Integrand size = 156, antiderivative size = 32 \[ \int \frac {e^{\frac {\left (-9 x-27 x^2\right ) \log ^2(3)}{-x-x^2+e^4 (1+3 x)}} \left (x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )+\left (18 x^3+e^4 \left (-9 x-54 x^2-81 x^3\right )\right ) \log ^2(3)\right )}{x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )} \, dx=e^{\frac {9 x \log ^2(3)}{-e^4+\frac {x+x^2}{1+3 x}}} x \]
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Leaf count is larger than twice the leaf count of optimal. \(164\) vs. \(2(32)=64\).
Time = 0.16 (sec) , antiderivative size = 164, normalized size of antiderivative = 5.12, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.006, Rules used = {2326} \[ \int \frac {e^{\frac {\left (-9 x-27 x^2\right ) \log ^2(3)}{-x-x^2+e^4 (1+3 x)}} \left (x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )+\left (18 x^3+e^4 \left (-9 x-54 x^2-81 x^3\right )\right ) \log ^2(3)\right )}{x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )} \, dx=-\frac {\left (2 x^3-e^4 \left (9 x^3+6 x^2+x\right )\right ) \exp \left (\frac {9 \left (3 x^2+x\right ) \log ^2(3)}{x^2+x-e^4 (3 x+1)}\right )}{\left (x^4+2 x^3+x^2+e^8 \left (9 x^2+6 x+1\right )-2 e^4 \left (3 x^3+4 x^2+x\right )\right ) \left (\frac {\left (2 x-3 e^4+1\right ) \left (3 x^2+x\right )}{\left (x^2+x-e^4 (3 x+1)\right )^2}-\frac {6 x+1}{x^2+x-e^4 (3 x+1)}\right )} \]
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Rule 2326
Rubi steps \begin{align*} \text {integral}& = -\frac {\exp \left (\frac {9 \left (x+3 x^2\right ) \log ^2(3)}{x+x^2-e^4 (1+3 x)}\right ) \left (2 x^3-e^4 \left (x+6 x^2+9 x^3\right )\right )}{\left (x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )-2 e^4 \left (x+4 x^2+3 x^3\right )\right ) \left (\frac {\left (1-3 e^4+2 x\right ) \left (x+3 x^2\right )}{\left (x+x^2-e^4 (1+3 x)\right )^2}-\frac {1+6 x}{x+x^2-e^4 (1+3 x)}\right )} \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.06 \[ \int \frac {e^{\frac {\left (-9 x-27 x^2\right ) \log ^2(3)}{-x-x^2+e^4 (1+3 x)}} \left (x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )+\left (18 x^3+e^4 \left (-9 x-54 x^2-81 x^3\right )\right ) \log ^2(3)\right )}{x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )} \, dx=e^{\frac {9 x (1+3 x) \log ^2(3)}{x (1+x)-e^4 (1+3 x)}} x \]
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Time = 0.80 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.06
method | result | size |
gosper | \(x \,{\mathrm e}^{-\frac {9 x \left (1+3 x \right ) \ln \left (3\right )^{2}}{3 x \,{\mathrm e}^{4}-x^{2}+{\mathrm e}^{4}-x}}\) | \(34\) |
risch | \(x \,{\mathrm e}^{-\frac {9 x \left (1+3 x \right ) \ln \left (3\right )^{2}}{3 x \,{\mathrm e}^{4}-x^{2}+{\mathrm e}^{4}-x}}\) | \(34\) |
parallelrisch | \(x \,{\mathrm e}^{\frac {\ln \left (3\right )^{2} \left (-27 x^{2}-9 x \right )}{3 x \,{\mathrm e}^{4}-x^{2}+{\mathrm e}^{4}-x}}\) | \(36\) |
norman | \(\frac {x \,{\mathrm e}^{4} {\mathrm e}^{\frac {\left (-27 x^{2}-9 x \right ) \ln \left (3\right )^{2}}{\left (1+3 x \right ) {\mathrm e}^{4}-x^{2}-x}}+\left (3 \,{\mathrm e}^{4}-1\right ) x^{2} {\mathrm e}^{\frac {\left (-27 x^{2}-9 x \right ) \ln \left (3\right )^{2}}{\left (1+3 x \right ) {\mathrm e}^{4}-x^{2}-x}}-x^{3} {\mathrm e}^{\frac {\left (-27 x^{2}-9 x \right ) \ln \left (3\right )^{2}}{\left (1+3 x \right ) {\mathrm e}^{4}-x^{2}-x}}}{3 x \,{\mathrm e}^{4}-x^{2}+{\mathrm e}^{4}-x}\) | \(142\) |
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Time = 0.24 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.00 \[ \int \frac {e^{\frac {\left (-9 x-27 x^2\right ) \log ^2(3)}{-x-x^2+e^4 (1+3 x)}} \left (x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )+\left (18 x^3+e^4 \left (-9 x-54 x^2-81 x^3\right )\right ) \log ^2(3)\right )}{x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )} \, dx=x e^{\left (\frac {9 \, {\left (3 \, x^{2} + x\right )} \log \left (3\right )^{2}}{x^{2} - {\left (3 \, x + 1\right )} e^{4} + x}\right )} \]
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Time = 1.79 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.97 \[ \int \frac {e^{\frac {\left (-9 x-27 x^2\right ) \log ^2(3)}{-x-x^2+e^4 (1+3 x)}} \left (x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )+\left (18 x^3+e^4 \left (-9 x-54 x^2-81 x^3\right )\right ) \log ^2(3)\right )}{x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )} \, dx=x e^{\frac {\left (- 27 x^{2} - 9 x\right ) \log {\left (3 \right )}^{2}}{- x^{2} - x + \left (3 x + 1\right ) e^{4}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 91 vs. \(2 (30) = 60\).
Time = 0.43 (sec) , antiderivative size = 91, normalized size of antiderivative = 2.84 \[ \int \frac {e^{\frac {\left (-9 x-27 x^2\right ) \log ^2(3)}{-x-x^2+e^4 (1+3 x)}} \left (x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )+\left (18 x^3+e^4 \left (-9 x-54 x^2-81 x^3\right )\right ) \log ^2(3)\right )}{x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )} \, dx=x e^{\left (\frac {81 \, x e^{4} \log \left (3\right )^{2}}{x^{2} - x {\left (3 \, e^{4} - 1\right )} - e^{4}} - \frac {18 \, x \log \left (3\right )^{2}}{x^{2} - x {\left (3 \, e^{4} - 1\right )} - e^{4}} + \frac {27 \, e^{4} \log \left (3\right )^{2}}{x^{2} - x {\left (3 \, e^{4} - 1\right )} - e^{4}} + 27 \, \log \left (3\right )^{2}\right )} \]
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Time = 0.47 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.16 \[ \int \frac {e^{\frac {\left (-9 x-27 x^2\right ) \log ^2(3)}{-x-x^2+e^4 (1+3 x)}} \left (x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )+\left (18 x^3+e^4 \left (-9 x-54 x^2-81 x^3\right )\right ) \log ^2(3)\right )}{x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )} \, dx=x e^{\left (\frac {9 \, {\left (3 \, x^{2} \log \left (3\right )^{2} + x \log \left (3\right )^{2}\right )}}{x^{2} - 3 \, x e^{4} + x - e^{4}}\right )} \]
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Time = 13.69 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.16 \[ \int \frac {e^{\frac {\left (-9 x-27 x^2\right ) \log ^2(3)}{-x-x^2+e^4 (1+3 x)}} \left (x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )+\left (18 x^3+e^4 \left (-9 x-54 x^2-81 x^3\right )\right ) \log ^2(3)\right )}{x^2+2 x^3+x^4+e^8 \left (1+6 x+9 x^2\right )+e^4 \left (-2 x-8 x^2-6 x^3\right )} \, dx=x\,{\mathrm {e}}^{\frac {27\,{\ln \left (3\right )}^2\,x^2+9\,{\ln \left (3\right )}^2\,x}{x-{\mathrm {e}}^4-3\,x\,{\mathrm {e}}^4+x^2}} \]
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