Integrand size = 70, antiderivative size = 27 \[ \int \frac {e^2+e^{e^{e+3 x+x^2}+x} \left (e^2 \left (1-2 x+x^2\right )+e^{2+e+3 x+x^2} \left (3-4 x-x^2+2 x^3\right )\right )}{1-2 x+x^2} \, dx=e^2 \left (-1+e^{e^{e+x (3+x)}+x}-\frac {x}{-1+x}\right ) \]
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Time = 0.31 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.96, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.057, Rules used = {27, 6820, 12, 6838} \[ \int \frac {e^2+e^{e^{e+3 x+x^2}+x} \left (e^2 \left (1-2 x+x^2\right )+e^{2+e+3 x+x^2} \left (3-4 x-x^2+2 x^3\right )\right )}{1-2 x+x^2} \, dx=e^{x+e^{x (x+3)+e}+2}+\frac {e^2}{1-x} \]
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Rule 12
Rule 27
Rule 6820
Rule 6838
Rubi steps \begin{align*} \text {integral}& = \int \frac {e^2+e^{e^{e+3 x+x^2}+x} \left (e^2 \left (1-2 x+x^2\right )+e^{2+e+3 x+x^2} \left (3-4 x-x^2+2 x^3\right )\right )}{(-1+x)^2} \, dx \\ & = \int e^2 \left (\frac {1}{(-1+x)^2}+e^{e^{e+x (3+x)}+x} \left (1+e^{e+x (3+x)} (3+2 x)\right )\right ) \, dx \\ & = e^2 \int \left (\frac {1}{(-1+x)^2}+e^{e^{e+x (3+x)}+x} \left (1+e^{e+x (3+x)} (3+2 x)\right )\right ) \, dx \\ & = \frac {e^2}{1-x}+e^2 \int e^{e^{e+x (3+x)}+x} \left (1+e^{e+x (3+x)} (3+2 x)\right ) \, dx \\ & = e^{2+e^{e+x (3+x)}+x}+\frac {e^2}{1-x} \\ \end{align*}
Time = 0.55 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.96 \[ \int \frac {e^2+e^{e^{e+3 x+x^2}+x} \left (e^2 \left (1-2 x+x^2\right )+e^{2+e+3 x+x^2} \left (3-4 x-x^2+2 x^3\right )\right )}{1-2 x+x^2} \, dx=e^2 \left (e^{e^{e+3 x+x^2}+x}-\frac {1}{-1+x}\right ) \]
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Time = 0.71 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.93
method | result | size |
risch | \(-\frac {{\mathrm e}^{2}}{-1+x}+{\mathrm e}^{{\mathrm e}^{{\mathrm e}+x^{2}+3 x}+x +2}\) | \(25\) |
parts | \({\mathrm e}^{{\mathrm e}^{{\mathrm e}+x^{2}+3 x}+x} {\mathrm e}^{2}-\frac {{\mathrm e}^{2}}{-1+x}\) | \(27\) |
norman | \(\frac {{\mathrm e}^{{\mathrm e}^{{\mathrm e}+x^{2}+3 x}+x} {\mathrm e}^{2} x -{\mathrm e}^{{\mathrm e}^{{\mathrm e}+x^{2}+3 x}+x} {\mathrm e}^{2}-{\mathrm e}^{2}}{-1+x}\) | \(46\) |
parallelrisch | \(\frac {{\mathrm e}^{{\mathrm e}^{{\mathrm e}+x^{2}+3 x}+x} {\mathrm e}^{2} x -{\mathrm e}^{{\mathrm e}^{{\mathrm e}+x^{2}+3 x}+x} {\mathrm e}^{2}-{\mathrm e}^{2}}{-1+x}\) | \(46\) |
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Time = 0.24 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.37 \[ \int \frac {e^2+e^{e^{e+3 x+x^2}+x} \left (e^2 \left (1-2 x+x^2\right )+e^{2+e+3 x+x^2} \left (3-4 x-x^2+2 x^3\right )\right )}{1-2 x+x^2} \, dx=\frac {{\left (x - 1\right )} e^{\left ({\left (x e^{2} + e^{\left (x^{2} + 3 \, x + e + 2\right )}\right )} e^{\left (-2\right )} + 2\right )} - e^{2}}{x - 1} \]
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Time = 0.16 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.89 \[ \int \frac {e^2+e^{e^{e+3 x+x^2}+x} \left (e^2 \left (1-2 x+x^2\right )+e^{2+e+3 x+x^2} \left (3-4 x-x^2+2 x^3\right )\right )}{1-2 x+x^2} \, dx=e^{2} e^{x + e^{x^{2} + 3 x + e}} - \frac {e^{2}}{x - 1} \]
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Time = 0.27 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.89 \[ \int \frac {e^2+e^{e^{e+3 x+x^2}+x} \left (e^2 \left (1-2 x+x^2\right )+e^{2+e+3 x+x^2} \left (3-4 x-x^2+2 x^3\right )\right )}{1-2 x+x^2} \, dx=-\frac {e^{2}}{x - 1} + e^{\left (x + e^{\left (x^{2} + 3 \, x + e\right )} + 2\right )} \]
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Time = 0.33 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.59 \[ \int \frac {e^2+e^{e^{e+3 x+x^2}+x} \left (e^2 \left (1-2 x+x^2\right )+e^{2+e+3 x+x^2} \left (3-4 x-x^2+2 x^3\right )\right )}{1-2 x+x^2} \, dx=\frac {x e^{\left (x + e^{\left (x^{2} + 3 \, x + e\right )} + 2\right )} - e^{2} - e^{\left (x + e^{\left (x^{2} + 3 \, x + e\right )} + 2\right )}}{x - 1} \]
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Time = 11.46 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.04 \[ \int \frac {e^2+e^{e^{e+3 x+x^2}+x} \left (e^2 \left (1-2 x+x^2\right )+e^{2+e+3 x+x^2} \left (3-4 x-x^2+2 x^3\right )\right )}{1-2 x+x^2} \, dx={\mathrm {e}}^{{\mathrm {e}}^{3\,x}\,{\mathrm {e}}^{x^2}\,{\mathrm {e}}^{\mathrm {e}}}\,{\mathrm {e}}^2\,{\mathrm {e}}^x-\frac {{\mathrm {e}}^2}{x-1} \]
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