Integrand size = 9, antiderivative size = 9 \[ \int \left (80 x+64 x^3\right ) \, dx=\left (-5-4 x^2\right )^2 \]
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Time = 0.00 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.22, number of steps used = 1, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \left (80 x+64 x^3\right ) \, dx=16 x^4+40 x^2 \]
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Rubi steps \begin{align*} \text {integral}& = 40 x^2+16 x^4 \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.22 \[ \int \left (80 x+64 x^3\right ) \, dx=40 x^2+16 x^4 \]
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Time = 0.05 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.11
method | result | size |
default | \(\left (4 x^{2}+5\right )^{2}\) | \(10\) |
norman | \(16 x^{4}+40 x^{2}\) | \(12\) |
risch | \(16 x^{4}+40 x^{2}\) | \(12\) |
parallelrisch | \(16 x^{4}+40 x^{2}\) | \(12\) |
parts | \(16 x^{4}+40 x^{2}\) | \(12\) |
gosper | \(8 x^{2} \left (2 x^{2}+5\right )\) | \(13\) |
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none
Time = 0.23 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.22 \[ \int \left (80 x+64 x^3\right ) \, dx=16 \, x^{4} + 40 \, x^{2} \]
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Time = 0.02 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.89 \[ \int \left (80 x+64 x^3\right ) \, dx=16 x^{4} + 40 x^{2} \]
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none
Time = 0.18 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.22 \[ \int \left (80 x+64 x^3\right ) \, dx=16 \, x^{4} + 40 \, x^{2} \]
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none
Time = 0.27 (sec) , antiderivative size = 11, normalized size of antiderivative = 1.22 \[ \int \left (80 x+64 x^3\right ) \, dx=16 \, x^{4} + 40 \, x^{2} \]
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Time = 0.02 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.33 \[ \int \left (80 x+64 x^3\right ) \, dx=8\,x^2\,\left (2\,x^2+5\right ) \]
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