Integrand size = 17, antiderivative size = 24 \[ \int \frac {-5+4 x+e^4 x}{5 x} \, dx=\frac {1}{5} x \left (-1+e^4+\frac {5 \left (2+x+\log \left (\frac {3}{x}\right )\right )}{x}\right ) \]
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Time = 0.01 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.62, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.176, Rules used = {6, 12, 45} \[ \int \frac {-5+4 x+e^4 x}{5 x} \, dx=\frac {1}{5} \left (4+e^4\right ) x-\log (x) \]
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Rule 6
Rule 12
Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \frac {-5+\left (4+e^4\right ) x}{5 x} \, dx \\ & = \frac {1}{5} \int \frac {-5+\left (4+e^4\right ) x}{x} \, dx \\ & = \frac {1}{5} \int \left (4+e^4-\frac {5}{x}\right ) \, dx \\ & = \frac {1}{5} \left (4+e^4\right ) x-\log (x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.71 \[ \int \frac {-5+4 x+e^4 x}{5 x} \, dx=\frac {1}{5} \left (4 x+e^4 x-5 \log (x)\right ) \]
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Time = 0.02 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.58
method | result | size |
default | \(\frac {4 x}{5}+\frac {x \,{\mathrm e}^{4}}{5}-\ln \left (x \right )\) | \(14\) |
norman | \(\left (\frac {4}{5}+\frac {{\mathrm e}^{4}}{5}\right ) x -\ln \left (x \right )\) | \(14\) |
risch | \(\frac {4 x}{5}+\frac {x \,{\mathrm e}^{4}}{5}-\ln \left (x \right )\) | \(14\) |
parallelrisch | \(\frac {4 x}{5}+\frac {x \,{\mathrm e}^{4}}{5}-\ln \left (x \right )\) | \(14\) |
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none
Time = 0.23 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.54 \[ \int \frac {-5+4 x+e^4 x}{5 x} \, dx=\frac {1}{5} \, x e^{4} + \frac {4}{5} \, x - \log \left (x\right ) \]
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Time = 0.04 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.42 \[ \int \frac {-5+4 x+e^4 x}{5 x} \, dx=\frac {x \left (4 + e^{4}\right )}{5} - \log {\left (x \right )} \]
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Time = 0.20 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.50 \[ \int \frac {-5+4 x+e^4 x}{5 x} \, dx=\frac {1}{5} \, x {\left (e^{4} + 4\right )} - \log \left (x\right ) \]
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none
Time = 0.28 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.58 \[ \int \frac {-5+4 x+e^4 x}{5 x} \, dx=\frac {1}{5} \, x e^{4} + \frac {4}{5} \, x - \log \left ({\left | x \right |}\right ) \]
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Time = 0.04 (sec) , antiderivative size = 13, normalized size of antiderivative = 0.54 \[ \int \frac {-5+4 x+e^4 x}{5 x} \, dx=x\,\left (\frac {{\mathrm {e}}^4}{5}+\frac {4}{5}\right )-\ln \left (x\right ) \]
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