\(\int \frac {4+2 x^3+8 \log (\frac {5}{x})+e^{x^{\frac {1}{x}}} x^{\frac {1}{x}} (x-x \log (x))}{x^3} \, dx\) [3805]

   Optimal result
   Rubi [F]
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 39, antiderivative size = 25 \[ \int \frac {4+2 x^3+8 \log \left (\frac {5}{x}\right )+e^{x^{\frac {1}{x}}} x^{\frac {1}{x}} (x-x \log (x))}{x^3} \, dx=\frac {3}{4}+e^{x^{\frac {1}{x}}}+2 x-\frac {4 \log \left (\frac {5}{x}\right )}{x^2} \]

[Out]

exp(exp(ln(x)/x))+2*x+3/4-4*ln(5/x)/x^2

Rubi [F]

\[ \int \frac {4+2 x^3+8 \log \left (\frac {5}{x}\right )+e^{x^{\frac {1}{x}}} x^{\frac {1}{x}} (x-x \log (x))}{x^3} \, dx=\int \frac {4+2 x^3+8 \log \left (\frac {5}{x}\right )+e^{x^{\frac {1}{x}}} x^{\frac {1}{x}} (x-x \log (x))}{x^3} \, dx \]

[In]

Int[(4 + 2*x^3 + 8*Log[5/x] + E^x^x^(-1)*x^x^(-1)*(x - x*Log[x]))/x^3,x]

[Out]

2*x - (4*Log[5/x])/x^2 + Defer[Int][E^x^x^(-1)*x^(-2 + x^(-1)), x] - Log[x]*Defer[Int][E^x^x^(-1)*x^(-2 + x^(-
1)), x] + Defer[Int][Defer[Int][E^x^x^(-1)*x^(-2 + x^(-1)), x]/x, x]

Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {2 \left (2+x^3+4 \log \left (\frac {5}{x}\right )\right )}{x^3}-e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} (-1+\log (x))\right ) \, dx \\ & = 2 \int \frac {2+x^3+4 \log \left (\frac {5}{x}\right )}{x^3} \, dx-\int e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} (-1+\log (x)) \, dx \\ & = 2 \int \left (\frac {2+x^3}{x^3}+\frac {4 \log \left (\frac {5}{x}\right )}{x^3}\right ) \, dx-\int \left (-e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}}+e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} \log (x)\right ) \, dx \\ & = 2 \int \frac {2+x^3}{x^3} \, dx+8 \int \frac {\log \left (\frac {5}{x}\right )}{x^3} \, dx+\int e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} \, dx-\int e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} \log (x) \, dx \\ & = \frac {2}{x^2}-\frac {4 \log \left (\frac {5}{x}\right )}{x^2}+2 \int \left (1+\frac {2}{x^3}\right ) \, dx-\log (x) \int e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} \, dx+\int e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} \, dx+\int \frac {\int e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} \, dx}{x} \, dx \\ & = 2 x-\frac {4 \log \left (\frac {5}{x}\right )}{x^2}-\log (x) \int e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} \, dx+\int e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} \, dx+\int \frac {\int e^{x^{\frac {1}{x}}} x^{-2+\frac {1}{x}} \, dx}{x} \, dx \\ \end{align*}

Mathematica [A] (verified)

Time = 0.11 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.88 \[ \int \frac {4+2 x^3+8 \log \left (\frac {5}{x}\right )+e^{x^{\frac {1}{x}}} x^{\frac {1}{x}} (x-x \log (x))}{x^3} \, dx=e^{x^{\frac {1}{x}}}+2 x-\frac {4 \log \left (\frac {5}{x}\right )}{x^2} \]

[In]

Integrate[(4 + 2*x^3 + 8*Log[5/x] + E^x^x^(-1)*x^x^(-1)*(x - x*Log[x]))/x^3,x]

[Out]

E^x^x^(-1) + 2*x - (4*Log[5/x])/x^2

Maple [A] (verified)

Time = 2.72 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.20

method result size
risch \(\frac {4 \ln \left (x \right )}{x^{2}}-\frac {2 \left (-x^{3}+2 \ln \left (5\right )\right )}{x^{2}}+{\mathrm e}^{x^{\frac {1}{x}}}\) \(30\)
parallelrisch \(-\frac {-4 x^{3}-2 \,{\mathrm e}^{{\mathrm e}^{\frac {\ln \left (x \right )}{x}}} x^{2}+8 \ln \left (\frac {5}{x}\right )}{2 x^{2}}\) \(33\)
default \({\mathrm e}^{{\mathrm e}^{\frac {\ln \left (x \right )}{x}}}-\frac {4 \ln \left (\frac {1}{x}\right )}{x^{2}}+\frac {2}{x^{2}}-\frac {4 \ln \left (5\right )+2}{x^{2}}+2 x\) \(38\)

[In]

int(((x-x*ln(x))*exp(ln(x)/x)*exp(exp(ln(x)/x))+8*ln(5/x)+2*x^3+4)/x^3,x,method=_RETURNVERBOSE)

[Out]

4*ln(x)/x^2-2*(-x^3+2*ln(5))/x^2+exp(x^(1/x))

Fricas [A] (verification not implemented)

none

Time = 0.26 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.56 \[ \int \frac {4+2 x^3+8 \log \left (\frac {5}{x}\right )+e^{x^{\frac {1}{x}}} x^{\frac {1}{x}} (x-x \log (x))}{x^3} \, dx=\frac {2 \, x^{3} + x^{2} e^{\left (e^{\left (\frac {\log \left (5\right ) - \log \left (\frac {5}{x}\right )}{x}\right )}\right )} - 4 \, \log \left (\frac {5}{x}\right )}{x^{2}} \]

[In]

integrate(((x-x*log(x))*exp(log(x)/x)*exp(exp(log(x)/x))+8*log(5/x)+2*x^3+4)/x^3,x, algorithm="fricas")

[Out]

(2*x^3 + x^2*e^(e^((log(5) - log(5/x))/x)) - 4*log(5/x))/x^2

Sympy [A] (verification not implemented)

Time = 0.27 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.08 \[ \int \frac {4+2 x^3+8 \log \left (\frac {5}{x}\right )+e^{x^{\frac {1}{x}}} x^{\frac {1}{x}} (x-x \log (x))}{x^3} \, dx=2 x + e^{e^{\frac {\log {\left (x \right )}}{x}}} + \frac {4 \log {\left (x \right )}}{x^{2}} - \frac {4 \log {\left (5 \right )}}{x^{2}} \]

[In]

integrate(((x-x*ln(x))*exp(ln(x)/x)*exp(exp(ln(x)/x))+8*ln(5/x)+2*x**3+4)/x**3,x)

[Out]

2*x + exp(exp(log(x)/x)) + 4*log(x)/x**2 - 4*log(5)/x**2

Maxima [A] (verification not implemented)

none

Time = 0.25 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.84 \[ \int \frac {4+2 x^3+8 \log \left (\frac {5}{x}\right )+e^{x^{\frac {1}{x}}} x^{\frac {1}{x}} (x-x \log (x))}{x^3} \, dx=2 \, x - \frac {4 \, \log \left (\frac {5}{x}\right )}{x^{2}} + e^{\left (x^{\left (\frac {1}{x}\right )}\right )} \]

[In]

integrate(((x-x*log(x))*exp(log(x)/x)*exp(exp(log(x)/x))+8*log(5/x)+2*x^3+4)/x^3,x, algorithm="maxima")

[Out]

2*x - 4*log(5/x)/x^2 + e^(x^(1/x))

Giac [A] (verification not implemented)

none

Time = 0.30 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.96 \[ \int \frac {4+2 x^3+8 \log \left (\frac {5}{x}\right )+e^{x^{\frac {1}{x}}} x^{\frac {1}{x}} (x-x \log (x))}{x^3} \, dx=2 \, x - \frac {4 \, \log \left (5\right )}{x^{2}} + \frac {4 \, \log \left (x\right )}{x^{2}} + e^{\left (x^{\left (\frac {1}{x}\right )}\right )} \]

[In]

integrate(((x-x*log(x))*exp(log(x)/x)*exp(exp(log(x)/x))+8*log(5/x)+2*x^3+4)/x^3,x, algorithm="giac")

[Out]

2*x - 4*log(5)/x^2 + 4*log(x)/x^2 + e^(x^(1/x))

Mupad [B] (verification not implemented)

Time = 9.53 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.04 \[ \int \frac {4+2 x^3+8 \log \left (\frac {5}{x}\right )+e^{x^{\frac {1}{x}}} x^{\frac {1}{x}} (x-x \log (x))}{x^3} \, dx=2\,x+{\mathrm {e}}^{x^{1/x}}-\frac {4\,\ln \left (\frac {1}{x}\right )}{x^2}-\frac {4\,\ln \left (5\right )}{x^2} \]

[In]

int((8*log(5/x) + 2*x^3 + exp(log(x)/x)*exp(exp(log(x)/x))*(x - x*log(x)) + 4)/x^3,x)

[Out]

2*x + exp(x^(1/x)) - (4*log(1/x))/x^2 - (4*log(5))/x^2