Integrand size = 163, antiderivative size = 27 \[ \int \frac {-16 x+e^{e^{25 x^2}} \left (8-16 x+e^{25 x^2} \left (400 x^2-400 x^3\right )\right )}{-25+75 x^2-75 x^4+25 x^6+e^{3 e^{25 x^2}} \left (-25 x^3+75 x^4-75 x^5+25 x^6\right )+e^{2 e^{25 x^2}} \left (-75 x^2+150 x^3-150 x^5+75 x^6\right )+e^{e^{25 x^2}} \left (-75 x+75 x^2+150 x^3-150 x^4-75 x^5+75 x^6\right )} \, dx=\frac {4}{25 (1-x)^2 \left (1+x+e^{e^{25 x^2}} x\right )^2} \]
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\[ \int \frac {-16 x+e^{e^{25 x^2}} \left (8-16 x+e^{25 x^2} \left (400 x^2-400 x^3\right )\right )}{-25+75 x^2-75 x^4+25 x^6+e^{3 e^{25 x^2}} \left (-25 x^3+75 x^4-75 x^5+25 x^6\right )+e^{2 e^{25 x^2}} \left (-75 x^2+150 x^3-150 x^5+75 x^6\right )+e^{e^{25 x^2}} \left (-75 x+75 x^2+150 x^3-150 x^4-75 x^5+75 x^6\right )} \, dx=\int \frac {-16 x+e^{e^{25 x^2}} \left (8-16 x+e^{25 x^2} \left (400 x^2-400 x^3\right )\right )}{-25+75 x^2-75 x^4+25 x^6+e^{3 e^{25 x^2}} \left (-25 x^3+75 x^4-75 x^5+25 x^6\right )+e^{2 e^{25 x^2}} \left (-75 x^2+150 x^3-150 x^5+75 x^6\right )+e^{e^{25 x^2}} \left (-75 x+75 x^2+150 x^3-150 x^4-75 x^5+75 x^6\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {8 \left (2 x+50 e^{e^{25 x^2}+25 x^2} (-1+x) x^2+e^{e^{25 x^2}} (-1+2 x)\right )}{25 (1-x)^3 \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx \\ & = \frac {8}{25} \int \frac {2 x+50 e^{e^{25 x^2}+25 x^2} (-1+x) x^2+e^{e^{25 x^2}} (-1+2 x)}{(1-x)^3 \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx \\ & = \frac {8}{25} \int \left (-\frac {2 x}{(-1+x)^3 \left (1+x+e^{e^{25 x^2}} x\right )^3}-\frac {50 e^{e^{25 x^2}+25 x^2} x^2}{(-1+x)^2 \left (1+x+e^{e^{25 x^2}} x\right )^3}-\frac {e^{e^{25 x^2}} (-1+2 x)}{(-1+x)^3 \left (1+x+e^{e^{25 x^2}} x\right )^3}\right ) \, dx \\ & = -\left (\frac {8}{25} \int \frac {e^{e^{25 x^2}} (-1+2 x)}{(-1+x)^3 \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx\right )-\frac {16}{25} \int \frac {x}{(-1+x)^3 \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx-16 \int \frac {e^{e^{25 x^2}+25 x^2} x^2}{(-1+x)^2 \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx \\ & = -\left (\frac {8}{25} \int \left (\frac {e^{e^{25 x^2}}}{(-1+x)^3 \left (1+x+e^{e^{25 x^2}} x\right )^3}+\frac {2 e^{e^{25 x^2}}}{(-1+x)^2 \left (1+x+e^{e^{25 x^2}} x\right )^3}\right ) \, dx\right )-\frac {16}{25} \int \left (\frac {1}{(-1+x)^3 \left (1+x+e^{e^{25 x^2}} x\right )^3}+\frac {1}{(-1+x)^2 \left (1+x+e^{e^{25 x^2}} x\right )^3}\right ) \, dx-16 \int \left (\frac {e^{e^{25 x^2}+25 x^2}}{\left (1+x+e^{e^{25 x^2}} x\right )^3}+\frac {e^{e^{25 x^2}+25 x^2}}{(-1+x)^2 \left (1+x+e^{e^{25 x^2}} x\right )^3}+\frac {2 e^{e^{25 x^2}+25 x^2}}{(-1+x) \left (1+x+e^{e^{25 x^2}} x\right )^3}\right ) \, dx \\ & = -\left (\frac {8}{25} \int \frac {e^{e^{25 x^2}}}{(-1+x)^3 \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx\right )-\frac {16}{25} \int \frac {1}{(-1+x)^3 \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx-\frac {16}{25} \int \frac {1}{(-1+x)^2 \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx-\frac {16}{25} \int \frac {e^{e^{25 x^2}}}{(-1+x)^2 \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx-16 \int \frac {e^{e^{25 x^2}+25 x^2}}{\left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx-16 \int \frac {e^{e^{25 x^2}+25 x^2}}{(-1+x)^2 \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx-32 \int \frac {e^{e^{25 x^2}+25 x^2}}{(-1+x) \left (1+x+e^{e^{25 x^2}} x\right )^3} \, dx \\ \end{align*}
Time = 0.64 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.93 \[ \int \frac {-16 x+e^{e^{25 x^2}} \left (8-16 x+e^{25 x^2} \left (400 x^2-400 x^3\right )\right )}{-25+75 x^2-75 x^4+25 x^6+e^{3 e^{25 x^2}} \left (-25 x^3+75 x^4-75 x^5+25 x^6\right )+e^{2 e^{25 x^2}} \left (-75 x^2+150 x^3-150 x^5+75 x^6\right )+e^{e^{25 x^2}} \left (-75 x+75 x^2+150 x^3-150 x^4-75 x^5+75 x^6\right )} \, dx=\frac {4}{25 (-1+x)^2 \left (1+x+e^{e^{25 x^2}} x\right )^2} \]
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Time = 1.77 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.00
method | result | size |
risch | \(\frac {4}{25 \left (x^{2}-2 x +1\right ) \left (x +1+x \,{\mathrm e}^{{\mathrm e}^{25 x^{2}}}\right )^{2}}\) | \(27\) |
parallelrisch | \(\frac {4}{25 \left ({\mathrm e}^{2 \,{\mathrm e}^{25 x^{2}}} x^{4}+2 \,{\mathrm e}^{{\mathrm e}^{25 x^{2}}} x^{4}-2 \,{\mathrm e}^{2 \,{\mathrm e}^{25 x^{2}}} x^{3}+x^{4}-2 \,{\mathrm e}^{{\mathrm e}^{25 x^{2}}} x^{3}+{\mathrm e}^{2 \,{\mathrm e}^{25 x^{2}}} x^{2}-2 \,{\mathrm e}^{{\mathrm e}^{25 x^{2}}} x^{2}-2 x^{2}+2 x \,{\mathrm e}^{{\mathrm e}^{25 x^{2}}}+1\right )}\) | \(101\) |
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Leaf count of result is larger than twice the leaf count of optimal. 60 vs. \(2 (21) = 42\).
Time = 0.25 (sec) , antiderivative size = 60, normalized size of antiderivative = 2.22 \[ \int \frac {-16 x+e^{e^{25 x^2}} \left (8-16 x+e^{25 x^2} \left (400 x^2-400 x^3\right )\right )}{-25+75 x^2-75 x^4+25 x^6+e^{3 e^{25 x^2}} \left (-25 x^3+75 x^4-75 x^5+25 x^6\right )+e^{2 e^{25 x^2}} \left (-75 x^2+150 x^3-150 x^5+75 x^6\right )+e^{e^{25 x^2}} \left (-75 x+75 x^2+150 x^3-150 x^4-75 x^5+75 x^6\right )} \, dx=\frac {4}{25 \, {\left (x^{4} - 2 \, x^{2} + {\left (x^{4} - 2 \, x^{3} + x^{2}\right )} e^{\left (2 \, e^{\left (25 \, x^{2}\right )}\right )} + 2 \, {\left (x^{4} - x^{3} - x^{2} + x\right )} e^{\left (e^{\left (25 \, x^{2}\right )}\right )} + 1\right )}} \]
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Time = 0.16 (sec) , antiderivative size = 65, normalized size of antiderivative = 2.41 \[ \int \frac {-16 x+e^{e^{25 x^2}} \left (8-16 x+e^{25 x^2} \left (400 x^2-400 x^3\right )\right )}{-25+75 x^2-75 x^4+25 x^6+e^{3 e^{25 x^2}} \left (-25 x^3+75 x^4-75 x^5+25 x^6\right )+e^{2 e^{25 x^2}} \left (-75 x^2+150 x^3-150 x^5+75 x^6\right )+e^{e^{25 x^2}} \left (-75 x+75 x^2+150 x^3-150 x^4-75 x^5+75 x^6\right )} \, dx=\frac {4}{25 x^{4} - 50 x^{2} + \left (25 x^{4} - 50 x^{3} + 25 x^{2}\right ) e^{2 e^{25 x^{2}}} + \left (50 x^{4} - 50 x^{3} - 50 x^{2} + 50 x\right ) e^{e^{25 x^{2}}} + 25} \]
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Leaf count of result is larger than twice the leaf count of optimal. 60 vs. \(2 (21) = 42\).
Time = 0.26 (sec) , antiderivative size = 60, normalized size of antiderivative = 2.22 \[ \int \frac {-16 x+e^{e^{25 x^2}} \left (8-16 x+e^{25 x^2} \left (400 x^2-400 x^3\right )\right )}{-25+75 x^2-75 x^4+25 x^6+e^{3 e^{25 x^2}} \left (-25 x^3+75 x^4-75 x^5+25 x^6\right )+e^{2 e^{25 x^2}} \left (-75 x^2+150 x^3-150 x^5+75 x^6\right )+e^{e^{25 x^2}} \left (-75 x+75 x^2+150 x^3-150 x^4-75 x^5+75 x^6\right )} \, dx=\frac {4}{25 \, {\left (x^{4} - 2 \, x^{2} + {\left (x^{4} - 2 \, x^{3} + x^{2}\right )} e^{\left (2 \, e^{\left (25 \, x^{2}\right )}\right )} + 2 \, {\left (x^{4} - x^{3} - x^{2} + x\right )} e^{\left (e^{\left (25 \, x^{2}\right )}\right )} + 1\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 100 vs. \(2 (21) = 42\).
Time = 0.36 (sec) , antiderivative size = 100, normalized size of antiderivative = 3.70 \[ \int \frac {-16 x+e^{e^{25 x^2}} \left (8-16 x+e^{25 x^2} \left (400 x^2-400 x^3\right )\right )}{-25+75 x^2-75 x^4+25 x^6+e^{3 e^{25 x^2}} \left (-25 x^3+75 x^4-75 x^5+25 x^6\right )+e^{2 e^{25 x^2}} \left (-75 x^2+150 x^3-150 x^5+75 x^6\right )+e^{e^{25 x^2}} \left (-75 x+75 x^2+150 x^3-150 x^4-75 x^5+75 x^6\right )} \, dx=\frac {4}{25 \, {\left (x^{4} e^{\left (2 \, e^{\left (25 \, x^{2}\right )}\right )} + 2 \, x^{4} e^{\left (e^{\left (25 \, x^{2}\right )}\right )} + x^{4} - 2 \, x^{3} e^{\left (2 \, e^{\left (25 \, x^{2}\right )}\right )} - 2 \, x^{3} e^{\left (e^{\left (25 \, x^{2}\right )}\right )} + x^{2} e^{\left (2 \, e^{\left (25 \, x^{2}\right )}\right )} - 2 \, x^{2} e^{\left (e^{\left (25 \, x^{2}\right )}\right )} - 2 \, x^{2} + 2 \, x e^{\left (e^{\left (25 \, x^{2}\right )}\right )} + 1\right )}} \]
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Time = 11.52 (sec) , antiderivative size = 92, normalized size of antiderivative = 3.41 \[ \int \frac {-16 x+e^{e^{25 x^2}} \left (8-16 x+e^{25 x^2} \left (400 x^2-400 x^3\right )\right )}{-25+75 x^2-75 x^4+25 x^6+e^{3 e^{25 x^2}} \left (-25 x^3+75 x^4-75 x^5+25 x^6\right )+e^{2 e^{25 x^2}} \left (-75 x^2+150 x^3-150 x^5+75 x^6\right )+e^{e^{25 x^2}} \left (-75 x+75 x^2+150 x^3-150 x^4-75 x^5+75 x^6\right )} \, dx=\frac {4\,\left (x-50\,x^2\,{\mathrm {e}}^{25\,x^2}+50\,x^4\,{\mathrm {e}}^{25\,x^2}-1\right )}{25\,{\left (x-1\right )}^3\,\left (50\,x^2\,{\mathrm {e}}^{25\,x^2}+50\,x^3\,{\mathrm {e}}^{25\,x^2}+1\right )\,\left ({\left (x+1\right )}^2+x^2\,{\mathrm {e}}^{2\,{\mathrm {e}}^{25\,x^2}}+2\,x\,{\mathrm {e}}^{{\mathrm {e}}^{25\,x^2}}\,\left (x+1\right )\right )} \]
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