Integrand size = 49, antiderivative size = 22 \[ \int \frac {1}{3} \left (-3+e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right )\right ) \, dx=e^{\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )}-x \]
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\[ \int \frac {1}{3} \left (-3+e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right )\right ) \, dx=\int \frac {1}{3} \left (-3+e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right )\right ) \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \int \left (-3+e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right )\right ) \, dx \\ & = -x+\frac {1}{3} \int e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right ) \, dx \\ & = -x+\frac {1}{3} \int e^{\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right ) \, dx \\ & = -x+\frac {1}{3} \int \left (-10 e^{\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )}+2 e^{2 x+\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )}+e^{x+\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} (-3+2 x)\right ) \, dx \\ & = -x+\frac {1}{3} \int e^{x+\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} (-3+2 x) \, dx+\frac {2}{3} \int e^{2 x+\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} \, dx-\frac {10}{3} \int e^{\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} \, dx \\ & = -x+\frac {1}{3} \int \left (-3 e^{x+\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )}+2 e^{x+\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} x\right ) \, dx+\frac {2}{3} \int e^{2 x+\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} \, dx-\frac {10}{3} \int e^{\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} \, dx \\ & = -x+\frac {2}{3} \int e^{2 x+\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} \, dx+\frac {2}{3} \int e^{x+\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} x \, dx-\frac {10}{3} \int e^{\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} \, dx-\int e^{x+\frac {1}{3} \left (-5+e^x\right ) \left (e^x+2 x\right )} \, dx \\ \end{align*}
Time = 0.76 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.23 \[ \int \frac {1}{3} \left (-3+e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right )\right ) \, dx=e^{-\frac {10 x}{3}+\frac {1}{3} e^x \left (-5+e^x+2 x\right )}-x \]
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Time = 0.56 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.14
method | result | size |
default | \(-x +{\mathrm e}^{\frac {{\mathrm e}^{2 x}}{3}+\frac {\left (-5+2 x \right ) {\mathrm e}^{x}}{3}-\frac {10 x}{3}}\) | \(25\) |
norman | \(-x +{\mathrm e}^{\frac {{\mathrm e}^{2 x}}{3}+\frac {\left (-5+2 x \right ) {\mathrm e}^{x}}{3}-\frac {10 x}{3}}\) | \(25\) |
risch | \(-x +{\mathrm e}^{\frac {{\mathrm e}^{2 x}}{3}+\frac {2 \,{\mathrm e}^{x} x}{3}-\frac {5 \,{\mathrm e}^{x}}{3}-\frac {10 x}{3}}\) | \(25\) |
parallelrisch | \(-x +{\mathrm e}^{\frac {{\mathrm e}^{2 x}}{3}+\frac {\left (-5+2 x \right ) {\mathrm e}^{x}}{3}-\frac {10 x}{3}}\) | \(25\) |
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Time = 0.25 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {1}{3} \left (-3+e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right )\right ) \, dx=-x + e^{\left (\frac {1}{3} \, {\left (2 \, x - 5\right )} e^{x} - \frac {10}{3} \, x + \frac {1}{3} \, e^{\left (2 \, x\right )}\right )} \]
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Time = 0.14 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.18 \[ \int \frac {1}{3} \left (-3+e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right )\right ) \, dx=- x + e^{- \frac {10 x}{3} + \left (\frac {2 x}{3} - \frac {5}{3}\right ) e^{x} + \frac {e^{2 x}}{3}} \]
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\[ \int \frac {1}{3} \left (-3+e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right )\right ) \, dx=\int { \frac {1}{3} \, {\left ({\left (2 \, x - 3\right )} e^{x} + 2 \, e^{\left (2 \, x\right )} - 10\right )} e^{\left (\frac {1}{3} \, {\left (2 \, x - 5\right )} e^{x} - \frac {10}{3} \, x + \frac {1}{3} \, e^{\left (2 \, x\right )}\right )} - 1 \,d x } \]
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Time = 0.27 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {1}{3} \left (-3+e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right )\right ) \, dx=-x + e^{\left (\frac {2}{3} \, x e^{x} - \frac {10}{3} \, x + \frac {1}{3} \, e^{\left (2 \, x\right )} - \frac {5}{3} \, e^{x}\right )} \]
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Time = 0.12 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {1}{3} \left (-3+e^{\frac {1}{3} \left (e^{2 x}-10 x+e^x (-5+2 x)\right )} \left (-10+2 e^{2 x}+e^x (-3+2 x)\right )\right ) \, dx={\mathrm {e}}^{\frac {{\mathrm {e}}^{2\,x}}{3}-\frac {10\,x}{3}-\frac {5\,{\mathrm {e}}^x}{3}+\frac {2\,x\,{\mathrm {e}}^x}{3}}-x \]
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