Integrand size = 116, antiderivative size = 27 \[ \int \frac {e^{-5-x} \left (-1+x-2 x^2+x^3-(-1+x) \log \left (\frac {7}{4}\right )+e^{5+x} \left (1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )\right )\right )}{1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )} \, dx=x+\frac {e^{-5-x} x}{-1+3 x-x^2+\log \left (\frac {7}{4}\right )} \]
[Out]
Result contains higher order function than in optimal. Order 4 vs. order 3 in optimal.
Time = 5.65 (sec) , antiderivative size = 1653, normalized size of antiderivative = 61.22, number of steps used = 67, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.052, Rules used = {6820, 6874, 2300, 2209, 2208, 6860} \[ \int \frac {e^{-5-x} \left (-1+x-2 x^2+x^3-(-1+x) \log \left (\frac {7}{4}\right )+e^{5+x} \left (1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )\right )\right )}{1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )} \, dx =\text {Too large to display} \]
[In]
[Out]
Rule 2208
Rule 2209
Rule 2300
Rule 6820
Rule 6860
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \int \frac {e^{-5-x} \left (-1-2 x^2+x^3+x \left (1-\log \left (\frac {7}{4}\right )\right )+e^{5+x} \left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2+\log \left (\frac {7}{4}\right )\right )}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2} \, dx \\ & = \int \left (1-\frac {2 e^{-5-x} x^2}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2}+\frac {e^{-5-x} x^3}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2}-\frac {e^{-5-x} \left (1-\log \left (\frac {7}{4}\right )\right )}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2}-\frac {e^{-5-x} x \left (-1+\log \left (\frac {7}{4}\right )\right )}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2}\right ) \, dx \\ & = x-2 \int \frac {e^{-5-x} x^2}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2} \, dx+\left (1-\log \left (\frac {7}{4}\right )\right ) \int \frac {e^{-5-x} x}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2} \, dx+\left (-1+\log \left (\frac {7}{4}\right )\right ) \int \frac {e^{-5-x}}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2} \, dx+\int \frac {e^{-5-x} x^3}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2} \, dx \\ & = x-2 \int \left (\frac {e^{-5-x}}{1-3 x+x^2-\log \left (\frac {7}{4}\right )}+\frac {e^{-5-x} \left (-1+3 x+\log \left (\frac {7}{4}\right )\right )}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2}\right ) \, dx+\left (1-\log \left (\frac {7}{4}\right )\right ) \int \left (\frac {2 e^{-5-x} \left (3+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )}{\left (5+4 \log \left (\frac {7}{4}\right )\right ) \left (3-2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )^2}+\frac {6 e^{-5-x}}{\left (5+4 \log \left (\frac {7}{4}\right )\right )^{3/2} \left (3-2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )}+\frac {2 e^{-5-x} \left (3-\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )}{\left (5+4 \log \left (\frac {7}{4}\right )\right ) \left (-3+2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )^2}+\frac {6 e^{-5-x}}{\left (5+4 \log \left (\frac {7}{4}\right )\right )^{3/2} \left (-3+2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )}\right ) \, dx+\left (-1+\log \left (\frac {7}{4}\right )\right ) \int \left (\frac {4 e^{-5-x}}{\left (5+4 \log \left (\frac {7}{4}\right )\right ) \left (3-2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )^2}+\frac {4 e^{-5-x}}{\left (5+4 \log \left (\frac {7}{4}\right )\right )^{3/2} \left (3-2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )}+\frac {4 e^{-5-x}}{\left (5+4 \log \left (\frac {7}{4}\right )\right ) \left (-3+2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )^2}+\frac {4 e^{-5-x}}{\left (5+4 \log \left (\frac {7}{4}\right )\right )^{3/2} \left (-3+2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )}\right ) \, dx+\int \left (\frac {e^{-5-x} (3+x)}{1-3 x+x^2-\log \left (\frac {7}{4}\right )}+\frac {e^{-5-x} \left (-3 \left (1-\log \left (\frac {7}{4}\right )\right )+x \left (8+\log \left (\frac {7}{4}\right )\right )\right )}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2}\right ) \, dx \\ & = x-2 \int \frac {e^{-5-x}}{1-3 x+x^2-\log \left (\frac {7}{4}\right )} \, dx-2 \int \frac {e^{-5-x} \left (-1+3 x+\log \left (\frac {7}{4}\right )\right )}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2} \, dx-\frac {\left (4 \left (1-\log \left (\frac {7}{4}\right )\right )\right ) \int \frac {e^{-5-x}}{3-2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}} \, dx}{\left (5+4 \log \left (\frac {7}{4}\right )\right )^{3/2}}-\frac {\left (4 \left (1-\log \left (\frac {7}{4}\right )\right )\right ) \int \frac {e^{-5-x}}{-3+2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}} \, dx}{\left (5+4 \log \left (\frac {7}{4}\right )\right )^{3/2}}+\frac {\left (6 \left (1-\log \left (\frac {7}{4}\right )\right )\right ) \int \frac {e^{-5-x}}{3-2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}} \, dx}{\left (5+4 \log \left (\frac {7}{4}\right )\right )^{3/2}}+\frac {\left (6 \left (1-\log \left (\frac {7}{4}\right )\right )\right ) \int \frac {e^{-5-x}}{-3+2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}} \, dx}{\left (5+4 \log \left (\frac {7}{4}\right )\right )^{3/2}}-\frac {\left (4 \left (1-\log \left (\frac {7}{4}\right )\right )\right ) \int \frac {e^{-5-x}}{\left (3-2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )^2} \, dx}{5+4 \log \left (\frac {7}{4}\right )}-\frac {\left (4 \left (1-\log \left (\frac {7}{4}\right )\right )\right ) \int \frac {e^{-5-x}}{\left (-3+2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )^2} \, dx}{5+4 \log \left (\frac {7}{4}\right )}+\frac {\left (2 \left (1-\log \left (\frac {7}{4}\right )\right ) \left (3-\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )\right ) \int \frac {e^{-5-x}}{\left (-3+2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )^2} \, dx}{5+4 \log \left (\frac {7}{4}\right )}+\frac {\left (2 \left (1-\log \left (\frac {7}{4}\right )\right ) \left (3+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )\right ) \int \frac {e^{-5-x}}{\left (3-2 x+\sqrt {5+4 \log \left (\frac {7}{4}\right )}\right )^2} \, dx}{5+4 \log \left (\frac {7}{4}\right )}+\int \frac {e^{-5-x} (3+x)}{1-3 x+x^2-\log \left (\frac {7}{4}\right )} \, dx+\int \frac {e^{-5-x} \left (-3 \left (1-\log \left (\frac {7}{4}\right )\right )+x \left (8+\log \left (\frac {7}{4}\right )\right )\right )}{\left (1-3 x+x^2-\log \left (\frac {7}{4}\right )\right )^2} \, dx \\ & = \text {Too large to display} \\ \end{align*}
Time = 5.07 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.04 \[ \int \frac {e^{-5-x} \left (-1+x-2 x^2+x^3-(-1+x) \log \left (\frac {7}{4}\right )+e^{5+x} \left (1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )\right )\right )}{1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )} \, dx=x-\frac {e^{-5-x} x}{1-3 x+x^2-\log \left (\frac {7}{4}\right )} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. \(60\) vs. \(2(26)=52\).
Time = 0.38 (sec) , antiderivative size = 61, normalized size of antiderivative = 2.26
method | result | size |
parallelrisch | \(\frac {\left (x^{3} {\mathrm e}^{5+x}+\ln \left (\frac {4}{7}\right ) {\mathrm e}^{5+x} x +3 \ln \left (\frac {4}{7}\right ) {\mathrm e}^{5+x}-8 x \,{\mathrm e}^{5+x}-x +3 \,{\mathrm e}^{5+x}\right ) {\mathrm e}^{-x -5}}{x^{2}+\ln \left (\frac {4}{7}\right )-3 x +1}\) | \(61\) |
norman | \(\frac {\left (x^{3} {\mathrm e}^{5+x}+\left (-3 \ln \left (7\right )+6 \ln \left (2\right )+3\right ) {\mathrm e}^{5+x}+\left (-8+2 \ln \left (2\right )-\ln \left (7\right )\right ) x \,{\mathrm e}^{5+x}-x \right ) {\mathrm e}^{-x -5}}{x^{2}+\ln \left (\frac {4}{7}\right )-3 x +1}\) | \(63\) |
parts | \(x +\frac {4 \ln \left (7\right ) {\mathrm e}^{-x -5}}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}+\frac {96 \,{\mathrm e}^{-x -5} \left (-17+13 x +2 \ln \left (7\right )-4 \ln \left (2\right )\right )}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}-\frac {8 \ln \left (2\right ) {\mathrm e}^{-x -5}}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}-\frac {2 \ln \left (7\right )^{2} {\mathrm e}^{-x -5}}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}-\frac {\ln \left (7\right ) {\mathrm e}^{-x -5} \left (5+x \right )}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}+\frac {8 \ln \left (2\right ) \ln \left (7\right ) {\mathrm e}^{-x -5}}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}-\frac {17 \,{\mathrm e}^{-x -5} \left (2 \ln \left (7\right ) \left (5+x \right )-4 \ln \left (2\right ) \left (5+x \right )+13 \ln \left (7\right )-26 \ln \left (2\right )-98+87 x \right )}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}+\frac {{\mathrm e}^{-x -5} \left (2 \ln \left (7\right )^{2}-8 \ln \left (2\right ) \ln \left (7\right )+39 \ln \left (7\right ) \left (5+x \right )+8 \ln \left (2\right )^{2}-78 \ln \left (2\right ) \left (5+x \right )+5 \ln \left (7\right )-10 \ln \left (2\right )-577+598 x \right )}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}-\frac {181 \,{\mathrm e}^{-x -5} \left (-3+2 x \right )}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}+\frac {2 \ln \left (2\right ) {\mathrm e}^{-x -5} \left (5+x \right )}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}-\frac {8 \ln \left (2\right )^{2} {\mathrm e}^{-x -5}}{\left (4 \ln \left (7\right )-8 \ln \left (2\right )+5\right ) \left (-\left (5+x \right )^{2}+\ln \left (7\right )-2 \ln \left (2\right )+24+13 x \right )}\) | \(558\) |
derivativedivides | \(\text {Expression too large to display}\) | \(2086\) |
default | \(\text {Expression too large to display}\) | \(2086\) |
[In]
[Out]
none
Time = 0.25 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.56 \[ \int \frac {e^{-5-x} \left (-1+x-2 x^2+x^3-(-1+x) \log \left (\frac {7}{4}\right )+e^{5+x} \left (1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )\right )\right )}{1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )} \, dx=\frac {{\left ({\left (x^{3} - 3 \, x^{2} + x \log \left (\frac {4}{7}\right ) + x\right )} e^{\left (x + 5\right )} - x\right )} e^{\left (-x - 5\right )}}{x^{2} - 3 \, x + \log \left (\frac {4}{7}\right ) + 1} \]
[In]
[Out]
Time = 0.15 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.96 \[ \int \frac {e^{-5-x} \left (-1+x-2 x^2+x^3-(-1+x) \log \left (\frac {7}{4}\right )+e^{5+x} \left (1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )\right )\right )}{1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )} \, dx=x - \frac {x e^{- x - 5}}{x^{2} - 3 x - \log {\left (7 \right )} + 1 + 2 \log {\left (2 \right )}} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 898 vs. \(2 (23) = 46\).
Time = 0.37 (sec) , antiderivative size = 898, normalized size of antiderivative = 33.26 \[ \int \frac {e^{-5-x} \left (-1+x-2 x^2+x^3-(-1+x) \log \left (\frac {7}{4}\right )+e^{5+x} \left (1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )\right )\right )}{1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )} \, dx=\text {Too large to display} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 53 vs. \(2 (23) = 46\).
Time = 0.31 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.96 \[ \int \frac {e^{-5-x} \left (-1+x-2 x^2+x^3-(-1+x) \log \left (\frac {7}{4}\right )+e^{5+x} \left (1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )\right )\right )}{1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )} \, dx=\frac {x^{3} e^{5} - 3 \, x^{2} e^{5} + x e^{5} \log \left (\frac {4}{7}\right ) + x e^{5} - x e^{\left (-x\right )}}{x^{2} e^{5} - 3 \, x e^{5} + e^{5} \log \left (\frac {4}{7}\right ) + e^{5}} \]
[In]
[Out]
Timed out. \[ \int \frac {e^{-5-x} \left (-1+x-2 x^2+x^3-(-1+x) \log \left (\frac {7}{4}\right )+e^{5+x} \left (1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )\right )\right )}{1-6 x+11 x^2-6 x^3+x^4-\left (2-6 x+2 x^2\right ) \log \left (\frac {7}{4}\right )+\log ^2\left (\frac {7}{4}\right )} \, dx=\int \frac {{\mathrm {e}}^{-x-5}\,\left (x+{\mathrm {e}}^{x+5}\,\left (\ln \left (\frac {4}{7}\right )\,\left (2\,x^2-6\,x+2\right )-6\,x+{\ln \left (\frac {4}{7}\right )}^2+11\,x^2-6\,x^3+x^4+1\right )+\ln \left (\frac {4}{7}\right )\,\left (x-1\right )-2\,x^2+x^3-1\right )}{\ln \left (\frac {4}{7}\right )\,\left (2\,x^2-6\,x+2\right )-6\,x+{\ln \left (\frac {4}{7}\right )}^2+11\,x^2-6\,x^3+x^4+1} \,d x \]
[In]
[Out]