Integrand size = 5, antiderivative size = 13 \[ \int (28+2 x) \, dx=2 x+(-4+x) (30+x)+\log (5) \]
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Time = 0.00 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.54, number of steps used = 1, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int (28+2 x) \, dx=x^2+28 x \]
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Rubi steps \begin{align*} \text {integral}& = 28 x+x^2 \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.54 \[ \int (28+2 x) \, dx=28 x+x^2 \]
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Time = 0.20 (sec) , antiderivative size = 6, normalized size of antiderivative = 0.46
method | result | size |
gosper | \(x \left (x +28\right )\) | \(6\) |
default | \(x^{2}+28 x\) | \(8\) |
norman | \(x^{2}+28 x\) | \(8\) |
risch | \(x^{2}+28 x\) | \(8\) |
parallelrisch | \(x^{2}+28 x\) | \(8\) |
parts | \(x^{2}+28 x\) | \(8\) |
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none
Time = 0.24 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.54 \[ \int (28+2 x) \, dx=x^{2} + 28 \, x \]
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Time = 0.02 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.38 \[ \int (28+2 x) \, dx=x^{2} + 28 x \]
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none
Time = 0.17 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.54 \[ \int (28+2 x) \, dx=x^{2} + 28 \, x \]
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none
Time = 0.27 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.54 \[ \int (28+2 x) \, dx=x^{2} + 28 \, x \]
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Time = 0.03 (sec) , antiderivative size = 5, normalized size of antiderivative = 0.38 \[ \int (28+2 x) \, dx=x\,\left (x+28\right ) \]
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