Integrand size = 14, antiderivative size = 27 \[ \int \frac {1}{10} \left (-22 x-5 \log \left (x^2\right )\right ) \, dx=x \left (-\frac {8 x}{5}+\frac {1+x}{x}+\frac {1}{2} \left (x-\log \left (x^2\right )\right )\right ) \]
[Out]
Time = 0.00 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.67, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {12, 2332} \[ \int \frac {1}{10} \left (-22 x-5 \log \left (x^2\right )\right ) \, dx=-\frac {11 x^2}{10}-\frac {1}{2} x \log \left (x^2\right )+x \]
[In]
[Out]
Rule 12
Rule 2332
Rubi steps \begin{align*} \text {integral}& = \frac {1}{10} \int \left (-22 x-5 \log \left (x^2\right )\right ) \, dx \\ & = -\frac {11 x^2}{10}-\frac {1}{2} \int \log \left (x^2\right ) \, dx \\ & = x-\frac {11 x^2}{10}-\frac {1}{2} x \log \left (x^2\right ) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.67 \[ \int \frac {1}{10} \left (-22 x-5 \log \left (x^2\right )\right ) \, dx=x-\frac {11 x^2}{10}-\frac {1}{2} x \log \left (x^2\right ) \]
[In]
[Out]
Time = 0.02 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.56
method | result | size |
default | \(-\frac {11 x^{2}}{10}-\frac {x \ln \left (x^{2}\right )}{2}+x\) | \(15\) |
norman | \(-\frac {11 x^{2}}{10}-\frac {x \ln \left (x^{2}\right )}{2}+x\) | \(15\) |
risch | \(-\frac {11 x^{2}}{10}-\frac {x \ln \left (x^{2}\right )}{2}+x\) | \(15\) |
parallelrisch | \(-\frac {11 x^{2}}{10}-\frac {x \ln \left (x^{2}\right )}{2}+x\) | \(15\) |
parts | \(-\frac {11 x^{2}}{10}-\frac {x \ln \left (x^{2}\right )}{2}+x\) | \(15\) |
[In]
[Out]
none
Time = 0.24 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.52 \[ \int \frac {1}{10} \left (-22 x-5 \log \left (x^2\right )\right ) \, dx=-\frac {11}{10} \, x^{2} - \frac {1}{2} \, x \log \left (x^{2}\right ) + x \]
[In]
[Out]
Time = 0.05 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.56 \[ \int \frac {1}{10} \left (-22 x-5 \log \left (x^2\right )\right ) \, dx=- \frac {11 x^{2}}{10} - \frac {x \log {\left (x^{2} \right )}}{2} + x \]
[In]
[Out]
none
Time = 0.19 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.52 \[ \int \frac {1}{10} \left (-22 x-5 \log \left (x^2\right )\right ) \, dx=-\frac {11}{10} \, x^{2} - \frac {1}{2} \, x \log \left (x^{2}\right ) + x \]
[In]
[Out]
none
Time = 0.27 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.52 \[ \int \frac {1}{10} \left (-22 x-5 \log \left (x^2\right )\right ) \, dx=-\frac {11}{10} \, x^{2} - \frac {1}{2} \, x \log \left (x^{2}\right ) + x \]
[In]
[Out]
Time = 10.68 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.44 \[ \int \frac {1}{10} \left (-22 x-5 \log \left (x^2\right )\right ) \, dx=-\frac {x\,\left (11\,x+\ln \left (x^{10}\right )-10\right )}{10} \]
[In]
[Out]