Integrand size = 19, antiderivative size = 19 \[ \int \frac {4-27 x-8 x^2-16 x^4}{x} \, dx=x-4 \left (-6+7 x+x^2+x^4-\log (x)\right ) \]
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Time = 0.00 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.95, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {14} \[ \int \frac {4-27 x-8 x^2-16 x^4}{x} \, dx=-4 x^4-4 x^2-27 x+4 \log (x) \]
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Rule 14
Rubi steps \begin{align*} \text {integral}& = \int \left (-27+\frac {4}{x}-8 x-16 x^3\right ) \, dx \\ & = -27 x-4 x^2-4 x^4+4 \log (x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.95 \[ \int \frac {4-27 x-8 x^2-16 x^4}{x} \, dx=-27 x-4 x^2-4 x^4+4 \log (x) \]
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Time = 0.04 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00
method | result | size |
default | \(-4 x^{4}-4 x^{2}-27 x +4 \ln \left (x \right )\) | \(19\) |
norman | \(-4 x^{4}-4 x^{2}-27 x +4 \ln \left (x \right )\) | \(19\) |
risch | \(-4 x^{4}-4 x^{2}-27 x +4 \ln \left (x \right )\) | \(19\) |
parallelrisch | \(-4 x^{4}-4 x^{2}-27 x +4 \ln \left (x \right )\) | \(19\) |
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none
Time = 0.23 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.95 \[ \int \frac {4-27 x-8 x^2-16 x^4}{x} \, dx=-4 \, x^{4} - 4 \, x^{2} - 27 \, x + 4 \, \log \left (x\right ) \]
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Time = 0.03 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.89 \[ \int \frac {4-27 x-8 x^2-16 x^4}{x} \, dx=- 4 x^{4} - 4 x^{2} - 27 x + 4 \log {\left (x \right )} \]
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none
Time = 0.19 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.95 \[ \int \frac {4-27 x-8 x^2-16 x^4}{x} \, dx=-4 \, x^{4} - 4 \, x^{2} - 27 \, x + 4 \, \log \left (x\right ) \]
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none
Time = 0.27 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \[ \int \frac {4-27 x-8 x^2-16 x^4}{x} \, dx=-4 \, x^{4} - 4 \, x^{2} - 27 \, x + 4 \, \log \left ({\left | x \right |}\right ) \]
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Time = 0.03 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.95 \[ \int \frac {4-27 x-8 x^2-16 x^4}{x} \, dx=4\,\ln \left (x\right )-27\,x-4\,x^2-4\,x^4 \]
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