Integrand size = 85, antiderivative size = 26 \[ \int \frac {-5 \log (\log (3))+e^{e^x} \log (\log (3))+24 e^{e^x+x} \log \left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))+8 e^{e^x+x} \log ^3\left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))}{-5+e^{e^x}} \, dx=5+\left (x+\left (3+\log ^2\left (\left (5-e^{e^x}\right )^2\right )\right )^2\right ) \log (\log (3)) \]
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Result contains higher order function than in optimal. Order 4 vs. order 3 in optimal.
Time = 0.75 (sec) , antiderivative size = 318, normalized size of antiderivative = 12.23, number of steps used = 26, number of rules used = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2320, 12, 6874, 36, 31, 29, 2458, 2379, 2421, 6724, 2438, 2430, 14, 2441, 2352, 2443, 2481} \[ \int \frac {-5 \log (\log (3))+e^{e^x} \log (\log (3))+24 e^{e^x+x} \log \left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))+8 e^{e^x+x} \log ^3\left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))}{-5+e^{e^x}} \, dx=48 \log (\log (3)) \operatorname {PolyLog}\left (2,\frac {5}{5-e^{e^x}}\right ) \log ^2\left (\left (e^{e^x}-5\right )^2\right )+48 \log (\log (3)) \operatorname {PolyLog}\left (2,1-\frac {e^{e^x}}{5}\right ) \log ^2\left (\left (e^{e^x}-5\right )^2\right )+192 \log (\log (3)) \operatorname {PolyLog}\left (3,\frac {5}{5-e^{e^x}}\right ) \log \left (\left (e^{e^x}-5\right )^2\right )-192 \log (\log (3)) \operatorname {PolyLog}\left (3,1-\frac {e^{e^x}}{5}\right ) \log \left (\left (e^{e^x}-5\right )^2\right )+48 \log (\log (3)) \operatorname {PolyLog}\left (2,\frac {5}{5-e^{e^x}}\right )+48 \log (\log (3)) \operatorname {PolyLog}\left (2,1-\frac {e^{e^x}}{5}\right )+384 \log (\log (3)) \operatorname {PolyLog}\left (4,\frac {5}{5-e^{e^x}}\right )+384 \log (\log (3)) \operatorname {PolyLog}\left (4,1-\frac {e^{e^x}}{5}\right )+8 \log (\log (3)) \log \left (\frac {e^{e^x}}{5}\right ) \log ^3\left (\left (e^{e^x}-5\right )^2\right )-8 \log (\log (3)) \log \left (1-\frac {5}{5-e^{e^x}}\right ) \log ^3\left (\left (e^{e^x}-5\right )^2\right )+24 \log (\log (3)) \log \left (\frac {e^{e^x}}{5}\right ) \log \left (\left (e^{e^x}-5\right )^2\right )-24 \log (\log (3)) \log \left (1-\frac {5}{5-e^{e^x}}\right ) \log \left (\left (e^{e^x}-5\right )^2\right )+x \log (\log (3)) \]
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Rule 12
Rule 14
Rule 29
Rule 31
Rule 36
Rule 2320
Rule 2352
Rule 2379
Rule 2421
Rule 2430
Rule 2438
Rule 2441
Rule 2443
Rule 2458
Rule 2481
Rule 6724
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \frac {\left (5-e^x-24 e^x x \log \left (\left (-5+e^x\right )^2\right )-8 e^x x \log ^3\left (\left (-5+e^x\right )^2\right )\right ) \log (\log (3))}{\left (5-e^x\right ) x} \, dx,x,e^x\right ) \\ & = \log (\log (3)) \text {Subst}\left (\int \frac {5-e^x-24 e^x x \log \left (\left (-5+e^x\right )^2\right )-8 e^x x \log ^3\left (\left (-5+e^x\right )^2\right )}{\left (5-e^x\right ) x} \, dx,x,e^x\right ) \\ & = \log (\log (3)) \text {Subst}\left (\int \left (\frac {40 \log \left (\left (-5+e^x\right )^2\right ) \left (3+\log ^2\left (\left (-5+e^x\right )^2\right )\right )}{-5+e^x}+\frac {1+24 x \log \left (\left (-5+e^x\right )^2\right )+8 x \log ^3\left (\left (-5+e^x\right )^2\right )}{x}\right ) \, dx,x,e^x\right ) \\ & = \log (\log (3)) \text {Subst}\left (\int \frac {1+24 x \log \left (\left (-5+e^x\right )^2\right )+8 x \log ^3\left (\left (-5+e^x\right )^2\right )}{x} \, dx,x,e^x\right )+(40 \log (\log (3))) \text {Subst}\left (\int \frac {\log \left (\left (-5+e^x\right )^2\right ) \left (3+\log ^2\left (\left (-5+e^x\right )^2\right )\right )}{-5+e^x} \, dx,x,e^x\right ) \\ & = \log (\log (3)) \text {Subst}\left (\int \left (\frac {1}{x}+24 \log \left (\left (-5+e^x\right )^2\right )+8 \log ^3\left (\left (-5+e^x\right )^2\right )\right ) \, dx,x,e^x\right )+(40 \log (\log (3))) \text {Subst}\left (\int \frac {\log \left ((-5+x)^2\right ) \left (3+\log ^2\left ((-5+x)^2\right )\right )}{(-5+x) x} \, dx,x,e^{e^x}\right ) \\ & = x \log (\log (3))+(8 \log (\log (3))) \text {Subst}\left (\int \log ^3\left (\left (-5+e^x\right )^2\right ) \, dx,x,e^x\right )+(24 \log (\log (3))) \text {Subst}\left (\int \log \left (\left (-5+e^x\right )^2\right ) \, dx,x,e^x\right )+(40 \log (\log (3))) \text {Subst}\left (\int \left (\frac {3 \log \left ((-5+x)^2\right )}{(-5+x) x}+\frac {\log ^3\left ((-5+x)^2\right )}{(-5+x) x}\right ) \, dx,x,e^{e^x}\right ) \\ & = x \log (\log (3))+(8 \log (\log (3))) \text {Subst}\left (\int \frac {\log ^3\left ((-5+x)^2\right )}{x} \, dx,x,e^{e^x}\right )+(24 \log (\log (3))) \text {Subst}\left (\int \frac {\log \left ((-5+x)^2\right )}{x} \, dx,x,e^{e^x}\right )+(40 \log (\log (3))) \text {Subst}\left (\int \frac {\log ^3\left ((-5+x)^2\right )}{(-5+x) x} \, dx,x,e^{e^x}\right )+(120 \log (\log (3))) \text {Subst}\left (\int \frac {\log \left ((-5+x)^2\right )}{(-5+x) x} \, dx,x,e^{e^x}\right ) \\ & = x \log (\log (3))+24 \log \left (\frac {e^{e^x}}{5}\right ) \log \left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3))+8 \log \left (\frac {e^{e^x}}{5}\right ) \log ^3\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3))+(40 \log (\log (3))) \text {Subst}\left (\int \frac {\log ^3\left (x^2\right )}{x (5+x)} \, dx,x,-5+e^{e^x}\right )-(48 \log (\log (3))) \text {Subst}\left (\int \frac {\log \left (\frac {x}{5}\right )}{-5+x} \, dx,x,e^{e^x}\right )-(48 \log (\log (3))) \text {Subst}\left (\int \frac {\log ^2\left ((-5+x)^2\right ) \log \left (\frac {x}{5}\right )}{-5+x} \, dx,x,e^{e^x}\right )+(120 \log (\log (3))) \text {Subst}\left (\int \frac {\log \left (x^2\right )}{x (5+x)} \, dx,x,-5+e^{e^x}\right ) \\ & = x \log (\log (3))+24 \log \left (\frac {e^{e^x}}{5}\right ) \log \left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3))+8 \log \left (\frac {e^{e^x}}{5}\right ) \log ^3\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3))-24 \log \left (\left (-5+e^{e^x}\right )^2\right ) \log \left (1-\frac {5}{5-e^{e^x}}\right ) \log (\log (3))-8 \log ^3\left (\left (-5+e^{e^x}\right )^2\right ) \log \left (1-\frac {5}{5-e^{e^x}}\right ) \log (\log (3))+48 \log (\log (3)) \text {Li}_2\left (1-\frac {e^{e^x}}{5}\right )+(48 \log (\log (3))) \text {Subst}\left (\int \frac {\log \left (1+\frac {5}{x}\right )}{x} \, dx,x,-5+e^{e^x}\right )+(48 \log (\log (3))) \text {Subst}\left (\int \frac {\log \left (1+\frac {5}{x}\right ) \log ^2\left (x^2\right )}{x} \, dx,x,-5+e^{e^x}\right )-(48 \log (\log (3))) \text {Subst}\left (\int \frac {\log ^2\left (x^2\right ) \log \left (\frac {5+x}{5}\right )}{x} \, dx,x,-5+e^{e^x}\right ) \\ & = x \log (\log (3))+24 \log \left (\frac {e^{e^x}}{5}\right ) \log \left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3))+8 \log \left (\frac {e^{e^x}}{5}\right ) \log ^3\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3))-24 \log \left (\left (-5+e^{e^x}\right )^2\right ) \log \left (1-\frac {5}{5-e^{e^x}}\right ) \log (\log (3))-8 \log ^3\left (\left (-5+e^{e^x}\right )^2\right ) \log \left (1-\frac {5}{5-e^{e^x}}\right ) \log (\log (3))+48 \log (\log (3)) \text {Li}_2\left (\frac {5}{5-e^{e^x}}\right )+48 \log ^2\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3)) \text {Li}_2\left (\frac {5}{5-e^{e^x}}\right )+48 \log ^2\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3)) \text {Li}_2\left (\frac {1}{5} \left (5-e^{e^x}\right )\right )+48 \log (\log (3)) \text {Li}_2\left (1-\frac {e^{e^x}}{5}\right )-(192 \log (\log (3))) \text {Subst}\left (\int \frac {\log \left (x^2\right ) \text {Li}_2\left (-\frac {5}{x}\right )}{x} \, dx,x,-5+e^{e^x}\right )-(192 \log (\log (3))) \text {Subst}\left (\int \frac {\log \left (x^2\right ) \text {Li}_2\left (-\frac {x}{5}\right )}{x} \, dx,x,-5+e^{e^x}\right ) \\ & = x \log (\log (3))+24 \log \left (\frac {e^{e^x}}{5}\right ) \log \left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3))+8 \log \left (\frac {e^{e^x}}{5}\right ) \log ^3\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3))-24 \log \left (\left (-5+e^{e^x}\right )^2\right ) \log \left (1-\frac {5}{5-e^{e^x}}\right ) \log (\log (3))-8 \log ^3\left (\left (-5+e^{e^x}\right )^2\right ) \log \left (1-\frac {5}{5-e^{e^x}}\right ) \log (\log (3))+48 \log (\log (3)) \text {Li}_2\left (\frac {5}{5-e^{e^x}}\right )+48 \log ^2\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3)) \text {Li}_2\left (\frac {5}{5-e^{e^x}}\right )+48 \log ^2\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3)) \text {Li}_2\left (\frac {1}{5} \left (5-e^{e^x}\right )\right )+48 \log (\log (3)) \text {Li}_2\left (1-\frac {e^{e^x}}{5}\right )+192 \log \left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3)) \text {Li}_3\left (\frac {5}{5-e^{e^x}}\right )-192 \log \left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3)) \text {Li}_3\left (\frac {1}{5} \left (5-e^{e^x}\right )\right )-(384 \log (\log (3))) \text {Subst}\left (\int \frac {\text {Li}_3\left (-\frac {5}{x}\right )}{x} \, dx,x,-5+e^{e^x}\right )+(384 \log (\log (3))) \text {Subst}\left (\int \frac {\text {Li}_3\left (-\frac {x}{5}\right )}{x} \, dx,x,-5+e^{e^x}\right ) \\ & = x \log (\log (3))+24 \log \left (\frac {e^{e^x}}{5}\right ) \log \left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3))+8 \log \left (\frac {e^{e^x}}{5}\right ) \log ^3\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3))-24 \log \left (\left (-5+e^{e^x}\right )^2\right ) \log \left (1-\frac {5}{5-e^{e^x}}\right ) \log (\log (3))-8 \log ^3\left (\left (-5+e^{e^x}\right )^2\right ) \log \left (1-\frac {5}{5-e^{e^x}}\right ) \log (\log (3))+48 \log (\log (3)) \text {Li}_2\left (\frac {5}{5-e^{e^x}}\right )+48 \log ^2\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3)) \text {Li}_2\left (\frac {5}{5-e^{e^x}}\right )+48 \log ^2\left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3)) \text {Li}_2\left (\frac {1}{5} \left (5-e^{e^x}\right )\right )+48 \log (\log (3)) \text {Li}_2\left (1-\frac {e^{e^x}}{5}\right )+192 \log \left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3)) \text {Li}_3\left (\frac {5}{5-e^{e^x}}\right )-192 \log \left (\left (-5+e^{e^x}\right )^2\right ) \log (\log (3)) \text {Li}_3\left (\frac {1}{5} \left (5-e^{e^x}\right )\right )+384 \log (\log (3)) \text {Li}_4\left (\frac {5}{5-e^{e^x}}\right )+384 \log (\log (3)) \text {Li}_4\left (\frac {1}{5} \left (5-e^{e^x}\right )\right ) \\ \end{align*}
Time = 0.19 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.23 \[ \int \frac {-5 \log (\log (3))+e^{e^x} \log (\log (3))+24 e^{e^x+x} \log \left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))+8 e^{e^x+x} \log ^3\left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))}{-5+e^{e^x}} \, dx=\left (x+6 \log ^2\left (\left (-5+e^{e^x}\right )^2\right )+\log ^4\left (\left (-5+e^{e^x}\right )^2\right )\right ) \log (\log (3)) \]
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Time = 5.97 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.15
method | result | size |
parts | \(\ln \left (\ln \left (3\right )\right ) x +\ln \left (\ln \left (3\right )\right ) {\left (\ln \left ({\mathrm e}^{2 \,{\mathrm e}^{x}}-10 \,{\mathrm e}^{{\mathrm e}^{x}}+25\right )^{2}+3\right )}^{2}\) | \(30\) |
parallelrisch | \(\ln \left (\ln \left (3\right )\right ) \ln \left ({\mathrm e}^{2 \,{\mathrm e}^{x}}-10 \,{\mathrm e}^{{\mathrm e}^{x}}+25\right )^{4}+6 \ln \left (\ln \left (3\right )\right ) \ln \left ({\mathrm e}^{2 \,{\mathrm e}^{x}}-10 \,{\mathrm e}^{{\mathrm e}^{x}}+25\right )^{2}+\ln \left (\ln \left (3\right )\right ) x\) | \(46\) |
derivativedivides | \(\left (24 \ln \left (\ln \left (3\right )\right ) {\left (\ln \left (\left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{2}\right )-2 \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )\right )}^{2}+24 \ln \left (\ln \left (3\right )\right )\right ) \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{2}+\left (8 \ln \left (\ln \left (3\right )\right ) {\left (\ln \left (\left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{2}\right )-2 \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )\right )}^{3}+24 \ln \left (\ln \left (3\right )\right ) \left (\ln \left (\left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{2}\right )-2 \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )\right )\right ) \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )+16 \ln \left (\ln \left (3\right )\right ) \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{4}+32 \ln \left (\ln \left (3\right )\right ) \left (\ln \left (\left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{2}\right )-2 \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )\right ) \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{3}+\ln \left (\ln \left (3\right )\right ) \ln \left ({\mathrm e}^{x}\right )\) | \(145\) |
default | \(\left (24 \ln \left (\ln \left (3\right )\right ) {\left (\ln \left (\left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{2}\right )-2 \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )\right )}^{2}+24 \ln \left (\ln \left (3\right )\right )\right ) \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{2}+\left (8 \ln \left (\ln \left (3\right )\right ) {\left (\ln \left (\left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{2}\right )-2 \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )\right )}^{3}+24 \ln \left (\ln \left (3\right )\right ) \left (\ln \left (\left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{2}\right )-2 \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )\right )\right ) \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )+16 \ln \left (\ln \left (3\right )\right ) \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{4}+32 \ln \left (\ln \left (3\right )\right ) \left (\ln \left (\left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{2}\right )-2 \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )\right ) \ln \left ({\mathrm e}^{{\mathrm e}^{x}}-5\right )^{3}+\ln \left (\ln \left (3\right )\right ) \ln \left ({\mathrm e}^{x}\right )\) | \(145\) |
risch | \(\text {Expression too large to display}\) | \(611\) |
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Leaf count of result is larger than twice the leaf count of optimal. 81 vs. \(2 (22) = 44\).
Time = 0.25 (sec) , antiderivative size = 81, normalized size of antiderivative = 3.12 \[ \int \frac {-5 \log (\log (3))+e^{e^x} \log (\log (3))+24 e^{e^x+x} \log \left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))+8 e^{e^x+x} \log ^3\left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))}{-5+e^{e^x}} \, dx=\log \left ({\left (25 \, e^{\left (2 \, x\right )} + e^{\left (2 \, x + 2 \, e^{x}\right )} - 10 \, e^{\left (2 \, x + e^{x}\right )}\right )} e^{\left (-2 \, x\right )}\right )^{4} \log \left (\log \left (3\right )\right ) + 6 \, \log \left ({\left (25 \, e^{\left (2 \, x\right )} + e^{\left (2 \, x + 2 \, e^{x}\right )} - 10 \, e^{\left (2 \, x + e^{x}\right )}\right )} e^{\left (-2 \, x\right )}\right )^{2} \log \left (\log \left (3\right )\right ) + x \log \left (\log \left (3\right )\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 54 vs. \(2 (22) = 44\).
Time = 0.16 (sec) , antiderivative size = 54, normalized size of antiderivative = 2.08 \[ \int \frac {-5 \log (\log (3))+e^{e^x} \log (\log (3))+24 e^{e^x+x} \log \left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))+8 e^{e^x+x} \log ^3\left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))}{-5+e^{e^x}} \, dx=x \log {\left (\log {\left (3 \right )} \right )} + \log {\left (e^{2 e^{x}} - 10 e^{e^{x}} + 25 \right )}^{4} \log {\left (\log {\left (3 \right )} \right )} + 6 \log {\left (e^{2 e^{x}} - 10 e^{e^{x}} + 25 \right )}^{2} \log {\left (\log {\left (3 \right )} \right )} \]
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Time = 0.32 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.23 \[ \int \frac {-5 \log (\log (3))+e^{e^x} \log (\log (3))+24 e^{e^x+x} \log \left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))+8 e^{e^x+x} \log ^3\left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))}{-5+e^{e^x}} \, dx=16 \, \log \left (e^{\left (e^{x}\right )} - 5\right )^{4} \log \left (\log \left (3\right )\right ) + 24 \, \log \left (e^{\left (e^{x}\right )} - 5\right )^{2} \log \left (\log \left (3\right )\right ) + x \log \left (\log \left (3\right )\right ) \]
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\[ \int \frac {-5 \log (\log (3))+e^{e^x} \log (\log (3))+24 e^{e^x+x} \log \left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))+8 e^{e^x+x} \log ^3\left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))}{-5+e^{e^x}} \, dx=\int { \frac {8 \, e^{\left (x + e^{x}\right )} \log \left (e^{\left (2 \, e^{x}\right )} - 10 \, e^{\left (e^{x}\right )} + 25\right )^{3} \log \left (\log \left (3\right )\right ) + 24 \, e^{\left (x + e^{x}\right )} \log \left (e^{\left (2 \, e^{x}\right )} - 10 \, e^{\left (e^{x}\right )} + 25\right ) \log \left (\log \left (3\right )\right ) + e^{\left (e^{x}\right )} \log \left (\log \left (3\right )\right ) - 5 \, \log \left (\log \left (3\right )\right )}{e^{\left (e^{x}\right )} - 5} \,d x } \]
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Time = 12.43 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.46 \[ \int \frac {-5 \log (\log (3))+e^{e^x} \log (\log (3))+24 e^{e^x+x} \log \left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))+8 e^{e^x+x} \log ^3\left (25-10 e^{e^x}+e^{2 e^x}\right ) \log (\log (3))}{-5+e^{e^x}} \, dx=\ln \left (\ln \left (3\right )\right )\,\left ({\ln \left ({\mathrm {e}}^{2\,{\mathrm {e}}^x}-10\,{\mathrm {e}}^{{\mathrm {e}}^x}+25\right )}^4+6\,{\ln \left ({\mathrm {e}}^{2\,{\mathrm {e}}^x}-10\,{\mathrm {e}}^{{\mathrm {e}}^x}+25\right )}^2+x\right ) \]
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