Integrand size = 61, antiderivative size = 22 \[ \int \frac {2-6 x+e^{18} \left (-100 x-20 e x-e^2 x\right )}{-6 x^2+e^{18} \left (-100 x^2-20 e x^2-e^2 x^2\right )+2 x \log (x)} \, dx=\log \left (3 x+\frac {1}{2} e^{18} (10+e)^2 x-\log (x)\right ) \]
[Out]
Time = 0.15 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.049, Rules used = {6873, 2641, 6816} \[ \int \frac {2-6 x+e^{18} \left (-100 x-20 e x-e^2 x\right )}{-6 x^2+e^{18} \left (-100 x^2-20 e x^2-e^2 x^2\right )+2 x \log (x)} \, dx=\log \left (\left (6+e^{18} (10+e)^2\right ) x-2 \log (x)\right ) \]
[In]
[Out]
Rule 2641
Rule 6816
Rule 6873
Rubi steps \begin{align*} \text {integral}& = \int \frac {-2+\left (6+100 e^{18}+20 e^{19}+e^{20}\right ) x}{6 \left (1+\frac {1}{6} e^{18} (10+e)^2\right ) x^2-2 x \log (x)} \, dx \\ & = \int \frac {-2+\left (6+100 e^{18}+20 e^{19}+e^{20}\right ) x}{x \left (6 \left (1+\frac {1}{6} e^{18} (10+e)^2\right ) x-2 \log (x)\right )} \, dx \\ & = \log \left (\left (6+e^{18} (10+e)^2\right ) x-2 \log (x)\right ) \\ \end{align*}
Time = 0.19 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.18 \[ \int \frac {2-6 x+e^{18} \left (-100 x-20 e x-e^2 x\right )}{-6 x^2+e^{18} \left (-100 x^2-20 e x^2-e^2 x^2\right )+2 x \log (x)} \, dx=\log \left (6 x+100 e^{18} x+20 e^{19} x+e^{20} x-2 \log (x)\right ) \]
[In]
[Out]
Time = 0.08 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.05
method | result | size |
risch | \(\ln \left (-\frac {x \,{\mathrm e}^{20}}{2}-10 \,{\mathrm e}^{19} x -50 \,{\mathrm e}^{18} x -3 x +\ln \left (x \right )\right )\) | \(23\) |
default | \(\ln \left ({\mathrm e}^{18} {\mathrm e}^{2} x +20 \,{\mathrm e}^{18} {\mathrm e} x +100 \,{\mathrm e}^{18} x -2 \ln \left (x \right )+6 x \right )\) | \(36\) |
norman | \(\ln \left ({\mathrm e}^{18} {\mathrm e}^{2} x +20 \,{\mathrm e}^{18} {\mathrm e} x +100 \,{\mathrm e}^{18} x -2 \ln \left (x \right )+6 x \right )\) | \(36\) |
parallelrisch | \(\ln \left (\frac {{\mathrm e}^{18} {\mathrm e}^{2} x +20 \,{\mathrm e}^{18} {\mathrm e} x +100 \,{\mathrm e}^{18} x -2 \ln \left (x \right )+6 x}{{\mathrm e}^{18} {\mathrm e}^{2}+20 \,{\mathrm e}^{18} {\mathrm e}+100 \,{\mathrm e}^{18}+6}\right )\) | \(64\) |
[In]
[Out]
none
Time = 0.24 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {2-6 x+e^{18} \left (-100 x-20 e x-e^2 x\right )}{-6 x^2+e^{18} \left (-100 x^2-20 e x^2-e^2 x^2\right )+2 x \log (x)} \, dx=\log \left (-x e^{20} - 20 \, x e^{19} - 100 \, x e^{18} - 6 \, x + 2 \, \log \left (x\right )\right ) \]
[In]
[Out]
Time = 0.10 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.23 \[ \int \frac {2-6 x+e^{18} \left (-100 x-20 e x-e^2 x\right )}{-6 x^2+e^{18} \left (-100 x^2-20 e x^2-e^2 x^2\right )+2 x \log (x)} \, dx=\log {\left (- 50 x e^{18} - 10 x e^{19} - \frac {x e^{20}}{2} - 3 x + \log {\left (x \right )} \right )} \]
[In]
[Out]
none
Time = 0.22 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86 \[ \int \frac {2-6 x+e^{18} \left (-100 x-20 e x-e^2 x\right )}{-6 x^2+e^{18} \left (-100 x^2-20 e x^2-e^2 x^2\right )+2 x \log (x)} \, dx=\log \left (-\frac {1}{2} \, x {\left (e^{20} + 20 \, e^{19} + 100 \, e^{18} + 6\right )} + \log \left (x\right )\right ) \]
[In]
[Out]
none
Time = 0.26 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {2-6 x+e^{18} \left (-100 x-20 e x-e^2 x\right )}{-6 x^2+e^{18} \left (-100 x^2-20 e x^2-e^2 x^2\right )+2 x \log (x)} \, dx=\log \left (-x e^{20} - 20 \, x e^{19} - 100 \, x e^{18} - 6 \, x + 2 \, \log \left (x\right )\right ) \]
[In]
[Out]
Time = 11.89 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.05 \[ \int \frac {2-6 x+e^{18} \left (-100 x-20 e x-e^2 x\right )}{-6 x^2+e^{18} \left (-100 x^2-20 e x^2-e^2 x^2\right )+2 x \log (x)} \, dx=\ln \left (6\,x-2\,\ln \left (x\right )+100\,x\,{\mathrm {e}}^{18}+20\,x\,{\mathrm {e}}^{19}+x\,{\mathrm {e}}^{20}\right ) \]
[In]
[Out]