Integrand size = 56, antiderivative size = 19 \[ \int \frac {-3+36 x-12 e^{x^2} x-6 x^2}{e^{3 x^2}+e^{2 x^2} (-12+2 x)+e^{x^2} \left (36-12 x+x^2\right )} \, dx=\frac {3 e^{-x^2}}{-6+e^{x^2}+x} \]
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\[ \int \frac {-3+36 x-12 e^{x^2} x-6 x^2}{e^{3 x^2}+e^{2 x^2} (-12+2 x)+e^{x^2} \left (36-12 x+x^2\right )} \, dx=\int \frac {-3+36 x-12 e^{x^2} x-6 x^2}{e^{3 x^2}+e^{2 x^2} (-12+2 x)+e^{x^2} \left (36-12 x+x^2\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {3 e^{-x^2} \left (-1-4 \left (-3+e^{x^2}\right ) x-2 x^2\right )}{\left (6-e^{x^2}-x\right )^2} \, dx \\ & = 3 \int \frac {e^{-x^2} \left (-1-4 \left (-3+e^{x^2}\right ) x-2 x^2\right )}{\left (6-e^{x^2}-x\right )^2} \, dx \\ & = 3 \int \left (-\frac {4 e^{-x^2} x}{-6+e^{x^2}+x}+\frac {e^{-x^2} \left (-1-12 x+2 x^2\right )}{\left (-6+e^{x^2}+x\right )^2}\right ) \, dx \\ & = 3 \int \frac {e^{-x^2} \left (-1-12 x+2 x^2\right )}{\left (-6+e^{x^2}+x\right )^2} \, dx-12 \int \frac {e^{-x^2} x}{-6+e^{x^2}+x} \, dx \\ & = 3 \int \left (-\frac {e^{-x^2}}{\left (-6+e^{x^2}+x\right )^2}-\frac {12 e^{-x^2} x}{\left (-6+e^{x^2}+x\right )^2}+\frac {2 e^{-x^2} x^2}{\left (-6+e^{x^2}+x\right )^2}\right ) \, dx-12 \int \frac {e^{-x^2} x}{-6+e^{x^2}+x} \, dx \\ & = -\left (3 \int \frac {e^{-x^2}}{\left (-6+e^{x^2}+x\right )^2} \, dx\right )+6 \int \frac {e^{-x^2} x^2}{\left (-6+e^{x^2}+x\right )^2} \, dx-12 \int \frac {e^{-x^2} x}{-6+e^{x^2}+x} \, dx-36 \int \frac {e^{-x^2} x}{\left (-6+e^{x^2}+x\right )^2} \, dx \\ \end{align*}
Time = 0.84 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \[ \int \frac {-3+36 x-12 e^{x^2} x-6 x^2}{e^{3 x^2}+e^{2 x^2} (-12+2 x)+e^{x^2} \left (36-12 x+x^2\right )} \, dx=\frac {3 e^{-x^2}}{-6+e^{x^2}+x} \]
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Time = 0.06 (sec) , antiderivative size = 18, normalized size of antiderivative = 0.95
method | result | size |
norman | \(\frac {3 \,{\mathrm e}^{-x^{2}}}{{\mathrm e}^{x^{2}}+x -6}\) | \(18\) |
parallelrisch | \(\frac {3 \,{\mathrm e}^{-x^{2}}}{{\mathrm e}^{x^{2}}+x -6}\) | \(18\) |
risch | \(\frac {3 \,{\mathrm e}^{-x^{2}}}{-6+x}-\frac {3}{\left (-6+x \right ) \left ({\mathrm e}^{x^{2}}+x -6\right )}\) | \(31\) |
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Time = 0.25 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \[ \int \frac {-3+36 x-12 e^{x^2} x-6 x^2}{e^{3 x^2}+e^{2 x^2} (-12+2 x)+e^{x^2} \left (36-12 x+x^2\right )} \, dx=\frac {3}{{\left (x - 6\right )} e^{\left (x^{2}\right )} + e^{\left (2 \, x^{2}\right )}} \]
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Time = 0.08 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.42 \[ \int \frac {-3+36 x-12 e^{x^2} x-6 x^2}{e^{3 x^2}+e^{2 x^2} (-12+2 x)+e^{x^2} \left (36-12 x+x^2\right )} \, dx=- \frac {3}{x^{2} - 12 x + \left (x - 6\right ) e^{x^{2}} + 36} + \frac {3 e^{- x^{2}}}{x - 6} \]
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\[ \int \frac {-3+36 x-12 e^{x^2} x-6 x^2}{e^{3 x^2}+e^{2 x^2} (-12+2 x)+e^{x^2} \left (36-12 x+x^2\right )} \, dx=\int { -\frac {3 \, {\left (2 \, x^{2} + 4 \, x e^{\left (x^{2}\right )} - 12 \, x + 1\right )}}{2 \, {\left (x - 6\right )} e^{\left (2 \, x^{2}\right )} + {\left (x^{2} - 12 \, x + 36\right )} e^{\left (x^{2}\right )} + e^{\left (3 \, x^{2}\right )}} \,d x } \]
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Time = 0.27 (sec) , antiderivative size = 23, normalized size of antiderivative = 1.21 \[ \int \frac {-3+36 x-12 e^{x^2} x-6 x^2}{e^{3 x^2}+e^{2 x^2} (-12+2 x)+e^{x^2} \left (36-12 x+x^2\right )} \, dx=\frac {3}{x e^{\left (x^{2}\right )} + e^{\left (2 \, x^{2}\right )} - 6 \, e^{\left (x^{2}\right )}} \]
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Time = 0.20 (sec) , antiderivative size = 19, normalized size of antiderivative = 1.00 \[ \int \frac {-3+36 x-12 e^{x^2} x-6 x^2}{e^{3 x^2}+e^{2 x^2} (-12+2 x)+e^{x^2} \left (36-12 x+x^2\right )} \, dx=\frac {3}{{\mathrm {e}}^{2\,x^2}+{\mathrm {e}}^{x^2}\,\left (x-6\right )} \]
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