Integrand size = 27, antiderivative size = 28 \[ \int \frac {1}{5} \left (-55+6 x+60 x^2+\left (-60+12 x-90 x^2\right ) \log (x)\right ) \, dx=x-6 x^2 \left (-x+\left (-\frac {-2+\frac {x}{5}}{x}+x\right ) \log (x)\right ) \]
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Time = 0.03 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.148, Rules used = {12, 2403, 2332, 2341} \[ \int \frac {1}{5} \left (-55+6 x+60 x^2+\left (-60+12 x-90 x^2\right ) \log (x)\right ) \, dx=6 x^3-6 x^3 \log (x)+\frac {6}{5} x^2 \log (x)+x-12 x \log (x) \]
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Rule 12
Rule 2332
Rule 2341
Rule 2403
Rubi steps \begin{align*} \text {integral}& = \frac {1}{5} \int \left (-55+6 x+60 x^2+\left (-60+12 x-90 x^2\right ) \log (x)\right ) \, dx \\ & = -11 x+\frac {3 x^2}{5}+4 x^3+\frac {1}{5} \int \left (-60+12 x-90 x^2\right ) \log (x) \, dx \\ & = -11 x+\frac {3 x^2}{5}+4 x^3+\frac {1}{5} \int \left (-60 \log (x)+12 x \log (x)-90 x^2 \log (x)\right ) \, dx \\ & = -11 x+\frac {3 x^2}{5}+4 x^3+\frac {12}{5} \int x \log (x) \, dx-12 \int \log (x) \, dx-18 \int x^2 \log (x) \, dx \\ & = x+6 x^3-12 x \log (x)+\frac {6}{5} x^2 \log (x)-6 x^3 \log (x) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00 \[ \int \frac {1}{5} \left (-55+6 x+60 x^2+\left (-60+12 x-90 x^2\right ) \log (x)\right ) \, dx=x+6 x^3-12 x \log (x)+\frac {6}{5} x^2 \log (x)-6 x^3 \log (x) \]
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Time = 0.01 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93
method | result | size |
risch | \(\frac {\left (-30 x^{3}+6 x^{2}-60 x \right ) \ln \left (x \right )}{5}+6 x^{3}+x\) | \(26\) |
default | \(x -6 x^{3} \ln \left (x \right )+6 x^{3}+\frac {6 x^{2} \ln \left (x \right )}{5}-12 x \ln \left (x \right )\) | \(27\) |
norman | \(x -6 x^{3} \ln \left (x \right )+6 x^{3}+\frac {6 x^{2} \ln \left (x \right )}{5}-12 x \ln \left (x \right )\) | \(27\) |
parallelrisch | \(x -6 x^{3} \ln \left (x \right )+6 x^{3}+\frac {6 x^{2} \ln \left (x \right )}{5}-12 x \ln \left (x \right )\) | \(27\) |
parts | \(x -6 x^{3} \ln \left (x \right )+6 x^{3}+\frac {6 x^{2} \ln \left (x \right )}{5}-12 x \ln \left (x \right )\) | \(27\) |
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Time = 0.26 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.89 \[ \int \frac {1}{5} \left (-55+6 x+60 x^2+\left (-60+12 x-90 x^2\right ) \log (x)\right ) \, dx=6 \, x^{3} - \frac {6}{5} \, {\left (5 \, x^{3} - x^{2} + 10 \, x\right )} \log \left (x\right ) + x \]
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Time = 0.06 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.86 \[ \int \frac {1}{5} \left (-55+6 x+60 x^2+\left (-60+12 x-90 x^2\right ) \log (x)\right ) \, dx=6 x^{3} + x + \left (- 6 x^{3} + \frac {6 x^{2}}{5} - 12 x\right ) \log {\left (x \right )} \]
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Time = 0.23 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.89 \[ \int \frac {1}{5} \left (-55+6 x+60 x^2+\left (-60+12 x-90 x^2\right ) \log (x)\right ) \, dx=6 \, x^{3} - \frac {6}{5} \, {\left (5 \, x^{3} - x^{2} + 10 \, x\right )} \log \left (x\right ) + x \]
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Time = 0.28 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93 \[ \int \frac {1}{5} \left (-55+6 x+60 x^2+\left (-60+12 x-90 x^2\right ) \log (x)\right ) \, dx=-6 \, x^{3} \log \left (x\right ) + 6 \, x^{3} + \frac {6}{5} \, x^{2} \log \left (x\right ) - 12 \, x \log \left (x\right ) + x \]
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Time = 8.15 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93 \[ \int \frac {1}{5} \left (-55+6 x+60 x^2+\left (-60+12 x-90 x^2\right ) \log (x)\right ) \, dx=\frac {x\,\left (6\,x\,\ln \left (x\right )-30\,x^2\,\ln \left (x\right )-60\,\ln \left (x\right )+30\,x^2+5\right )}{5} \]
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