\int \frac {e^3 \left (-100 x^3+24 x^4\right )-2 e^3 x^4 \log (4)+2 e^3 x^4 \log (4) \log (x)}{-15625+22500 x-10800 x^2+1728 x^3+\left (1875 x-1800 x^2+432 x^3\right ) \log (4) \log (x)+\left (-75 x^2+36 x^3\right ) \log ^2(4) \log ^2(x)+x^3 \log ^3(4) \log ^3(x)} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {2 e^3 x^3 (50+x (-12+\log (4))-x \log (4) \log (x))}{(25-12 x-x \log (4) \log (x))^3} \, dx \\ & = \left (2 e^3\right ) \int \frac {x^3 (50+x (-12+\log (4))-x \log (4) \log (x))}{(25-12 x-x \log (4) \log (x))^3} \, dx \\ & = \left (2 e^3\right ) \int \left (-\frac {x^3 (25+x \log (4))}{(-25+12 x+x \log (4) \log (x))^3}+\frac {x^3}{(-25+12 x+x \log (4) \log (x))^2}\right ) \, dx \\ & = -\left (\left (2 e^3\right ) \int \frac {x^3 (25+x \log (4))}{(-25+12 x+x \log (4) \log (x))^3} \, dx\right )+\left (2 e^3\right ) \int \frac {x^3}{(-25+12 x+x \log (4) \log (x))^2} \, dx \\ & = \left (2 e^3\right ) \int \frac {x^3}{(-25+12 x+x \log (4) \log (x))^2} \, dx-\left (2 e^3\right ) \int \left (\frac {25 x^3}{(-25+12 x+x \log (4) \log (x))^3}+\frac {x^4 \log (4)}{(-25+12 x+x \log (4) \log (x))^3}\right ) \, dx \\ & = \left (2 e^3\right ) \int \frac {x^3}{(-25+12 x+x \log (4) \log (x))^2} \, dx-\left (50 e^3\right ) \int \frac {x^3}{(-25+12 x+x \log (4) \log (x))^3} \, dx-\left (2 e^3 \log (4)\right ) \int \frac {x^4}{(-25+12 x+x \log (4) \log (x))^3} \, dx \\ \end{align*}
Time = 5.02 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.69 \[ \int \frac {e^3 \left (-100 x^3+24 x^4\right )-2 e^3 x^4 \log (4)+2 e^3 x^4 \log (4) \log (x)}{-15625+22500 x-10800 x^2+1728 x^3+\left (1875 x-1800 x^2+432 x^3\right ) \log (4) \log (x)+\left (-75 x^2+36 x^3\right ) \log ^2(4) \log ^2(x)+x^3 \log ^3(4) \log ^3(x)} \, dx=\frac {e^3 x^4}{(-25+12 x+x \log (4) \log (x))^2} \]
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Time = 7.29 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.72
method | result | size |
default | \(\frac {{\mathrm e}^{3} x^{4}}{\left (2 x \ln \left (2\right ) \ln \left (x \right )+12 x -25\right )^{2}}\) | \(21\) |
norman | \(\frac {{\mathrm e}^{3} x^{4}}{\left (2 x \ln \left (2\right ) \ln \left (x \right )+12 x -25\right )^{2}}\) | \(21\) |
risch | \(\frac {{\mathrm e}^{3} x^{4}}{\left (2 x \ln \left (2\right ) \ln \left (x \right )+12 x -25\right )^{2}}\) | \(21\) |
parallelrisch | \(\frac {x^{4} {\mathrm e}^{3}}{4 \ln \left (x \right )^{2} \ln \left (2\right )^{2} x^{2}+48 x^{2} \ln \left (2\right ) \ln \left (x \right )-100 x \ln \left (2\right ) \ln \left (x \right )+144 x^{2}-600 x +625}\) | \(48\) |
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Time = 0.29 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.59 \[ \int \frac {e^3 \left (-100 x^3+24 x^4\right )-2 e^3 x^4 \log (4)+2 e^3 x^4 \log (4) \log (x)}{-15625+22500 x-10800 x^2+1728 x^3+\left (1875 x-1800 x^2+432 x^3\right ) \log (4) \log (x)+\left (-75 x^2+36 x^3\right ) \log ^2(4) \log ^2(x)+x^3 \log ^3(4) \log ^3(x)} \, dx=\frac {x^{4} e^{3}}{4 \, x^{2} \log \left (2\right )^{2} \log \left (x\right )^{2} + 4 \, {\left (12 \, x^{2} - 25 \, x\right )} \log \left (2\right ) \log \left (x\right ) + 144 \, x^{2} - 600 \, x + 625} \]
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Time = 0.13 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.69 \[ \int \frac {e^3 \left (-100 x^3+24 x^4\right )-2 e^3 x^4 \log (4)+2 e^3 x^4 \log (4) \log (x)}{-15625+22500 x-10800 x^2+1728 x^3+\left (1875 x-1800 x^2+432 x^3\right ) \log (4) \log (x)+\left (-75 x^2+36 x^3\right ) \log ^2(4) \log ^2(x)+x^3 \log ^3(4) \log ^3(x)} \, dx=\frac {x^{4} e^{3}}{4 x^{2} \log {\left (2 \right )}^{2} \log {\left (x \right )}^{2} + 144 x^{2} - 600 x + \left (48 x^{2} \log {\left (2 \right )} - 100 x \log {\left (2 \right )}\right ) \log {\left (x \right )} + 625} \]
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Time = 0.32 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.66 \[ \int \frac {e^3 \left (-100 x^3+24 x^4\right )-2 e^3 x^4 \log (4)+2 e^3 x^4 \log (4) \log (x)}{-15625+22500 x-10800 x^2+1728 x^3+\left (1875 x-1800 x^2+432 x^3\right ) \log (4) \log (x)+\left (-75 x^2+36 x^3\right ) \log ^2(4) \log ^2(x)+x^3 \log ^3(4) \log ^3(x)} \, dx=\frac {x^{4} e^{3}}{4 \, x^{2} \log \left (2\right )^{2} \log \left (x\right )^{2} + 144 \, x^{2} + 4 \, {\left (12 \, x^{2} \log \left (2\right ) - 25 \, x \log \left (2\right )\right )} \log \left (x\right ) - 600 \, x + 625} \]
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Time = 0.27 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.62 \[ \int \frac {e^3 \left (-100 x^3+24 x^4\right )-2 e^3 x^4 \log (4)+2 e^3 x^4 \log (4) \log (x)}{-15625+22500 x-10800 x^2+1728 x^3+\left (1875 x-1800 x^2+432 x^3\right ) \log (4) \log (x)+\left (-75 x^2+36 x^3\right ) \log ^2(4) \log ^2(x)+x^3 \log ^3(4) \log ^3(x)} \, dx=\frac {x^{4} e^{3}}{4 \, x^{2} \log \left (2\right )^{2} \log \left (x\right )^{2} + 48 \, x^{2} \log \left (2\right ) \log \left (x\right ) - 100 \, x \log \left (2\right ) \log \left (x\right ) + 144 \, x^{2} - 600 \, x + 625} \]
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Timed out. \[ \int \frac {e^3 \left (-100 x^3+24 x^4\right )-2 e^3 x^4 \log (4)+2 e^3 x^4 \log (4) \log (x)}{-15625+22500 x-10800 x^2+1728 x^3+\left (1875 x-1800 x^2+432 x^3\right ) \log (4) \log (x)+\left (-75 x^2+36 x^3\right ) \log ^2(4) \log ^2(x)+x^3 \log ^3(4) \log ^3(x)} \, dx=\int -\frac {{\mathrm {e}}^3\,\left (100\,x^3-24\,x^4\right )+4\,x^4\,{\mathrm {e}}^3\,\ln \left (2\right )-4\,x^4\,{\mathrm {e}}^3\,\ln \left (2\right )\,\ln \left (x\right )}{22500\,x-10800\,x^2+1728\,x^3-4\,{\ln \left (2\right )}^2\,{\ln \left (x\right )}^2\,\left (75\,x^2-36\,x^3\right )+8\,x^3\,{\ln \left (2\right )}^3\,{\ln \left (x\right )}^3+2\,\ln \left (2\right )\,\ln \left (x\right )\,\left (432\,x^3-1800\,x^2+1875\,x\right )-15625} \,d x \]
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