Integrand size = 41, antiderivative size = 22 \[ \int \frac {1}{2} \left (e^x \left (16+e^4 \left (6+x^4\right )\right )+e^{4+x} \left (6+6 x+5 x^4+x^5\right ) \log (x)\right ) \, dx=2 e^x \left (4+\frac {1}{4} e^4 x \left (6+x^4\right ) \log (x)\right ) \]
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Time = 0.18 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.36, number of steps used = 22, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.122, Rules used = {12, 2227, 2225, 2207, 2634} \[ \int \frac {1}{2} \left (e^x \left (16+e^4 \left (6+x^4\right )\right )+e^{4+x} \left (6+6 x+5 x^4+x^5\right ) \log (x)\right ) \, dx=\frac {1}{2} e^{x+4} x^5 \log (x)+8 e^x+3 e^{x+4} x \log (x) \]
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Rule 12
Rule 2207
Rule 2225
Rule 2227
Rule 2634
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \int \left (e^x \left (16+e^4 \left (6+x^4\right )\right )+e^{4+x} \left (6+6 x+5 x^4+x^5\right ) \log (x)\right ) \, dx \\ & = \frac {1}{2} \int e^x \left (16+e^4 \left (6+x^4\right )\right ) \, dx+\frac {1}{2} \int e^{4+x} \left (6+6 x+5 x^4+x^5\right ) \log (x) \, dx \\ & = 3 e^{4+x} x \log (x)+\frac {1}{2} e^{4+x} x^5 \log (x)-\frac {1}{2} \int e^{4+x} \left (6+x^4\right ) \, dx+\frac {1}{2} \int \left (16 e^x+e^{4+x} \left (6+x^4\right )\right ) \, dx \\ & = 3 e^{4+x} x \log (x)+\frac {1}{2} e^{4+x} x^5 \log (x)+\frac {1}{2} \int e^{4+x} \left (6+x^4\right ) \, dx-\frac {1}{2} \int \left (6 e^{4+x}+e^{4+x} x^4\right ) \, dx+8 \int e^x \, dx \\ & = 8 e^x+3 e^{4+x} x \log (x)+\frac {1}{2} e^{4+x} x^5 \log (x)-\frac {1}{2} \int e^{4+x} x^4 \, dx+\frac {1}{2} \int \left (6 e^{4+x}+e^{4+x} x^4\right ) \, dx-3 \int e^{4+x} \, dx \\ & = 8 e^x-3 e^{4+x}-\frac {1}{2} e^{4+x} x^4+3 e^{4+x} x \log (x)+\frac {1}{2} e^{4+x} x^5 \log (x)+\frac {1}{2} \int e^{4+x} x^4 \, dx+2 \int e^{4+x} x^3 \, dx+3 \int e^{4+x} \, dx \\ & = 8 e^x+2 e^{4+x} x^3+3 e^{4+x} x \log (x)+\frac {1}{2} e^{4+x} x^5 \log (x)-2 \int e^{4+x} x^3 \, dx-6 \int e^{4+x} x^2 \, dx \\ & = 8 e^x-6 e^{4+x} x^2+3 e^{4+x} x \log (x)+\frac {1}{2} e^{4+x} x^5 \log (x)+6 \int e^{4+x} x^2 \, dx+12 \int e^{4+x} x \, dx \\ & = 8 e^x+12 e^{4+x} x+3 e^{4+x} x \log (x)+\frac {1}{2} e^{4+x} x^5 \log (x)-12 \int e^{4+x} \, dx-12 \int e^{4+x} x \, dx \\ & = 8 e^x-12 e^{4+x}+3 e^{4+x} x \log (x)+\frac {1}{2} e^{4+x} x^5 \log (x)+12 \int e^{4+x} \, dx \\ & = 8 e^x+3 e^{4+x} x \log (x)+\frac {1}{2} e^{4+x} x^5 \log (x) \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.95 \[ \int \frac {1}{2} \left (e^x \left (16+e^4 \left (6+x^4\right )\right )+e^{4+x} \left (6+6 x+5 x^4+x^5\right ) \log (x)\right ) \, dx=\frac {1}{2} e^x \left (16+e^4 x \left (6+x^4\right ) \log (x)\right ) \]
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Time = 3.23 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.18
method | result | size |
risch | \(\frac {\ln \left (x \right ) {\mathrm e}^{4+x} x^{5}}{2}+3 \ln \left (x \right ) {\mathrm e}^{4+x} x +8 \,{\mathrm e}^{x}\) | \(26\) |
parallelrisch | \(\frac {\ln \left (x \right ) {\mathrm e}^{4} {\mathrm e}^{x} x^{5}}{2}+3 \ln \left (x \right ) {\mathrm e}^{4} {\mathrm e}^{x} x +8 \,{\mathrm e}^{x}\) | \(26\) |
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Time = 0.27 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.14 \[ \int \frac {1}{2} \left (e^x \left (16+e^4 \left (6+x^4\right )\right )+e^{4+x} \left (6+6 x+5 x^4+x^5\right ) \log (x)\right ) \, dx=\frac {1}{2} \, {\left ({\left (x^{5} + 6 \, x\right )} e^{\left (x + 8\right )} \log \left (x\right ) + 16 \, e^{\left (x + 4\right )}\right )} e^{\left (-4\right )} \]
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Time = 0.13 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.18 \[ \int \frac {1}{2} \left (e^x \left (16+e^4 \left (6+x^4\right )\right )+e^{4+x} \left (6+6 x+5 x^4+x^5\right ) \log (x)\right ) \, dx=\frac {\left (x^{5} e^{4} \log {\left (x \right )} + 6 x e^{4} \log {\left (x \right )} + 16\right ) e^{x}}{2} \]
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Leaf count of result is larger than twice the leaf count of optimal. 97 vs. \(2 (17) = 34\).
Time = 0.20 (sec) , antiderivative size = 97, normalized size of antiderivative = 4.41 \[ \int \frac {1}{2} \left (e^x \left (16+e^4 \left (6+x^4\right )\right )+e^{4+x} \left (6+6 x+5 x^4+x^5\right ) \log (x)\right ) \, dx=\frac {1}{2} \, {\left (x^{5} e^{4} + 6 \, x e^{4}\right )} e^{x} \log \left (x\right ) - \frac {1}{2} \, {\left (x^{4} e^{4} - 4 \, x^{3} e^{4} + 12 \, x^{2} e^{4} - 24 \, x e^{4} + 30 \, e^{4}\right )} e^{x} + \frac {1}{2} \, {\left (x^{4} e^{4} - 4 \, x^{3} e^{4} + 12 \, x^{2} e^{4} - 24 \, x e^{4} + 24 \, e^{4}\right )} e^{x} + 3 \, e^{\left (x + 4\right )} + 8 \, e^{x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 74 vs. \(2 (17) = 34\).
Time = 0.26 (sec) , antiderivative size = 74, normalized size of antiderivative = 3.36 \[ \int \frac {1}{2} \left (e^x \left (16+e^4 \left (6+x^4\right )\right )+e^{4+x} \left (6+6 x+5 x^4+x^5\right ) \log (x)\right ) \, dx=\frac {1}{2} \, {\left (x^{5} + 6 \, x\right )} e^{\left (x + 4\right )} \log \left (x\right ) + \frac {1}{2} \, {\left (x^{4} - 4 \, x^{3} + 12 \, x^{2} - 24 \, x + 30\right )} e^{\left (x + 4\right )} - \frac {1}{2} \, {\left (x^{4} - 4 \, x^{3} + 12 \, x^{2} - 24 \, x + 24\right )} e^{\left (x + 4\right )} - 3 \, e^{\left (x + 4\right )} + 8 \, e^{x} \]
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Time = 10.17 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.05 \[ \int \frac {1}{2} \left (e^x \left (16+e^4 \left (6+x^4\right )\right )+e^{4+x} \left (6+6 x+5 x^4+x^5\right ) \log (x)\right ) \, dx=8\,{\mathrm {e}}^x+{\mathrm {e}}^x\,\ln \left (x\right )\,\left (\frac {{\mathrm {e}}^4\,x^5}{2}+3\,{\mathrm {e}}^4\,x\right ) \]
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