Integrand size = 36, antiderivative size = 23 \[ \int \frac {48+e^{4 x} (24-48 x)+e^{e^2} \left (-16+e^{4 x} (-8+16 x)\right )}{x^3} \, dx=4-\frac {4 \left (-3+e^{e^2}\right ) \left (-2-e^{4 x}\right )}{x^2} \]
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Time = 0.03 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.48, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {14, 2228} \[ \int \frac {48+e^{4 x} (24-48 x)+e^{e^2} \left (-16+e^{4 x} (-8+16 x)\right )}{x^3} \, dx=-\frac {4 \left (3-e^{e^2}\right ) e^{4 x}}{x^2}-\frac {8 \left (3-e^{e^2}\right )}{x^2} \]
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Rule 14
Rule 2228
Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {16 \left (-3+e^{e^2}\right )}{x^3}+\frac {8 e^{4 x} \left (-3+e^{e^2}\right ) (-1+2 x)}{x^3}\right ) \, dx \\ & = -\frac {8 \left (3-e^{e^2}\right )}{x^2}-\left (8 \left (3-e^{e^2}\right )\right ) \int \frac {e^{4 x} (-1+2 x)}{x^3} \, dx \\ & = -\frac {8 \left (3-e^{e^2}\right )}{x^2}-\frac {4 e^{4 x} \left (3-e^{e^2}\right )}{x^2} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.09 \[ \int \frac {48+e^{4 x} (24-48 x)+e^{e^2} \left (-16+e^{4 x} (-8+16 x)\right )}{x^3} \, dx=8 \left (-3+e^{e^2}\right ) \left (\frac {1}{x^2}+\frac {e^{4 x}}{2 x^2}\right ) \]
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Time = 0.08 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.04
method | result | size |
norman | \(\frac {\left (4 \,{\mathrm e}^{{\mathrm e}^{2}}-12\right ) {\mathrm e}^{4 x}+8 \,{\mathrm e}^{{\mathrm e}^{2}}-24}{x^{2}}\) | \(24\) |
risch | \(\frac {4 \,{\mathrm e}^{{\mathrm e}^{2}+4 x}+8 \,{\mathrm e}^{{\mathrm e}^{2}}-12 \,{\mathrm e}^{4 x}-24}{x^{2}}\) | \(26\) |
parallelrisch | \(\frac {4 \,{\mathrm e}^{4 x} {\mathrm e}^{{\mathrm e}^{2}}-12 \,{\mathrm e}^{4 x}-24+8 \,{\mathrm e}^{{\mathrm e}^{2}}}{x^{2}}\) | \(27\) |
parts | \(-\frac {-16 \,{\mathrm e}^{{\mathrm e}^{2}}+48}{2 x^{2}}-\frac {12 \,{\mathrm e}^{4 x}}{x^{2}}-8 \,{\mathrm e}^{{\mathrm e}^{2}} \left (-\frac {{\mathrm e}^{4 x}}{2 x^{2}}-\frac {2 \,{\mathrm e}^{4 x}}{x}-8 \,\operatorname {Ei}_{1}\left (-4 x \right )\right )+16 \,{\mathrm e}^{{\mathrm e}^{2}} \left (-\frac {{\mathrm e}^{4 x}}{x}-4 \,\operatorname {Ei}_{1}\left (-4 x \right )\right )\) | \(76\) |
default | \(-\frac {24}{x^{2}}-\frac {12 \,{\mathrm e}^{4 x}}{x^{2}}+\frac {8 \,{\mathrm e}^{{\mathrm e}^{2}}}{x^{2}}-8 \,{\mathrm e}^{{\mathrm e}^{2}} \left (-\frac {{\mathrm e}^{4 x}}{2 x^{2}}-\frac {2 \,{\mathrm e}^{4 x}}{x}-8 \,\operatorname {Ei}_{1}\left (-4 x \right )\right )+16 \,{\mathrm e}^{{\mathrm e}^{2}} \left (-\frac {{\mathrm e}^{4 x}}{x}-4 \,\operatorname {Ei}_{1}\left (-4 x \right )\right )\) | \(77\) |
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Time = 0.25 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.00 \[ \int \frac {48+e^{4 x} (24-48 x)+e^{e^2} \left (-16+e^{4 x} (-8+16 x)\right )}{x^3} \, dx=\frac {4 \, {\left ({\left (e^{\left (4 \, x\right )} + 2\right )} e^{\left (e^{2}\right )} - 3 \, e^{\left (4 \, x\right )} - 6\right )}}{x^{2}} \]
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Time = 0.07 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.26 \[ \int \frac {48+e^{4 x} (24-48 x)+e^{e^2} \left (-16+e^{4 x} (-8+16 x)\right )}{x^3} \, dx=\frac {\left (-12 + 4 e^{e^{2}}\right ) e^{4 x}}{x^{2}} - \frac {48 - 16 e^{e^{2}}}{2 x^{2}} \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 0.22 (sec) , antiderivative size = 48, normalized size of antiderivative = 2.09 \[ \int \frac {48+e^{4 x} (24-48 x)+e^{e^2} \left (-16+e^{4 x} (-8+16 x)\right )}{x^3} \, dx=64 \, e^{\left (e^{2}\right )} \Gamma \left (-1, -4 \, x\right ) + 128 \, e^{\left (e^{2}\right )} \Gamma \left (-2, -4 \, x\right ) + \frac {8 \, e^{\left (e^{2}\right )}}{x^{2}} - \frac {24}{x^{2}} - 192 \, \Gamma \left (-1, -4 \, x\right ) - 384 \, \Gamma \left (-2, -4 \, x\right ) \]
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Time = 0.27 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.17 \[ \int \frac {48+e^{4 x} (24-48 x)+e^{e^2} \left (-16+e^{4 x} (-8+16 x)\right )}{x^3} \, dx=-\frac {4 \, {\left (3 \, e^{\left (4 \, x\right )} - e^{\left (4 \, x + e^{2}\right )} - 2 \, e^{\left (e^{2}\right )} + 6\right )}}{x^{2}} \]
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Time = 0.09 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.70 \[ \int \frac {48+e^{4 x} (24-48 x)+e^{e^2} \left (-16+e^{4 x} (-8+16 x)\right )}{x^3} \, dx=\frac {4\,\left ({\mathrm {e}}^{{\mathrm {e}}^2}-3\right )\,\left ({\mathrm {e}}^{4\,x}+2\right )}{x^2} \]
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