Integrand size = 97, antiderivative size = 19 \[ \int \frac {e^{\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{625-500 x+150 x^2-20 x^3+x^4}} \left (-3061+3125 x-1250 x^2+250 x^3-25 x^4+x^5\right )}{-3125+3125 x-1250 x^2+250 x^3-25 x^4+x^5} \, dx=3+e-e^{256+\frac {16}{(-5+x)^4}-x} \]
[Out]
\[ \int \frac {e^{\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{625-500 x+150 x^2-20 x^3+x^4}} \left (-3061+3125 x-1250 x^2+250 x^3-25 x^4+x^5\right )}{-3125+3125 x-1250 x^2+250 x^3-25 x^4+x^5} \, dx=\int \frac {\exp \left (\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{625-500 x+150 x^2-20 x^3+x^4}\right ) \left (-3061+3125 x-1250 x^2+250 x^3-25 x^4+x^5\right )}{-3125+3125 x-1250 x^2+250 x^3-25 x^4+x^5} \, dx \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = \int \frac {\exp \left (\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{(-5+x)^4}\right ) \left (3061-3125 x+1250 x^2-250 x^3+25 x^4-x^5\right )}{(5-x)^5} \, dx \\ & = \int \left (\exp \left (\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{(-5+x)^4}\right )+\frac {64 \exp \left (\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{(-5+x)^4}\right )}{(-5+x)^5}\right ) \, dx \\ & = 64 \int \frac {\exp \left (\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{(-5+x)^4}\right )}{(-5+x)^5} \, dx+\int \exp \left (\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{(-5+x)^4}\right ) \, dx \\ \end{align*}
Time = 0.89 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.84 \[ \int \frac {e^{\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{625-500 x+150 x^2-20 x^3+x^4}} \left (-3061+3125 x-1250 x^2+250 x^3-25 x^4+x^5\right )}{-3125+3125 x-1250 x^2+250 x^3-25 x^4+x^5} \, dx=-e^{256+\frac {16}{(-5+x)^4}-x} \]
[In]
[Out]
Time = 3.04 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.79
method | result | size |
risch | \(-{\mathrm e}^{-\frac {x^{5}-276 x^{4}+5270 x^{3}-38900 x^{2}+128625 x -160016}{\left (-5+x \right )^{4}}}\) | \(34\) |
gosper | \(-{\mathrm e}^{-\frac {x^{5}-276 x^{4}+5270 x^{3}-38900 x^{2}+128625 x -160016}{x^{4}-20 x^{3}+150 x^{2}-500 x +625}}\) | \(49\) |
parallelrisch | \(-{\mathrm e}^{-\frac {x^{5}-276 x^{4}+5270 x^{3}-38900 x^{2}+128625 x -160016}{x^{4}-20 x^{3}+150 x^{2}-500 x +625}}\) | \(49\) |
norman | \(\frac {500 x \,{\mathrm e}^{\frac {-x^{5}+276 x^{4}-5270 x^{3}+38900 x^{2}-128625 x +160016}{x^{4}-20 x^{3}+150 x^{2}-500 x +625}}-150 x^{2} {\mathrm e}^{\frac {-x^{5}+276 x^{4}-5270 x^{3}+38900 x^{2}-128625 x +160016}{x^{4}-20 x^{3}+150 x^{2}-500 x +625}}+20 x^{3} {\mathrm e}^{\frac {-x^{5}+276 x^{4}-5270 x^{3}+38900 x^{2}-128625 x +160016}{x^{4}-20 x^{3}+150 x^{2}-500 x +625}}-x^{4} {\mathrm e}^{\frac {-x^{5}+276 x^{4}-5270 x^{3}+38900 x^{2}-128625 x +160016}{x^{4}-20 x^{3}+150 x^{2}-500 x +625}}-625 \,{\mathrm e}^{\frac {-x^{5}+276 x^{4}-5270 x^{3}+38900 x^{2}-128625 x +160016}{x^{4}-20 x^{3}+150 x^{2}-500 x +625}}}{\left (-5+x \right )^{4}}\) | \(263\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 48 vs. \(2 (19) = 38\).
Time = 0.25 (sec) , antiderivative size = 48, normalized size of antiderivative = 2.53 \[ \int \frac {e^{\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{625-500 x+150 x^2-20 x^3+x^4}} \left (-3061+3125 x-1250 x^2+250 x^3-25 x^4+x^5\right )}{-3125+3125 x-1250 x^2+250 x^3-25 x^4+x^5} \, dx=-e^{\left (-\frac {x^{5} - 276 \, x^{4} + 5270 \, x^{3} - 38900 \, x^{2} + 128625 \, x - 160016}{x^{4} - 20 \, x^{3} + 150 \, x^{2} - 500 \, x + 625}\right )} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 44 vs. \(2 (15) = 30\).
Time = 0.14 (sec) , antiderivative size = 44, normalized size of antiderivative = 2.32 \[ \int \frac {e^{\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{625-500 x+150 x^2-20 x^3+x^4}} \left (-3061+3125 x-1250 x^2+250 x^3-25 x^4+x^5\right )}{-3125+3125 x-1250 x^2+250 x^3-25 x^4+x^5} \, dx=- e^{\frac {- x^{5} + 276 x^{4} - 5270 x^{3} + 38900 x^{2} - 128625 x + 160016}{x^{4} - 20 x^{3} + 150 x^{2} - 500 x + 625}} \]
[In]
[Out]
none
Time = 0.39 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.58 \[ \int \frac {e^{\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{625-500 x+150 x^2-20 x^3+x^4}} \left (-3061+3125 x-1250 x^2+250 x^3-25 x^4+x^5\right )}{-3125+3125 x-1250 x^2+250 x^3-25 x^4+x^5} \, dx=-e^{\left (-x + \frac {16}{x^{4} - 20 \, x^{3} + 150 \, x^{2} - 500 \, x + 625} + 256\right )} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 149 vs. \(2 (19) = 38\).
Time = 0.26 (sec) , antiderivative size = 149, normalized size of antiderivative = 7.84 \[ \int \frac {e^{\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{625-500 x+150 x^2-20 x^3+x^4}} \left (-3061+3125 x-1250 x^2+250 x^3-25 x^4+x^5\right )}{-3125+3125 x-1250 x^2+250 x^3-25 x^4+x^5} \, dx=-e^{\left (-\frac {x^{5}}{x^{4} - 20 \, x^{3} + 150 \, x^{2} - 500 \, x + 625} + \frac {276 \, x^{4}}{x^{4} - 20 \, x^{3} + 150 \, x^{2} - 500 \, x + 625} - \frac {5270 \, x^{3}}{x^{4} - 20 \, x^{3} + 150 \, x^{2} - 500 \, x + 625} + \frac {38900 \, x^{2}}{x^{4} - 20 \, x^{3} + 150 \, x^{2} - 500 \, x + 625} - \frac {128625 \, x}{x^{4} - 20 \, x^{3} + 150 \, x^{2} - 500 \, x + 625} + \frac {160016}{x^{4} - 20 \, x^{3} + 150 \, x^{2} - 500 \, x + 625}\right )} \]
[In]
[Out]
Time = 10.64 (sec) , antiderivative size = 153, normalized size of antiderivative = 8.05 \[ \int \frac {e^{\frac {160016-128625 x+38900 x^2-5270 x^3+276 x^4-x^5}{625-500 x+150 x^2-20 x^3+x^4}} \left (-3061+3125 x-1250 x^2+250 x^3-25 x^4+x^5\right )}{-3125+3125 x-1250 x^2+250 x^3-25 x^4+x^5} \, dx=-{\mathrm {e}}^{-\frac {128625\,x}{x^4-20\,x^3+150\,x^2-500\,x+625}}\,{\mathrm {e}}^{-\frac {x^5}{x^4-20\,x^3+150\,x^2-500\,x+625}}\,{\mathrm {e}}^{\frac {276\,x^4}{x^4-20\,x^3+150\,x^2-500\,x+625}}\,{\mathrm {e}}^{-\frac {5270\,x^3}{x^4-20\,x^3+150\,x^2-500\,x+625}}\,{\mathrm {e}}^{\frac {38900\,x^2}{x^4-20\,x^3+150\,x^2-500\,x+625}}\,{\mathrm {e}}^{\frac {160016}{x^4-20\,x^3+150\,x^2-500\,x+625}} \]
[In]
[Out]