Integrand size = 44, antiderivative size = 24 \[ \int \frac {e^6-4 x^2-2 e^8 x^2-6 x^3+e^4 \left (6 x^2+3 x^3\right )}{e^6 x} \, dx=-\frac {\left (-2+e^4\right ) \left (-1+e^4-x\right ) x^2}{e^6}+\log (x) \]
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Time = 0.01 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.50, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.068, Rules used = {6, 12, 14} \[ \int \frac {e^6-4 x^2-2 e^8 x^2-6 x^3+e^4 \left (6 x^2+3 x^3\right )}{e^6 x} \, dx=-\frac {\left (2-e^4\right ) x^3}{e^6}-\frac {\left (2-3 e^4+e^8\right ) x^2}{e^6}+\log (x) \]
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Rule 6
Rule 12
Rule 14
Rubi steps \begin{align*} \text {integral}& = \int \frac {e^6+\left (-4-2 e^8\right ) x^2-6 x^3+e^4 \left (6 x^2+3 x^3\right )}{e^6 x} \, dx \\ & = \frac {\int \frac {e^6+\left (-4-2 e^8\right ) x^2-6 x^3+e^4 \left (6 x^2+3 x^3\right )}{x} \, dx}{e^6} \\ & = \frac {\int \left (\frac {e^6}{x}-2 \left (2-3 e^4+e^8\right ) x-3 \left (2-e^4\right ) x^2\right ) \, dx}{e^6} \\ & = -\frac {\left (2-3 e^4+e^8\right ) x^2}{e^6}-\frac {\left (2-e^4\right ) x^3}{e^6}+\log (x) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.75 \[ \int \frac {e^6-4 x^2-2 e^8 x^2-6 x^3+e^4 \left (6 x^2+3 x^3\right )}{e^6 x} \, dx=-\frac {2 x^2}{e^6}+\frac {3 x^2}{e^2}-e^2 x^2-\frac {2 x^3}{e^6}+\frac {x^3}{e^2}+\log (x) \]
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Time = 0.08 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.71
method | result | size |
norman | \(\left (\left ({\mathrm e}^{4}-2\right ) {\mathrm e}^{-3} x^{3}-\left ({\mathrm e}^{8}-3 \,{\mathrm e}^{4}+2\right ) {\mathrm e}^{-3} x^{2}\right ) {\mathrm e}^{-3}+\ln \left (x \right )\) | \(41\) |
default | \({\mathrm e}^{-6} \left (x^{3} {\mathrm e}^{4}-x^{2} {\mathrm e}^{8}+3 x^{2} {\mathrm e}^{4}-2 x^{3}-2 x^{2}+{\mathrm e}^{6} \ln \left (x \right )\right )\) | \(42\) |
risch | \(-{\mathrm e}^{-6} {\mathrm e}^{8} x^{2}+{\mathrm e}^{-6} {\mathrm e}^{4} x^{3}+3 \,{\mathrm e}^{-6} {\mathrm e}^{4} x^{2}-2 \,{\mathrm e}^{-6} x^{3}-2 \,{\mathrm e}^{-6} x^{2}+\ln \left (x \right )\) | \(46\) |
parallelrisch | \({\mathrm e}^{-6} \left (x^{3} {\mathrm e}^{4}-x^{2} {\mathrm e}^{8}+3 x^{2} {\mathrm e}^{4}-2 x^{3}-2 x^{2}+{\mathrm e}^{6} \ln \left (x \right )\right )\) | \(46\) |
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Time = 0.25 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.67 \[ \int \frac {e^6-4 x^2-2 e^8 x^2-6 x^3+e^4 \left (6 x^2+3 x^3\right )}{e^6 x} \, dx=-{\left (2 \, x^{3} + x^{2} e^{8} + 2 \, x^{2} - {\left (x^{3} + 3 \, x^{2}\right )} e^{4} - e^{6} \log \left (x\right )\right )} e^{\left (-6\right )} \]
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Time = 0.05 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.29 \[ \int \frac {e^6-4 x^2-2 e^8 x^2-6 x^3+e^4 \left (6 x^2+3 x^3\right )}{e^6 x} \, dx=\frac {- x^{3} \cdot \left (2 - e^{4}\right ) - x^{2} \left (- 3 e^{4} + 2 + e^{8}\right ) + e^{6} \log {\left (x \right )}}{e^{6}} \]
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Time = 0.19 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.25 \[ \int \frac {e^6-4 x^2-2 e^8 x^2-6 x^3+e^4 \left (6 x^2+3 x^3\right )}{e^6 x} \, dx={\left (x^{3} {\left (e^{4} - 2\right )} - x^{2} {\left (e^{8} - 3 \, e^{4} + 2\right )} + e^{6} \log \left (x\right )\right )} e^{\left (-6\right )} \]
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Time = 0.28 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.67 \[ \int \frac {e^6-4 x^2-2 e^8 x^2-6 x^3+e^4 \left (6 x^2+3 x^3\right )}{e^6 x} \, dx={\left (x^{3} e^{4} - 2 \, x^{3} - x^{2} e^{8} + 3 \, x^{2} e^{4} - 2 \, x^{2} + e^{6} \log \left ({\left | x \right |}\right )\right )} e^{\left (-6\right )} \]
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Time = 0.11 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.38 \[ \int \frac {e^6-4 x^2-2 e^8 x^2-6 x^3+e^4 \left (6 x^2+3 x^3\right )}{e^6 x} \, dx=\ln \left (x\right )-\frac {x^2\,{\mathrm {e}}^{-6}\,\left (2\,{\mathrm {e}}^8-6\,{\mathrm {e}}^4+4\right )}{2}+\frac {x^3\,{\mathrm {e}}^{-6}\,\left (3\,{\mathrm {e}}^4-6\right )}{3} \]
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