Integrand size = 109, antiderivative size = 25 \[ \int \frac {\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \left (e^{-3+x^2} \left (2 x+2 x^2\right )+e^{-3+x^2} \left (-4-2 x+8 x^2+4 x^3+e^x \left (-2+4 x^2\right )\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{2 x^2+e^x x^2+x^3} \, dx=\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \]
[Out]
\[ \int \frac {\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \left (e^{-3+x^2} \left (2 x+2 x^2\right )+e^{-3+x^2} \left (-4-2 x+8 x^2+4 x^3+e^x \left (-2+4 x^2\right )\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{2 x^2+e^x x^2+x^3} \, dx=\int \frac {\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \left (e^{-3+x^2} \left (2 x+2 x^2\right )+e^{-3+x^2} \left (-4-2 x+8 x^2+4 x^3+e^x \left (-2+4 x^2\right )\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{2 x^2+e^x x^2+x^3} \, dx \]
[In]
[Out]
Rubi steps \begin{align*} \text {integral}& = \int \frac {2 e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \left (x (1+x)+\left (2+e^x+x\right ) \left (-1+2 x^2\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{x^2} \, dx \\ & = 2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \left (x (1+x)+\left (2+e^x+x\right ) \left (-1+2 x^2\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{x^2} \, dx \\ & = 2 \int \left (\frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \left (-1+2 x^2\right ) \log \left (\frac {e^x}{2+e^x+x}\right )}{x^2}+\frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \left (x+x^2-2 \log \left (\frac {e^x}{2+e^x+x}\right )-x \log \left (\frac {e^x}{2+e^x+x}\right )+4 x^2 \log \left (\frac {e^x}{2+e^x+x}\right )+2 x^3 \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{x^2}\right ) \, dx \\ & = 2 \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \left (-1+2 x^2\right ) \log \left (\frac {e^x}{2+e^x+x}\right )}{x^2} \, dx+2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \left (x+x^2-2 \log \left (\frac {e^x}{2+e^x+x}\right )-x \log \left (\frac {e^x}{2+e^x+x}\right )+4 x^2 \log \left (\frac {e^x}{2+e^x+x}\right )+2 x^3 \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{x^2} \, dx \\ & = 2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \left (x (1+x)+\left (-2-x+4 x^2+2 x^3\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{x^2} \, dx-2 \int \frac {(1+x) \left (2 \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-\int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx\right )}{2+e^x+x} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx \\ & = 2 \int \left (\frac {e^{-3-x+x^2} (1+x) \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x}+\frac {e^{-3-x+x^2} (2+x) \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \left (-1+2 x^2\right ) \log \left (\frac {e^x}{2+e^x+x}\right )}{x^2}\right ) \, dx-2 \int \left (\frac {2 \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-\int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x}+\frac {x \left (2 \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-\int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx\right )}{2+e^x+x}\right ) \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx \\ & = 2 \int \frac {e^{-3-x+x^2} (1+x) \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+2 \int \frac {e^{-3-x+x^2} (2+x) \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \left (-1+2 x^2\right ) \log \left (\frac {e^x}{2+e^x+x}\right )}{x^2} \, dx-2 \int \frac {2 \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-\int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx-2 \int \frac {x \left (2 \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-\int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx\right )}{2+e^x+x} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx \\ & = 2 \int \left (e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}+\frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x}\right ) \, dx-2 \int \left (\frac {2 \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x}-\frac {\int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x}\right ) \, dx-2 \int \left (\frac {2 x \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x}-\frac {x \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x}\right ) \, dx-2 \int \frac {(1+x) \left (4 \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx-\int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+2 \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx\right )}{2+e^x+x} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx+\left (8 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx \\ & = 2 \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx+2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+2 \int \frac {\int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx+2 \int \frac {x \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx-2 \int \left (\frac {4 \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx-\int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+2 \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x}+\frac {x \left (4 \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx-\int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+2 \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx\right )}{2+e^x+x}\right ) \, dx-4 \int \frac {\int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-4 \int \frac {x \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx+\left (8 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx \\ & = 2 \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx+2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+2 \int \frac {\int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx+2 \int \frac {x \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx-2 \int \frac {4 \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx-\int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+2 \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-2 \int \frac {x \left (4 \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx-\int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+2 \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx\right )}{2+e^x+x} \, dx-4 \int \frac {\int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-4 \int \frac {x \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx+\left (8 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx \\ & = 2 \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx+2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+2 \int \frac {\int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx+2 \int \frac {x \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx-2 \int \left (\frac {4 \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x}-\frac {2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x}-\frac {\int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx}{2+e^x+x}+\frac {2 \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x}\right ) \, dx-2 \int \left (\frac {4 x \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x}-\frac {2 x \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x}-\frac {x \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx}{2+e^x+x}+\frac {2 x \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x}\right ) \, dx-4 \int \frac {\int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-4 \int \frac {x \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx+\left (8 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx \\ & = 2 \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx+2 \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+2 \int \frac {\int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx+2 \int \frac {x \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx+2 \int \frac {\int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx}{2+e^x+x} \, dx+2 \int \frac {x \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx}{2+e^x+x} \, dx-4 \int \frac {\int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-4 \int \frac {x \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx+4 \int \frac {\int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx+4 \int \frac {x \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx}{2+e^x+x} \, dx-4 \int \frac {\int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-4 \int \frac {x \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-8 \int \frac {\int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-8 \int \frac {x \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx}{2+e^x+x} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx-\left (2 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx-\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int \frac {e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}}}{x^2} \, dx+\left (4 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3-x+x^2} x \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx+\left (8 \log \left (\frac {e^x}{2+e^x+x}\right )\right ) \int e^{-3-x+x^2} \left (\frac {e^x}{2+e^x+x}\right )^{1+\frac {2 e^{-3+x^2}}{x}} \, dx \\ \end{align*}
Time = 5.23 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00 \[ \int \frac {\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \left (e^{-3+x^2} \left (2 x+2 x^2\right )+e^{-3+x^2} \left (-4-2 x+8 x^2+4 x^3+e^x \left (-2+4 x^2\right )\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{2 x^2+e^x x^2+x^3} \, dx=\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \]
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Time = 34.56 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00
method | result | size |
parallelrisch | \({\mathrm e}^{\frac {2 \,{\mathrm e}^{x^{2}-3} \ln \left (\frac {{\mathrm e}^{x}}{{\mathrm e}^{x}+2+x}\right )}{x}}\) | \(25\) |
risch | \(\left ({\mathrm e}^{x}+2+x \right )^{-\frac {2 \,{\mathrm e}^{x^{2}-3}}{x}} \left ({\mathrm e}^{x}\right )^{\frac {2 \,{\mathrm e}^{x^{2}-3}}{x}} {\mathrm e}^{-\frac {i {\mathrm e}^{x^{2}-3} \pi \,\operatorname {csgn}\left (\frac {i {\mathrm e}^{x}}{{\mathrm e}^{x}+2+x}\right ) \left (-\operatorname {csgn}\left (\frac {i {\mathrm e}^{x}}{{\mathrm e}^{x}+2+x}\right )+\operatorname {csgn}\left (i {\mathrm e}^{x}\right )\right ) \left (-\operatorname {csgn}\left (\frac {i {\mathrm e}^{x}}{{\mathrm e}^{x}+2+x}\right )+\operatorname {csgn}\left (\frac {i}{{\mathrm e}^{x}+2+x}\right )\right )}{x}}\) | \(112\) |
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Time = 0.24 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.88 \[ \int \frac {\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \left (e^{-3+x^2} \left (2 x+2 x^2\right )+e^{-3+x^2} \left (-4-2 x+8 x^2+4 x^3+e^x \left (-2+4 x^2\right )\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{2 x^2+e^x x^2+x^3} \, dx=\left (\frac {e^{x}}{x + e^{x} + 2}\right )^{\frac {2 \, e^{\left (x^{2} - 3\right )}}{x}} \]
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Timed out. \[ \int \frac {\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \left (e^{-3+x^2} \left (2 x+2 x^2\right )+e^{-3+x^2} \left (-4-2 x+8 x^2+4 x^3+e^x \left (-2+4 x^2\right )\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{2 x^2+e^x x^2+x^3} \, dx=\text {Timed out} \]
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Time = 0.27 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.08 \[ \int \frac {\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \left (e^{-3+x^2} \left (2 x+2 x^2\right )+e^{-3+x^2} \left (-4-2 x+8 x^2+4 x^3+e^x \left (-2+4 x^2\right )\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{2 x^2+e^x x^2+x^3} \, dx=e^{\left (-\frac {2 \, e^{\left (x^{2} - 3\right )} \log \left (x + e^{x} + 2\right )}{x} + 2 \, e^{\left (x^{2} - 3\right )}\right )} \]
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\[ \int \frac {\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \left (e^{-3+x^2} \left (2 x+2 x^2\right )+e^{-3+x^2} \left (-4-2 x+8 x^2+4 x^3+e^x \left (-2+4 x^2\right )\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{2 x^2+e^x x^2+x^3} \, dx=\int { \frac {2 \, {\left ({\left (2 \, x^{3} + 4 \, x^{2} + {\left (2 \, x^{2} - 1\right )} e^{x} - x - 2\right )} e^{\left (x^{2} - 3\right )} \log \left (\frac {e^{x}}{x + e^{x} + 2}\right ) + {\left (x^{2} + x\right )} e^{\left (x^{2} - 3\right )}\right )} \left (\frac {e^{x}}{x + e^{x} + 2}\right )^{\frac {2 \, e^{\left (x^{2} - 3\right )}}{x}}}{x^{3} + x^{2} e^{x} + 2 \, x^{2}} \,d x } \]
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Time = 11.14 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.16 \[ \int \frac {\left (\frac {e^x}{2+e^x+x}\right )^{\frac {2 e^{-3+x^2}}{x}} \left (e^{-3+x^2} \left (2 x+2 x^2\right )+e^{-3+x^2} \left (-4-2 x+8 x^2+4 x^3+e^x \left (-2+4 x^2\right )\right ) \log \left (\frac {e^x}{2+e^x+x}\right )\right )}{2 x^2+e^x x^2+x^3} \, dx={\mathrm {e}}^{2\,{\mathrm {e}}^{x^2}\,{\mathrm {e}}^{-3}}\,{\left (\frac {1}{x+{\mathrm {e}}^x+2}\right )}^{\frac {2\,{\mathrm {e}}^{x^2-3}}{x}} \]
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