Integrand size = 48, antiderivative size = 24 \[ \int \frac {27 e^{10} x^2+e^{-x^2+x \log \left (x^2\right )} \left (4+8 x-8 x^2+4 x \log \left (x^2\right )\right )}{4 e^{10}} \, dx=x \left (e^{-10+x \left (-x+\log \left (x^2\right )\right )}+\frac {9 x^2}{4}\right ) \]
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Leaf count is larger than twice the leaf count of optimal. \(49\) vs. \(2(24)=48\).
Time = 0.04 (sec) , antiderivative size = 49, normalized size of antiderivative = 2.04, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.042, Rules used = {12, 2326} \[ \int \frac {27 e^{10} x^2+e^{-x^2+x \log \left (x^2\right )} \left (4+8 x-8 x^2+4 x \log \left (x^2\right )\right )}{4 e^{10}} \, dx=\frac {9 x^3}{4}+\frac {e^{-x^2-10} \left (x^2\right )^x \left (-2 x^2+x \log \left (x^2\right )+2 x\right )}{\log \left (x^2\right )-2 x+2} \]
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Rule 12
Rule 2326
Rubi steps \begin{align*} \text {integral}& = \frac {\int \left (27 e^{10} x^2+e^{-x^2+x \log \left (x^2\right )} \left (4+8 x-8 x^2+4 x \log \left (x^2\right )\right )\right ) \, dx}{4 e^{10}} \\ & = \frac {9 x^3}{4}+\frac {\int e^{-x^2+x \log \left (x^2\right )} \left (4+8 x-8 x^2+4 x \log \left (x^2\right )\right ) \, dx}{4 e^{10}} \\ & = \frac {9 x^3}{4}+\frac {e^{-10-x^2} \left (x^2\right )^x \left (2 x-2 x^2+x \log \left (x^2\right )\right )}{2-2 x+\log \left (x^2\right )} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.12 \[ \int \frac {27 e^{10} x^2+e^{-x^2+x \log \left (x^2\right )} \left (4+8 x-8 x^2+4 x \log \left (x^2\right )\right )}{4 e^{10}} \, dx=\frac {1}{4} \left (9 x^3+4 e^{-10-x^2} x \left (x^2\right )^x\right ) \]
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Time = 0.24 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92
method | result | size |
risch | \(x \left (x^{2}\right )^{x} {\mathrm e}^{-x^{2}-10}+\frac {9 x^{3}}{4}\) | \(22\) |
parts | \({\mathrm e}^{-10} {\mathrm e}^{x \ln \left (x^{2}\right )-x^{2}} x +\frac {9 x^{3}}{4}\) | \(26\) |
parallelrisch | \(\frac {{\mathrm e}^{-10} \left (9 x^{3} {\mathrm e}^{10}+4 \,{\mathrm e}^{x \left (\ln \left (x^{2}\right )-x \right )} x \right )}{4}\) | \(31\) |
default | \(\frac {{\mathrm e}^{-10} \left (4 \,{\mathrm e}^{x \ln \left (x^{2}\right )-x^{2}} x +9 x^{3} {\mathrm e}^{10}\right )}{4}\) | \(33\) |
norman | \(\left (x \,{\mathrm e}^{-5} {\mathrm e}^{x \ln \left (x^{2}\right )-x^{2}}+\frac {9 x^{3} {\mathrm e}^{5}}{4}\right ) {\mathrm e}^{-5}\) | \(33\) |
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Time = 0.26 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.17 \[ \int \frac {27 e^{10} x^2+e^{-x^2+x \log \left (x^2\right )} \left (4+8 x-8 x^2+4 x \log \left (x^2\right )\right )}{4 e^{10}} \, dx=\frac {1}{4} \, {\left (9 \, x^{3} e^{10} + 4 \, x e^{\left (-x^{2} + x \log \left (x^{2}\right )\right )}\right )} e^{\left (-10\right )} \]
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Time = 0.12 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92 \[ \int \frac {27 e^{10} x^2+e^{-x^2+x \log \left (x^2\right )} \left (4+8 x-8 x^2+4 x \log \left (x^2\right )\right )}{4 e^{10}} \, dx=\frac {9 x^{3}}{4} + \frac {x e^{- x^{2} + x \log {\left (x^{2} \right )}}}{e^{10}} \]
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Time = 0.24 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.12 \[ \int \frac {27 e^{10} x^2+e^{-x^2+x \log \left (x^2\right )} \left (4+8 x-8 x^2+4 x \log \left (x^2\right )\right )}{4 e^{10}} \, dx=\frac {1}{4} \, {\left (9 \, x^{3} e^{10} + 4 \, x e^{\left (-x^{2} + 2 \, x \log \left (x\right )\right )}\right )} e^{\left (-10\right )} \]
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Time = 0.30 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.17 \[ \int \frac {27 e^{10} x^2+e^{-x^2+x \log \left (x^2\right )} \left (4+8 x-8 x^2+4 x \log \left (x^2\right )\right )}{4 e^{10}} \, dx=\frac {1}{4} \, {\left (9 \, x^{3} e^{10} + 4 \, x e^{\left (-x^{2} + x \log \left (x^{2}\right )\right )}\right )} e^{\left (-10\right )} \]
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Time = 11.45 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.88 \[ \int \frac {27 e^{10} x^2+e^{-x^2+x \log \left (x^2\right )} \left (4+8 x-8 x^2+4 x \log \left (x^2\right )\right )}{4 e^{10}} \, dx=\frac {9\,x^3}{4}+x\,{\mathrm {e}}^{-10}\,{\mathrm {e}}^{-x^2}\,{\left (x^2\right )}^x \]
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