Integrand size = 36, antiderivative size = 30 \[ \int \left (1-i \pi -2 x-6 x^2-\log \left (1+e^5\right )-4 x \log \left (4 x+e^4 x\right )\right ) \, dx=x \left (1-i \pi -\log \left (1+e^5\right )-2 x \left (x+\log \left (\left (4+e^4\right ) x\right )\right )\right ) \]
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Time = 0.02 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.20, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {2468, 2341} \[ \int \left (1-i \pi -2 x-6 x^2-\log \left (1+e^5\right )-4 x \log \left (4 x+e^4 x\right )\right ) \, dx=-2 x^3-2 x^2 \log \left (\left (4+e^4\right ) x\right )+x \left (1-i \pi -\log \left (1+e^5\right )\right ) \]
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Rule 2341
Rule 2468
Rubi steps \begin{align*} \text {integral}& = -x^2-2 x^3+x \left (1-i \pi -\log \left (1+e^5\right )\right )-4 \int x \log \left (4 x+e^4 x\right ) \, dx \\ & = -x^2-2 x^3+x \left (1-i \pi -\log \left (1+e^5\right )\right )-4 \int x \log \left (\left (4+e^4\right ) x\right ) \, dx \\ & = -2 x^3+x \left (1-i \pi -\log \left (1+e^5\right )\right )-2 x^2 \log \left (\left (4+e^4\right ) x\right ) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.17 \[ \int \left (1-i \pi -2 x-6 x^2-\log \left (1+e^5\right )-4 x \log \left (4 x+e^4 x\right )\right ) \, dx=x-i \pi x-2 x^3-x \log \left (1+e^5\right )-2 x^2 \log \left (\left (4+e^4\right ) x\right ) \]
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Time = 1.16 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.07
method | result | size |
risch | \(-2 x^{2} \ln \left (x \,{\mathrm e}^{4}+4 x \right )-\ln \left (-{\mathrm e}^{5}-1\right ) x -2 x^{3}+x\) | \(32\) |
norman | \(\left (-\ln \left (-{\mathrm e}^{5}-1\right )+1\right ) x -2 x^{3}-2 x^{2} \ln \left (x \,{\mathrm e}^{4}+4 x \right )\) | \(36\) |
parallelrisch | \(\left (-\ln \left (-{\mathrm e}^{5}-1\right )+1\right ) x -2 x^{3}-2 x^{2} \ln \left (x \,{\mathrm e}^{4}+4 x \right )\) | \(36\) |
default | \(-2 x^{3}-x^{2}+x -\frac {4 \left (\frac {x^{2} \left (4+{\mathrm e}^{4}\right )^{2} \ln \left (x \left (4+{\mathrm e}^{4}\right )\right )}{2}-\frac {x^{2} \left (4+{\mathrm e}^{4}\right )^{2}}{4}\right )}{\left (4+{\mathrm e}^{4}\right )^{2}}-\ln \left (-{\mathrm e}^{5}-1\right ) x\) | \(69\) |
parts | \(-2 x^{3}-x^{2}+x -\frac {4 \left (\frac {x^{2} \left (4+{\mathrm e}^{4}\right )^{2} \ln \left (x \left (4+{\mathrm e}^{4}\right )\right )}{2}-\frac {x^{2} \left (4+{\mathrm e}^{4}\right )^{2}}{4}\right )}{\left (4+{\mathrm e}^{4}\right )^{2}}-\ln \left (-{\mathrm e}^{5}-1\right ) x\) | \(69\) |
derivativedivides | \(\frac {x \left (4+{\mathrm e}^{4}\right )-\left (4+{\mathrm e}^{4}\right ) x^{2}-2 \left (4+{\mathrm e}^{4}\right ) x^{3}-\frac {4 \left (\frac {x^{2} \left (4+{\mathrm e}^{4}\right )^{2} \ln \left (x \left (4+{\mathrm e}^{4}\right )\right )}{2}-\frac {x^{2} \left (4+{\mathrm e}^{4}\right )^{2}}{4}\right )}{4+{\mathrm e}^{4}}-\ln \left (-{\mathrm e}^{5}-1\right ) x \left (4+{\mathrm e}^{4}\right )}{4+{\mathrm e}^{4}}\) | \(103\) |
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Time = 0.25 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.03 \[ \int \left (1-i \pi -2 x-6 x^2-\log \left (1+e^5\right )-4 x \log \left (4 x+e^4 x\right )\right ) \, dx=-2 \, x^{3} - 2 \, x^{2} \log \left (x e^{4} + 4 \, x\right ) - x \log \left (-e^{5} - 1\right ) + x \]
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Time = 0.08 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.23 \[ \int \left (1-i \pi -2 x-6 x^2-\log \left (1+e^5\right )-4 x \log \left (4 x+e^4 x\right )\right ) \, dx=- 2 x^{3} - 2 x^{2} \log {\left (x \right )} - 2 x^{2} \log {\left (4 + e^{4} \right )} + x \left (- \log {\left (1 + e^{5} \right )} + 1 - i \pi \right ) \]
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Time = 0.18 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.03 \[ \int \left (1-i \pi -2 x-6 x^2-\log \left (1+e^5\right )-4 x \log \left (4 x+e^4 x\right )\right ) \, dx=-2 \, x^{3} - 2 \, x^{2} \log \left (x e^{4} + 4 \, x\right ) - x \log \left (-e^{5} - 1\right ) + x \]
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Leaf count of result is larger than twice the leaf count of optimal. 74 vs. \(2 (24) = 48\).
Time = 0.26 (sec) , antiderivative size = 74, normalized size of antiderivative = 2.47 \[ \int \left (1-i \pi -2 x-6 x^2-\log \left (1+e^5\right )-4 x \log \left (4 x+e^4 x\right )\right ) \, dx=-2 \, x^{3} - x^{2} - \frac {2 \, {\left (x e^{4} + 4 \, x\right )}^{2} \log \left (x e^{4} + 4 \, x\right )}{e^{8} + 8 \, e^{4} + 16} - x \log \left (-e^{5} - 1\right ) + x + \frac {{\left (x e^{4} + 4 \, x\right )}^{2}}{e^{8} + 8 \, e^{4} + 16} \]
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Time = 9.88 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.97 \[ \int \left (1-i \pi -2 x-6 x^2-\log \left (1+e^5\right )-4 x \log \left (4 x+e^4 x\right )\right ) \, dx=-x\,\left (\ln \left (-{\mathrm {e}}^5-1\right )+2\,x\,\ln \left (4\,x+x\,{\mathrm {e}}^4\right )+2\,x^2-1\right ) \]
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