Integrand size = 82, antiderivative size = 32 \[ \int \frac {-400 x^6+\left (100 x^3+100 x^4-640 x^5+400 x^6\right ) \log (x)+\left (100 x^3+640 x^5\right ) \log ^2(x)+\left (-50-75 x+295 x^2+160 x^3-8 x^5\right ) \log ^3(x)}{8 x^5 \log ^3(x)} \, dx=4-x+\left (2-\frac {5}{4} \left (-\frac {1+x}{x^2}+4 \left (2+\frac {x}{\log (x)}\right )\right )\right )^2 \]
[Out]
\[ \int \frac {-400 x^6+\left (100 x^3+100 x^4-640 x^5+400 x^6\right ) \log (x)+\left (100 x^3+640 x^5\right ) \log ^2(x)+\left (-50-75 x+295 x^2+160 x^3-8 x^5\right ) \log ^3(x)}{8 x^5 \log ^3(x)} \, dx=\int \frac {-400 x^6+\left (100 x^3+100 x^4-640 x^5+400 x^6\right ) \log (x)+\left (100 x^3+640 x^5\right ) \log ^2(x)+\left (-50-75 x+295 x^2+160 x^3-8 x^5\right ) \log ^3(x)}{8 x^5 \log ^3(x)} \, dx \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = \frac {1}{8} \int \frac {-400 x^6+\left (100 x^3+100 x^4-640 x^5+400 x^6\right ) \log (x)+\left (100 x^3+640 x^5\right ) \log ^2(x)+\left (-50-75 x+295 x^2+160 x^3-8 x^5\right ) \log ^3(x)}{x^5 \log ^3(x)} \, dx \\ & = \frac {1}{8} \int \left (\frac {-50-75 x+295 x^2+160 x^3-8 x^5}{x^5}-\frac {400 x}{\log ^3(x)}+\frac {20 \left (5+5 x-32 x^2+20 x^3\right )}{x^2 \log ^2(x)}+\frac {20 \left (5+32 x^2\right )}{x^2 \log (x)}\right ) \, dx \\ & = \frac {1}{8} \int \frac {-50-75 x+295 x^2+160 x^3-8 x^5}{x^5} \, dx+\frac {5}{2} \int \frac {5+5 x-32 x^2+20 x^3}{x^2 \log ^2(x)} \, dx+\frac {5}{2} \int \frac {5+32 x^2}{x^2 \log (x)} \, dx-50 \int \frac {x}{\log ^3(x)} \, dx \\ & = \frac {25 x^2}{\log ^2(x)}+\frac {1}{8} \int \left (-8-\frac {50}{x^5}-\frac {75}{x^4}+\frac {295}{x^3}+\frac {160}{x^2}\right ) \, dx+\frac {5}{2} \int \left (\frac {32}{\log (x)}+\frac {5}{x^2 \log (x)}\right ) \, dx+\frac {5}{2} \int \frac {5+5 x-32 x^2+20 x^3}{x^2 \log ^2(x)} \, dx-50 \int \frac {x}{\log ^2(x)} \, dx \\ & = \frac {25}{16 x^4}+\frac {25}{8 x^3}-\frac {295}{16 x^2}-\frac {20}{x}-x+\frac {25 x^2}{\log ^2(x)}+\frac {50 x^2}{\log (x)}+\frac {5}{2} \int \frac {5+5 x-32 x^2+20 x^3}{x^2 \log ^2(x)} \, dx+\frac {25}{2} \int \frac {1}{x^2 \log (x)} \, dx+80 \int \frac {1}{\log (x)} \, dx-100 \int \frac {x}{\log (x)} \, dx \\ & = \frac {25}{16 x^4}+\frac {25}{8 x^3}-\frac {295}{16 x^2}-\frac {20}{x}-x+\frac {25 x^2}{\log ^2(x)}+\frac {50 x^2}{\log (x)}+80 \text {li}(x)+\frac {5}{2} \int \frac {5+5 x-32 x^2+20 x^3}{x^2 \log ^2(x)} \, dx+\frac {25}{2} \text {Subst}\left (\int \frac {e^{-x}}{x} \, dx,x,\log (x)\right )-100 \text {Subst}\left (\int \frac {e^{2 x}}{x} \, dx,x,\log (x)\right ) \\ & = \frac {25}{16 x^4}+\frac {25}{8 x^3}-\frac {295}{16 x^2}-\frac {20}{x}-x+\frac {25 \text {Ei}(-\log (x))}{2}-100 \text {Ei}(2 \log (x))+\frac {25 x^2}{\log ^2(x)}+\frac {50 x^2}{\log (x)}+80 \text {li}(x)+\frac {5}{2} \int \frac {5+5 x-32 x^2+20 x^3}{x^2 \log ^2(x)} \, dx \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(65\) vs. \(2(32)=64\).
Time = 0.18 (sec) , antiderivative size = 65, normalized size of antiderivative = 2.03 \[ \int \frac {-400 x^6+\left (100 x^3+100 x^4-640 x^5+400 x^6\right ) \log (x)+\left (100 x^3+640 x^5\right ) \log ^2(x)+\left (-50-75 x+295 x^2+160 x^3-8 x^5\right ) \log ^3(x)}{8 x^5 \log ^3(x)} \, dx=\frac {25}{16 x^4}+\frac {25}{8 x^3}-\frac {295}{16 x^2}-\frac {20}{x}-x+\frac {25 x^2}{\log ^2(x)}-\frac {25}{2 \log (x)}-\frac {25}{2 x \log (x)}+\frac {80 x}{\log (x)} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. \(55\) vs. \(2(24)=48\).
Time = 0.05 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.75
method | result | size |
default | \(-x -\frac {20}{x}+\frac {80 x}{\ln \left (x \right )}+\frac {25 x^{2}}{\ln \left (x \right )^{2}}-\frac {295}{16 x^{2}}-\frac {25}{2 \ln \left (x \right )}+\frac {25}{8 x^{3}}-\frac {25}{2 x \ln \left (x \right )}+\frac {25}{16 x^{4}}\) | \(56\) |
parts | \(-x -\frac {20}{x}+\frac {80 x}{\ln \left (x \right )}+\frac {25 x^{2}}{\ln \left (x \right )^{2}}-\frac {295}{16 x^{2}}-\frac {25}{2 \ln \left (x \right )}+\frac {25}{8 x^{3}}-\frac {25}{2 x \ln \left (x \right )}+\frac {25}{16 x^{4}}\) | \(56\) |
risch | \(-\frac {16 x^{5}+320 x^{3}+295 x^{2}-50 x -25}{16 x^{4}}+\frac {25 x^{3}+80 x^{2} \ln \left (x \right )-\frac {25 x \ln \left (x \right )}{2}-\frac {25 \ln \left (x \right )}{2}}{x \ln \left (x \right )^{2}}\) | \(58\) |
parallelrisch | \(-\frac {16 x^{5} \ln \left (x \right )^{2}-400 x^{6}-1280 x^{5} \ln \left (x \right )+200 x^{4} \ln \left (x \right )+320 x^{3} \ln \left (x \right )^{2}+200 x^{3} \ln \left (x \right )+295 x^{2} \ln \left (x \right )^{2}-50 x \ln \left (x \right )^{2}-25 \ln \left (x \right )^{2}}{16 x^{4} \ln \left (x \right )^{2}}\) | \(77\) |
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 61 vs. \(2 (26) = 52\).
Time = 0.23 (sec) , antiderivative size = 61, normalized size of antiderivative = 1.91 \[ \int \frac {-400 x^6+\left (100 x^3+100 x^4-640 x^5+400 x^6\right ) \log (x)+\left (100 x^3+640 x^5\right ) \log ^2(x)+\left (-50-75 x+295 x^2+160 x^3-8 x^5\right ) \log ^3(x)}{8 x^5 \log ^3(x)} \, dx=\frac {400 \, x^{6} - {\left (16 \, x^{5} + 320 \, x^{3} + 295 \, x^{2} - 50 \, x - 25\right )} \log \left (x\right )^{2} + 40 \, {\left (32 \, x^{5} - 5 \, x^{4} - 5 \, x^{3}\right )} \log \left (x\right )}{16 \, x^{4} \log \left (x\right )^{2}} \]
[In]
[Out]
Time = 0.09 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.50 \[ \int \frac {-400 x^6+\left (100 x^3+100 x^4-640 x^5+400 x^6\right ) \log (x)+\left (100 x^3+640 x^5\right ) \log ^2(x)+\left (-50-75 x+295 x^2+160 x^3-8 x^5\right ) \log ^3(x)}{8 x^5 \log ^3(x)} \, dx=- x + \frac {50 x^{3} + \left (160 x^{2} - 25 x - 25\right ) \log {\left (x \right )}}{2 x \log {\left (x \right )}^{2}} - \frac {320 x^{3} + 295 x^{2} - 50 x - 25}{16 x^{4}} \]
[In]
[Out]
Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 0.24 (sec) , antiderivative size = 72, normalized size of antiderivative = 2.25 \[ \int \frac {-400 x^6+\left (100 x^3+100 x^4-640 x^5+400 x^6\right ) \log (x)+\left (100 x^3+640 x^5\right ) \log ^2(x)+\left (-50-75 x+295 x^2+160 x^3-8 x^5\right ) \log ^3(x)}{8 x^5 \log ^3(x)} \, dx=-x - \frac {20}{x} - \frac {25}{2 \, \log \left (x\right )} - \frac {295}{16 \, x^{2}} + \frac {25}{8 \, x^{3}} + \frac {25}{16 \, x^{4}} + \frac {25}{2} \, {\rm Ei}\left (-\log \left (x\right )\right ) + 80 \, {\rm Ei}\left (\log \left (x\right )\right ) - 80 \, \Gamma \left (-1, -\log \left (x\right )\right ) + 100 \, \Gamma \left (-1, -2 \, \log \left (x\right )\right ) - \frac {25}{2} \, \Gamma \left (-1, \log \left (x\right )\right ) + 200 \, \Gamma \left (-2, -2 \, \log \left (x\right )\right ) \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 55 vs. \(2 (26) = 52\).
Time = 0.28 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.72 \[ \int \frac {-400 x^6+\left (100 x^3+100 x^4-640 x^5+400 x^6\right ) \log (x)+\left (100 x^3+640 x^5\right ) \log ^2(x)+\left (-50-75 x+295 x^2+160 x^3-8 x^5\right ) \log ^3(x)}{8 x^5 \log ^3(x)} \, dx=-x + \frac {5 \, {\left (10 \, x^{3} + 32 \, x^{2} \log \left (x\right ) - 5 \, x \log \left (x\right ) - 5 \, \log \left (x\right )\right )}}{2 \, x \log \left (x\right )^{2}} - \frac {5 \, {\left (64 \, x^{3} + 59 \, x^{2} - 10 \, x - 5\right )}}{16 \, x^{4}} \]
[In]
[Out]
Time = 12.43 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.81 \[ \int \frac {-400 x^6+\left (100 x^3+100 x^4-640 x^5+400 x^6\right ) \log (x)+\left (100 x^3+640 x^5\right ) \log ^2(x)+\left (-50-75 x+295 x^2+160 x^3-8 x^5\right ) \log ^3(x)}{8 x^5 \log ^3(x)} \, dx=-\frac {x^5+20\,x^3+\frac {295\,x^2}{16}-\frac {25\,x}{8}-\frac {25}{16}}{x^4}-\frac {\ln \left (x\right )\,\left (-80\,x^5+\frac {25\,x^4}{2}+\frac {25\,x^3}{2}\right )-25\,x^6}{x^4\,{\ln \left (x\right )}^2} \]
[In]
[Out]